Question about Computers & Internet

At 95% confidence level the limits are 57.47 -1.96*1.3 and 57.47+1.96*1.3. so there is no reason to reject the hypothesis

Posted on Dec 30, 2014

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Posted on Jan 02, 2017

First you need the Std Error of the mean value, a measure of the dispersion of that mean value.

SE = sample std deviation / sqrt (sample size)

= 100 / sqrt (64)

= 100 / 8

= 12.5

Then we use a figure for the number of std errors either side of the mean value, which make up a 95 % confidence interval. This is ± 1.96 std errors, from tables of the Normal Distribution.

So the confidence interval is

350 ± 1.96 * 12.5 or

374.5 to 325.5

.

SE = sample std deviation / sqrt (sample size)

= 100 / sqrt (64)

= 100 / 8

= 12.5

Then we use a figure for the number of std errors either side of the mean value, which make up a 95 % confidence interval. This is ± 1.96 std errors, from tables of the Normal Distribution.

So the confidence interval is

350 ± 1.96 * 12.5 or

374.5 to 325.5

.

Dec 11, 2015 | Institute of Mathematics and Statistics...

u have get form ur nearest electronic ( electrical ) store

take the sample of it they will give u the same of sample of pice

take the sample of it they will give u the same of sample of pice

Mar 30, 2008 | Lands Phones

First you need the Std Error of the mean value, a measure of the dispersion of that mean value.

SE = sample std deviation / sqrt (sample size)

= 8 / ? 64

= 1

Then we use a figure for the number of std errors either side of the mean value, which make up a 99 % confidence interval. This is ± 2.58 std errors, from tables of the Normal Distribution.

So the confidence interval is

125 ± 2.58 * 1 or

127.58 to 122.42

.

SE = sample std deviation / sqrt (sample size)

= 8 / ? 64

= 1

Then we use a figure for the number of std errors either side of the mean value, which make up a 99 % confidence interval. This is ± 2.58 std errors, from tables of the Normal Distribution.

So the confidence interval is

125 ± 2.58 * 1 or

127.58 to 122.42

.

Dec 10, 2015 | Institute of Mathematics and Statistics...

Oh geeze,, you have 480 ladybugs in all?!!!

That makes a total combined population of 1,680 critters!

And why did you only take a 1.25% sample?!!

But maybe ladybugs like living in dirt piles better than other backyard areas, so you might not have that many! ;)

That makes a total combined population of 1,680 critters!

And why did you only take a 1.25% sample?!!

But maybe ladybugs like living in dirt piles better than other backyard areas, so you might not have that many! ;)

Nov 07, 2014 | Office Equipment & Supplies

About 5.23. If this is homework, be sure to show your work.

Jun 25, 2014 | Office Equipment & Supplies

No. At the 0.05 level you cannot conclude that this sample is significantly different.

Apr 06, 2014 | Institute of Mathematics and Statistics...

Population size:4

Mean (?): 23.45

Standard deviation (?): 4.5986411036305

Mean (?): 23.45

Standard deviation (?): 4.5986411036305

Mar 07, 2014 | Office Equipment & Supplies

About 29%.

If this is homework, make sure to show your work.

If this is homework, make sure to show your work.

Oct 16, 2013 | Office Equipment & Supplies

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