How i calculate 2ton window ac gas filling in kg

gas input is 20 grams / hour
a full 4.5 kg bottle has 4500 grams of gas so calculations indicate that it should last for 225 hours or to be safe at least 200 hours or 8 days if it is on a caravan , a better proposition would be a 9 kg bottle

• 1.8 kg is 1.8 liters

About 62.1 kg.

"15:3" is a ratio, "kg" is a measure of mass (or weight). Your question is like asking how to convert one-half to pounds.

Quadricool TM

Machines are used to pack sugar into packets supposedly containing 1.20 kg each. On testing a large number of packets over a long period of time, it was found that the mean weight of the packets was 1.24 kg and the standard deviation was 0.04 Kg. A particular machine is selected to check the total weight of each of the 25 packets filled consecutively by the machine. Calculate the limits within which the weight of the packets should lie assuming that the machine is not been classified as faulty.

okay you carda was 4.5 kg bottle cannnot find what you have put on , at there site , so take it is the same bottle ? gas bottles will only fill so far ,you weigh the bottle say 10kg when empity you set the scales to 20 kg them fill the bottle when scale tips itis full , if you overfill a pressure relief kicks in letting out the over pressure so you can not over fill.. now freezing you could well have aleak on the lines or the reg is not working sticking open too much gas passing causing it to freeze up, this the best if can think of .

In scientific problems the powers of 10 are the easiest thing to handle if you keep in mind two or three rules.

1. 1/10^(a) = 10^(-a)
2. (10^a)*(10^b) = 10^(a+b)
3. (10^a)/(10^b) = 10^(a-b)
4. (10^a)^b=10^(a*b)

Example : suppose you want to calculate the charge to mass ratio of the electon
m_e= 9.109534 E-31 kg
q_e=1.6021892 E-19 C

q_e/m_e= (1.6021892/9.109534)* (E-19)*(E 31) C/kg
q_e/m_e= (1.6021892/9.109534)* (E 31-19) C/kg
q_e/m_e= (1.758804786 E-1)* (E 12) C/kg
q_e/m_e= 1.7588048 E 11 C/kg

If you just use your calculator to operate on the mantissas (multiplications and divisions) and handle the powers of 10 by hand, you will make fewer errors, especially if you are not confident in your mastery of the calculator as regards exponents.

Anyway, if you could give us a sample of the divisions you are performing, we might be able to help you. Post a comment to this thread and we will take it from there.

1Kg = 2.205lbs