A positive number is 5 times another number.If 21 is added to both the numbers,then one of the new numbers becomes twice the other number.What are the numbers

X=7 Therefore, first is 7, second is 35

I like numbers but as I get older, they get harder!

Posted on Dec 02, 2008

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Posted on Jan 02, 2017

Two equations:

x = first number

y = second number

2x - y = -1

y = 1 + 2x

2y + 3x = 9

2(1 + 2x) + 3x = 9

2 + 7x = 9

7x = 7

**x = 1**

**y =** 2(1) + 1 =** 3**

x = first number

y = second number

2x - y = -1

y = 1 + 2x

2y + 3x = 9

2(1 + 2x) + 3x = 9

2 + 7x = 9

7x = 7

Oct 25, 2016 | Cars & Trucks

A great tutorial: https://www.khanacademy.org/math/cc-eighth-grade-math/cc-8th-linear-equations-functions/8th-slope-intercept-form/v/linear-equations-in-slope-intercept-form

Mar 17, 2015 | math.com Computers & Internet

This may not be what you want, but I turn the mixed number into a fraction. Say 5 1/2, you multiply the whole number (5) by the denominator for the fraction (2), then add the numerator. So you have 5X2+1. That is the new numerator, it goes over the denominator. This gives you 11/2. To check it divide the numerator by the denominator. 2 into 11 gives you 5 (Rem) 1. 1 is the numerator now and it goes over the denomerator. 5 1/2.

I know it sounds like a lot, but try about ten or so, it becomes 2nd nature. You can make it all into decimal, 5 1/2 becomes 5.5, but now you have to put more numbers into the equation.

This is true. I had a math teacher ask me if he had to cut down a tree so I'd have enough scratch paper.

I know it sounds like a lot, but try about ten or so, it becomes 2nd nature. You can make it all into decimal, 5 1/2 becomes 5.5, but now you have to put more numbers into the equation.

This is true. I had a math teacher ask me if he had to cut down a tree so I'd have enough scratch paper.

Jan 26, 2015 | Office Equipment & Supplies

Start by using the distributive property to expand the term 5(I-31)=5*I-5*31=5*I-155.

Rewrite the equation as 5*I+5*I-155=55

Combine the terms with I, this yields 10*I-155=55

Add 155 to both sides of the equation 10*I-155+155=55+155

you now get 10*I=210

Divide both sides of the equation by 10

(10*I)/10=210/10

Cancel the 10's on the left and divide 210 by 10 to get 21

Thus I=21

Basically you use the priority order of operations BEDMAS backwards

Rewrite the equation as 5*I+5*I-155=55

Combine the terms with I, this yields 10*I-155=55

Add 155 to both sides of the equation 10*I-155+155=55+155

you now get 10*I=210

Divide both sides of the equation by 10

(10*I)/10=210/10

Cancel the 10's on the left and divide 210 by 10 to get 21

Thus I=21

Basically you use the priority order of operations BEDMAS backwards

Feb 13, 2013 | SoftMath Algebrator - Algebra Homework...

The following are examples of expressions:

2

*x*

3 + 7

2 ×*y* + 5

2 + 6 × (4 - 2)

*z* + 3 × (8 - *z*)

Example:

Roland weighs 70 kilograms, and Mark weighs*k* kilograms. Write an expression
for their combined weight. The combined weight in kilograms of these two people
is the sum of their weights, which is 70 + *k*.

Example:

A car travels down the freeway at 55 kilometers per hour. Write an expression for the distance the car will have traveled after*h* hours. Distance equals rate
times time, so the distance traveled is equal to 55 × *h*..

Example:

There are 2000 liters of water in a swimming pool. Water is filling the pool at the rate of 100 liters per minute. Write an expression for the amount of water, in liters, in the swimming pool after*m* minutes. The amount of water added
to the pool after *m* minutes will be 100 liters per minute times *m*,
or 100 × *m*. Since we started with 2000 liters of water in the pool,
we add this to the amount of water added to the pool to get the expression 100 ×
*m *+ 2000.

To evaluate an expression at some number means we replace a variable in an expression with the number, and simplify the expression.

Example:

Evaluate the expression 4 ×*z* + 12 when *z* = 15.

We replace each occurrence of*z* with the number 15, and simplify using the
usual rules: parentheses first, then exponents, multiplication and division, then
addition and subtraction.

4 ×*z* + 12 becomes

4 × 15 + 12 =

60 + 12 =

72

Example:

Evaluate the expression (1 +*z*) × 2 + 12 ÷ 3 - *z* when
*z* = 4.

We replace each occurrence of z with the number 4, and simplify using the usual rules: parentheses first, then exponents, multiplication and division, then addition and subtraction.

(1 +*z*) × 2 + 12 ÷ 3 - *z* becomes

(1 + 4) × 2 + 12 ÷ 3 - 4 =

5 × 2 + 12 ÷ 3 - 4 =

10 + 4 - 4 =

10.

**hope that help you**

2

3 + 7

2 ×

2 + 6 × (4 - 2)

Example:

Roland weighs 70 kilograms, and Mark weighs

Example:

A car travels down the freeway at 55 kilometers per hour. Write an expression for the distance the car will have traveled after

Example:

There are 2000 liters of water in a swimming pool. Water is filling the pool at the rate of 100 liters per minute. Write an expression for the amount of water, in liters, in the swimming pool after

To evaluate an expression at some number means we replace a variable in an expression with the number, and simplify the expression.

Example:

Evaluate the expression 4 ×

We replace each occurrence of

4 ×

4 × 15 + 12 =

60 + 12 =

72

Example:

Evaluate the expression (1 +

We replace each occurrence of z with the number 4, and simplify using the usual rules: parentheses first, then exponents, multiplication and division, then addition and subtraction.

(1 +

(1 + 4) × 2 + 12 ÷ 3 - 4 =

5 × 2 + 12 ÷ 3 - 4 =

10 + 4 - 4 =

10.

Jun 22, 2011 | LeapFrog Turbo Twist Math Cartridge 5th...

Pay more attention in math class, do your daily homework or tutorials. If you do not understand the chapter or any math problems, just ask the math teacher directly. He or she is the best bet that can help you directly dealing with your situation.

Just don't forget "In any examinations, it is a test of what you don't know".

Just don't forget "In any examinations, it is a test of what you don't know".

Jul 21, 2010 | Software Publishing Sports Math: Decimals...

The best way to solve this is to develop one or more equations and then solve for the unknown numbers.

I solved this problem twice using different sets of equations to make sure I was right, and here is what I found:

1) I used the equations x + y = 623, and x = (2/3)y. In these equations, x is the number of girls and y is the number of boys.

Substituting the second equation into the first, I get (2/3)y + y = 623.

Adding the left side together I get : (5/3)y = 623.

Dividing both sides by (5/3) I get 373.8.

This means that x (the number of girls) is 249.2.

2) For the second attempt, I developed the equation: 2x+3x=623. Here 2x is the number of girls, and 3x is the number of boys.

Adding the left side I get: 5x = 623.

Dividing both sides by 5 I get: x = 124.6.

This means that the number of girls (2x) is 249.2. Just like in the first method.

But since you can't have a 1/5 of a girl, the answer must be 249 girls.

I solved this problem twice using different sets of equations to make sure I was right, and here is what I found:

1) I used the equations x + y = 623, and x = (2/3)y. In these equations, x is the number of girls and y is the number of boys.

Substituting the second equation into the first, I get (2/3)y + y = 623.

Adding the left side together I get : (5/3)y = 623.

Dividing both sides by (5/3) I get 373.8.

This means that x (the number of girls) is 249.2.

2) For the second attempt, I developed the equation: 2x+3x=623. Here 2x is the number of girls, and 3x is the number of boys.

Adding the left side I get: 5x = 623.

Dividing both sides by 5 I get: x = 124.6.

This means that the number of girls (2x) is 249.2. Just like in the first method.

But since you can't have a 1/5 of a girl, the answer must be 249 girls.

Nov 19, 2009 | Office Equipment & Supplies

Hello,

Sorry this calculator cannot solve equations. It does not have the program. It does not know how to do those things. However it can calculate.**Before you can use the calculator you must prepare all yourself. **When you have solved the problem, you ask the calculator to compute the value of what you found.

Let us clean the equation a bit

2(x-4) -5x=-5

Get rid of the parentheses 2(x-4) becomes 2x-2*4=2x-8 .Put that result where it was in equation

2x-8 -5x=-5

Group together the terms that have x in them 2x-5x=-3x

Then

2x-8-5x=-5, becomes -3x-8=-5

You want to isolate the term with x (have it on one side, and the others on the other side) -3x= -5 -(-8)= -5+8 =3.

The equation becomes

-3x=3 Thus**-x=3/3=1 and x=-1.**

**In general you would have obtained x= (some number/some other number) and that is where the calculator would intervene.**

Hope it helps.

Sorry this calculator cannot solve equations. It does not have the program. It does not know how to do those things. However it can calculate.

Let us clean the equation a bit

2(x-4) -5x=-5

Get rid of the parentheses 2(x-4) becomes 2x-2*4=2x-8 .Put that result where it was in equation

2x-8 -5x=-5

Group together the terms that have x in them 2x-5x=-3x

Then

2x-8-5x=-5, becomes -3x-8=-5

You want to isolate the term with x (have it on one side, and the others on the other side) -3x= -5 -(-8)= -5+8 =3.

The equation becomes

-3x=3 Thus

Hope it helps.

Sep 11, 2009 | Texas Instruments TI-30XA Calculator

A positive number is 5 times another number.If 21 is added to both the numbers,then one of the new numbers becomes twice the other number.What are the numbers

Nov 29, 2007 | Computers & Internet

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