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How to solve 2.93+19j=-j-5.82-11.25

A long, fairly thorough way that shows the thinking behind it (usually considerably shorthanded in practice):
1) Rewrite the (negative-signed) elements of the equation so that their signs are clearly attached to them and cannot be confused with operations [you could also add the + in front of the positive-signed elements as well] -->
2.93 + 19j = -j + -5.82 + -11.25
2) Add j to both sides to consolidate all the j's on the same side of the equation [adding the same thing to both sides doesn't change the balance/value of the equation] --> 2.93 + 19j +j = +j +-j + -5.82 + -11.25 --> 2.93 + 20j = -5.82 + -11.25
3) Subtract 2.93 from both sides so that the j's are all by themselves on one side of the equation --> 2.93 + -2.93 + 20j = -5.82 + -11.25 + -2.93 --> 20j = -5.82 + -11.25 + -2.93
4) Add up the numbers on the right and rewrite the equation --> 20j = -20
5) Solve for j by dividing both sides by 20 [j's coefficient] --> j = -1
6) Test the answer in the left side of the equation --> 2.93 + 19(-1) --> 2.93 + -19 --> -16.07
7) Test the answer in the right side of the equation --> -(-1) + -5.82 + -11.25 --> 1 + -5.82 + -11.25 --> -16.07
8) Compare and validate: -16.07 = -16.07

Nov 21, 2017 | Math

1 Answer

Whats the answer to y=(x+2)^2 using a new equation in vertical form a transfer right 4 unit up 2 unit and reflect on x axis

Let's start with the original equation. It is in the form y=a(x-h)^2+k, where (h,k) is the vertex. In this case, h= - 2 and k= 0. Thus, is it y=x^2 and we have done a horizontal translation 2 units to the left. I assume we are going to translate this 4 units to the right, then 2 units up, and then reflect it in the x-axis. Before we do the reflection, we will be 2 units to the right and 2 units up. This equation would be y=(x-2)^2+2. If we reflect this in the x-axis, would we get a downward facing parabola y=-(x-2)^2 -2?

Good luck,


Dec 06, 2015 | Office Equipment & Supplies

1 Answer

Determine the x and y intercept of the graph for each equation. 5x-y=-5 And -3x+2y=7

5x-y=-5 answer x=-1, y= 5

-3x+2y=7 answer x = -7/3, y = 7/2

Feb 23, 2015 | Office Equipment & Supplies

1 Answer

Variable equation

3 times integer(x/20)
where integer(x) is the integer portion of x, discarding any fractional portion.

May 05, 2013 | Office Equipment & Supplies

1 Answer

How do I solve for y, 2y + (y-3)=18 - 2 (y+3). with the casio fx-300es? and if I cant whats the calculator that will. thanx

Do you really need a calculator to solve a linear equation?
Let us see how to solve it without a calculator.
Remove the parentheses fronm the second term on the left : y-3
Use the distributive property on the last term on the right side -2y-6
Take the term -3 to the right side, changing its sign in the process (becomes +3)
Take the -2y term to the left making it +2y.
3y +2y=18+3-6 or 5y=15 and the answer is straightforward .

As to your Casio FX300ES, it cannot solve equations because it does not have an EQUATION calculation mode. The Casios FX-115ES and FX-991ES have an Equation Mode. If you use any of the two to solve an equation in one variable (linear, quadratic or other) the unknown is taken to be x by default. You would have to change the name of the variable from y to x.

Sep 08, 2011 | Casio fx-300ES Calculator

1 Answer

How to solve the equation and you check like this one x+9=15


You just transfer the number to the other side of the equation, BUT it will become negative. So:

x + 9 = 15 becomes x = 15 - 9

Which becomes x = 6

To check it, replace the x by your answer, which is 6

6 + 9 = 15 is correct, so it means you got the right answer.

Thanks for using Fixya!

Jun 23, 2011 | CyberEd Algebra Equation Solver

1 Answer


First thing to do, before you enter the value of the equation to your calculator multiply the first term((1/3x+5) from the second term(1/3x+5) to make your answer simplified.Then after that you will observed that your answer look like in this pattern AX2 +BX+C it means that the equation is in general form of quadratic equation. So, in your problem,we are looking for a value of X1 and X2,when you used your calculator in solving this problem, First On you calculator then look for the mode then press it after that look for the equation(EQN).Then from the side of the word EQN there is a corresponding number to press,from my calculator it is number 5..Then press it.After you press it, there is a equations choices,look for the equation AX2 +BX+C then press it(given number to press). Now,enter the value of A, B and C from your simplified answer. After pressing the value of A press = sign from your calculator same as B and C.After you enter all the value of A,B and C continuously press = sign from your calculator till you get the answer, the value of X1 and X2.

Jun 14, 2011 | Texas Instruments TI-30 XIIS Calculator

1 Answer

Pls.give the equation of this problem:supposed i am giving an oral examination each correct answer is worth two points each incorrect responses is woth -1 point and no response is worth 0 points.If you...

Total Questions = 50
Answered = 25
Wrong = 8
No Response = 17

Equation: x^2-8y+0

Suppose X = 5 --------> 5^2 = 25
Suppose Y = -1 --------> 8(-1) = -8

So your equation will be x^2 + 8y + 0

Contact me back for further information.

Best of Luck

Mar 03, 2011 | Compaq (153515-001) Touch Pad

1 Answer

Wrong answer produced in sin / cos problems?

5sin(x)+1 = 0 is the equation you want to solve?
5sin(x) = -1
sin(x) = -(1/5)
arcsin( sin(x) ) = arcsin( -(1/5) )
x = -.201 (radians)
x = -11.5369 (degrees)

Jun 04, 2010 | Texas Instruments TI-84 Plus Calculator

2 Answers

How to use ti 89 with a problem like "-(3x+1)-(4x-7)=4-(3x+2)'

Just plug in one side of the equation and find the answer. Then plug in the other side and compare answers.

Feb 19, 2008 | Texas Instruments TI-89 Calculator

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