Question about Parsons QuickVerse 7 Essentials (fe11044) for PC

Tan x=70/200 => angle of elevation,x is ....

tan y=30/200 => angle of depression, y, is...

Posted on Sep 04, 2008

- FROM A WINDOW 30 feet above the ground,a building 100 feet high, and at a distance of 200 feet, is observed.find the angle of elevation of the top of the building and the angle of depression of its base.

Posted on Aug 01, 2008

Prove root 5 is irrational

Posted on Jul 14, 2008

The flagpole is twenty (20) feet tall.

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If this is homework, be sure to show your work.

Feb 26, 2015 | CyberEd Trigonometry Problem Solver

Assuming the dam face is vertical, 3017 feet.

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Jul 12, 2014 | Super Tutor Trigonometry (ESDTRIG) for PC

About 61.665 meters.

Feb 12, 2014 | Educational & Reference Software

e.

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Sep 25, 2013 | Educational & Reference Software

About 1930 feet.

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If this is homework, make sure to show your work.

Sep 24, 2013 | Educational & Reference Software

If the distance of a person from a tower is 100 m and the angle subtended by the top of the tower with the ground is 30o, what is the height of the tower in meters?
Solution:

*h* / 100
Therefore height of the tower *h* = 100 tan 30o = (100) 1/√3 = 57.74 m.

- AB = distance of the man from the tower = 100 m
- BC = height of the tower =
*h*(to be calculated) - The trigonometric function that uses AB and BC is tan
*A*, where A = 30o.

Jan 09, 2010 | Mathsoft StudyWorks! Mathematics Deluxe...

a2+b2=c2

a being your height, b is your distance from the airport and c is the distance from the airport to the plane........ so the answer is 5.385164807134504 miles

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a being your height, b is your distance from the airport and c is the distance from the airport to the plane........ so the answer is 5.385164807134504 miles

Pls Rate this post

Oct 08, 2009 | SoftMath Algebrator - Algebra Homework...

Depends ur height and building's height

Feb 12, 2009 | Super Tutor Trigonometry (ESDTRIG) for PC

ð XAC = ð ACB (Angle of elevation= Angle of depression)

AB = 5 Yards

BC = ?

Now Tan C= AB/BC

BC = AB/ Tan C

BC = 5 / Tan 28 Yards

BC = 5/.531709 Yards

BC = 9.403632 Yards

AB = 5 Yards

BC = ?

Now Tan C= AB/BC

BC = AB/ Tan C

BC = 5 / Tan 28 Yards

BC = 5/.531709 Yards

BC = 9.403632 Yards

Jan 02, 2009 | Super Tutor Trigonometry (ESDTRIG) for PC

Sep 08, 2011 | Parsons QuickVerse 7 Essentials (fe11044)...

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