Question about Parsons QuickVerse 7 Essentials (fe11044) for PC

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TRIANGLES FROM A WINDOW 30 feet above the ground,a building 100 feet high, and at a distance of 200 feet, is observed.find the angle of elevation of the top of the building and the angle of depression of its base.

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Tan x=70/200 => angle of elevation,x is ....

tan y=30/200 => angle of depression, y, is...

Posted on Sep 04, 2008

  • FROM A WINDOW 30 feet above the ground,a building 100 feet high, and at a distance of 200 feet, is observed.find the angle of elevation of the top of the building and the angle of depression of its base.

Posted on Aug 01, 2008

Prove root 5 is irrational

Posted on Jul 14, 2008

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Trigonometric word problem with solution


If the distance of a person from a tower is 100 m and the angle subtended by the top of the tower with the ground is 30o, what is the height of the tower in meters? Solution:
tower.gif
  • AB = distance of the man from the tower = 100 m

  • BC = height of the tower = h (to be calculated)

  • The trigonometric function that uses AB and BC is tan A , where A = 30o.
So tan 30o = BC / AB = h / 100 Therefore height of the tower h = 100 tan 30o = (100) 1/√3 = 57.74 m.

Jan 09, 2010 | Mathsoft StudyWorks! Mathematics Deluxe...

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An airplane is flying at a height of 2 miles above the ground. The distance along the ground from the airplane to the airport is 5 miles. What is the angle of depression from the airplane to the airport?


a2+b2=c2
a being your height, b is your distance from the airport and c is the distance from the airport to the plane........ so the answer is 5.385164807134504 miles

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Oct 08, 2009 | SoftMath Algebrator - Algebra Homework...

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Angle of depression


9cd8f44.jpg ð XAC = ð ACB (Angle of elevation= Angle of depression)
AB = 5 Yards
BC = ?
Now Tan C= AB/BC
BC = AB/ Tan C
BC = 5 / Tan 28 Yards
BC = 5/.531709 Yards
BC = 9.403632 Yards

Jan 02, 2009 | Super Tutor Trigonometry (ESDTRIG) for PC

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