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Did you check with the manufacturer on their web site? If not available it is because the set was a special model for a large store - they change the model numbers on those sets so they cannot be shopped. You need to find the equivalent JVC model which asise from a different model number is identical.

They do NOT make special models for these big retailers - just give them a special number.

They do NOT make special models for these big retailers - just give them a special number.

Feb 22, 2016 | JVC Televison & Video

Add a graph .

In Documents Toolbox, select 3: Graph/Entry Edit

Unfold the menu and select Equation (not function). Enter your equation.

For the 3D part, I am afraid you will have to read the manual.

In Documents Toolbox, select 3: Graph/Entry Edit

Unfold the menu and select Equation (not function). Enter your equation.

For the 3D part, I am afraid you will have to read the manual.

Jan 22, 2016 | Texas Instruments TI-Nspire CX CAS...

In algebra there are some identities (that are true all the time(.

(a+b)^2 is always equal to a^2+2ab+b^2, regardless of the values of a and b.

Another one (a-b)^2=a^2-2ab+b^2

a^2-b^2=(a-b)(a+b)

There is also the binomial identity (a+b)^n. Look this one up.

(a+b)^2 is always equal to a^2+2ab+b^2, regardless of the values of a and b.

Another one (a-b)^2=a^2-2ab+b^2

a^2-b^2=(a-b)(a+b)

There is also the binomial identity (a+b)^n. Look this one up.

Jun 08, 2014 | Computers & Internet

In algebra there are some identities (that are true all the time(.

(a+b)^2 is always equal to a^2+2ab+b^2, regardless of the values of a and b. Another one (**a-b)^2=a^2-2ab+b^2**, and **a^2-b^2=(a-b)(a+b)**

There is also the binomial identity (a+b)^n. Look this one up.

(a+b)^2 is always equal to a^2+2ab+b^2, regardless of the values of a and b. Another one (

There is also the binomial identity (a+b)^n. Look this one up.

Jun 07, 2014 | Computers & Internet

In algebra there are some identities (that are true all the time)

**(a+b)^2 is always equal to a^2+2ab+b^2**, regardless of the values of a and b. Another one **(a-b)^2=a^2-2ab+b^2**, and

**a^2-b^2=(a-b)(a+b)**

There is also the binomial identity**(a+b)^n.** Look this one up.

There is also the binomial identity

Jun 05, 2014 | Computers & Internet

tan(x/2)=sin(x)/(1+cos(x))

Setting x/2=45, means that x=90 (degrees)

But cos(90)=0 and sin(90)=1. Thus tan(45)=1/(1+0)=1.

Setting x/2=45, means that x=90 (degrees)

But cos(90)=0 and sin(90)=1. Thus tan(45)=1/(1+0)=1.

Mar 13, 2013 | SoftMath Algebrator - Algebra Homework...

Just complete the square

x^2-22x-10=x^2-2(x)*11+11^2-11^2-10=(x-11)^2-121-10=(x-11)^2- 131.

Use the identity a^2-b^2=(a-b)(a+b) with a=(x-11) and b= square root (131)

Solutions are**x1= 11 + square root (131) **and **x2=11-square root (131)**.

By the way, the calculator you are refer to cannot perform symbolic algebra calculations.

x^2-22x-10=x^2-2(x)*11+11^2-11^2-10=(x-11)^2-121-10=(x-11)^2- 131.

Use the identity a^2-b^2=(a-b)(a+b) with a=(x-11) and b= square root (131)

Solutions are

By the way, the calculator you are refer to cannot perform symbolic algebra calculations.

Nov 30, 2011 | Casio FX-115ES Scientific Calculator

I do not own that calculator so I checked the manual. In the chapter Manual calculations it explains the use of matrices but not a single reference to eigenvalues or eigenvectors. I looked also in the advanced functions chapter but nothing on eigenvalues. I believe you will have to use the general algebraic methods for calculating eigenvalues: characteristic polynomial and its solutions. Set up the equation det (Mat A -lambda Mat I)=0 where A is your original matrix and I is the Identity matrix with same dimensions as A. The determinant will give you a polynomial equation in the eigenvalue lambda. the degree of the polynomial will be equal to the dimension of the matrix. You might want to feed the equation to the polynomial solver to find some eigenvalues.

Jun 30, 2011 | Casio Algebra FX 2.0 Calculator

Not with that calculator. You can use Wolfram Alpha to solve most equations very quickly: http://www.wolframalpha.com/input/?i=x^2+-+3x+-+4+%3D+0

You can even use it to solve systems of equations: http://www.wolframalpha.com/input/?i=2x+%2B+3y+%3D+5%2C+4x+-+3y+%3D+1

Enjoy.

You can even use it to solve systems of equations: http://www.wolframalpha.com/input/?i=2x+%2B+3y+%3D+5%2C+4x+-+3y+%3D+1

Enjoy.

Mar 03, 2011 | Texas Instruments TI30X IIB Scientific...

Use the fact that cos(pi/4)=sin(pi/4)= 1/square root(2). Trigonometric identity cos(a+b)=cos(a)cos(b)-sin(a)sin(b).

Nov 07, 2010 | SoftMath Algebrator - Algebra Homework...

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