Question about Computers & Internet

# I want ans..... of que? ques is what is the atomicity of glucose molecule

Posted by on

Ad

## 1 Answer

• Level 2:

An expert who has achieved level 2 by getting 100 points

Hot-Shot:

An expert who has answered 20 questions.

Corporal:

An expert that hasĀ over 10 points.

Mayor:

An expert whose answer gotĀ voted for 2 times.

• Expert
• 69 Answers

Molar mass of C6H12O6 = 180.15588 g/mol

Posted on Jan 04, 2011

Ad

## 1 Suggested Answer

• 2 Answers

Hi,
a 6ya expert can help you resolve that issue over the phone in a minute or two.
Best thing about this new service is that you are never placed on hold and get to talk to real repairmen in the US.
the service is completely free and covers almost anything you can think of.(from cars to computers, handyman, and even drones)
click here to download the app (for users in the US for now) and get all the help you need.
Goodluck!

Posted on Jan 02, 2017

Ad

## Add Your Answer

×

Uploading: 0%

my-video-file.mp4

Complete. Click "Add" to insert your video.

×

Loading...

## Related Questions:

1 Answer

### What does it mean if there isn't a subscript number in a chemical formula?

It means just one atom of an element is present in the molecule, or that just one group of several different atoms is present.
.

Jan 13, 2017 | Computers & Internet

1 Answer

### How many atoms of hyrdrogen gas in tow moles how

Hydrogen gas is a diatomic substance: Each molecule contains two hydrogen atoms.
A mole of hydrogen gas contains 6.02*10^23 hydrogen molecules, but since each molecule contains 2 hydrogen atom you have 2*6.02*10^23=?
The formula for nitric acid is HNO_3. It contains 5 atoms regardless of the elements
Now, 0.25 moles contain 0.25* 6.02*10^23 molecules oh nitric acid, ans since each molecule contains 5 atoms then 0.25 moles contain 0.25*5*6.02*10^23=? atoms
0.25*1*6.02*10^23 of hydrogen atoms, and the same number of nitrogen atoms and 0.25*3*6.02*10^23 oxygen atoms.

Oct 01, 2013 | Cars & Trucks

1 Answer

### How many grams of aluminum acetate contain 2.24 x 1022 atoms of hydrogen?

1 Look up the formula for the aluminum acetate.
2 Count the number of Hydrogen atoms per molecule: Call that nH.
3 Dividing 2.24*10^22 by nH you get the number of molecules of acetate.
4. Divide that number by Avogadro's Number to obtain the number of moles required.
5. Multiply the number of moles by the molecular mass of the aluminum acetate (look it up or use the periodic table to calculate it), you will get the mass of aluminum acetate that contains 2.24*10^22 hydrogen atoms.

Sep 14, 2011 | Texas Instruments TI-84 Plus Calculator

1 Answer

### Ionization

Please restate as a question. Do you mean "what is ionisation?" If so: ionisation is the physical process of converting a molecule or atom into an ion by adding or removing charged particles such as electrons or other ions, to form a charged form of the atom or molecule.

Feb 19, 2011 | Scientific Explorer My First Chemistry Kit

1 Answer

### I need to take bake my facebook account end pasword pls!!!!tnx

no se que es lo que pasa intento comprar FV en Farmville pero me dice que todo esta bloqueado kiero que me expliquen que paso por que yo no era el que estaba usando mi facebook era mi ermano y no se que fue lo que iso con mi facebook. please

Nov 25, 2010 | Facebook Social Network

1 Answer

### How do I calculate this question with the fx-115es. Find the number of moles of nitrogen in 1.75 mol N2H4?

You have 1.75 moles of hydrazine or 1.75xNa molecules of the substance. Since each molecule of N2H4 contains 2 atoms of nitrogen 1.75Na molecules contain 2x1.75xNa atoms of nitrogen. The number of moles of nitrogen is 2x1.75xNa/Na, which leaves 2x1.75 or 3.5 moles.
Your answer: 1.75 mol of hydrazine contain 3.5 mol of nitrogen atoms.

Sep 23, 2010 | Casio FX-115ES Scientific Calculator

## Open Questions:

#### Related Topics:

77 people viewed this question

## Ask a Question

Usually answered in minutes!

Level 3 Expert

7733 Answers

Level 3 Expert

102366 Answers

Level 3 Expert

14161 Answers

Loading...