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Posted on Jan 02, 2017

We use the symbol ? to mean "is a subset of" and the symbol ? to mean "is not a subset of".

The subsets of D are { },{ a},{ b},{ c},{d },{x },{ y}

{ ab},{ac},{ad },{ax},{ay}

{bc },{bd},{bx},{by}

{cd},{cx},{cy}

{dx},{dy}

{xy}

Hope this solution could help you to solve your problem. Sir/Mam don't forget me to rate me up i really I appreciate what grade you have given to me. Thanks a lot and God Bless.

The subsets of D are { },{ a},{ b},{ c},{d },{x },{ y}

{ ab},{ac},{ad },{ax},{ay}

{bc },{bd},{bx},{by}

{cd},{cx},{cy}

{dx},{dy}

{xy}

Hope this solution could help you to solve your problem. Sir/Mam don't forget me to rate me up i really I appreciate what grade you have given to me. Thanks a lot and God Bless.

Jun 19, 2011 | Computers & Internet

The short story is that this calculator does have a computer algebra system or CAS and thus cannot factor polynomials with arbitrary (unknown) coefficients or known coefficients.

However if the coefficients are given you can ,if you are willing to travel that way, factor approximately a polynomial P(x).

Basically, the idea is that any polynomial P(X) of degree n can be written in the factored form (X-x_1)(X-x_2)...(X-x_n), where x_1, x_2, x_3,...x_n are the roots (real or complex) of the equation P(X)=0.

The procedure ( for a 3rd degree polynomial) is as follows: (the fixYa site parser will remove the plus signs, so I am writing the whole word plus instead of the mathematical sign

If you want to factor a cubic polynomial P3(X) = aX^3 plus bX^2 plus cX plus d , you write the corresponding cubic equation as**aX^3 plus bX^2 plus cX plus d =0** , then you divide all terms of the equation by** a** to obtain

**X^3 plus (b/a)X^2 plus (c/a)X plus (d/a)=0.**

You use the calculator to solve (approximately) this equation.

Suppose you find the 3 roots**X1,X2,and X3.**
Then the polynomial X^3 plus (b/a)X^2 plus (c/a)X plus (d/a) can be cast in the
factored form (X-X1)(X-X2)(X-X3) and the original polynomial P3(X) can
be written as

**P3(X) = a*(X-X1)(X-X2)(X-X3) **

You can handle the quadratic polynomial the same way.

P2(X) =a*(X-X1)(X-X2) where X1, X2 are the two real roots.

To find the various roots you must use the solve( application.

However if the coefficients are given you can ,if you are willing to travel that way, factor approximately a polynomial P(x).

Basically, the idea is that any polynomial P(X) of degree n can be written in the factored form (X-x_1)(X-x_2)...(X-x_n), where x_1, x_2, x_3,...x_n are the roots (real or complex) of the equation P(X)=0.

The procedure ( for a 3rd degree polynomial) is as follows: (the fixYa site parser will remove the plus signs, so I am writing the whole word plus instead of the mathematical sign

If you want to factor a cubic polynomial P3(X) = aX^3 plus bX^2 plus cX plus d , you write the corresponding cubic equation as

You use the calculator to solve (approximately) this equation.

Suppose you find the 3 roots

You can handle the quadratic polynomial the same way.

P2(X) =a*(X-X1)(X-X2) where X1, X2 are the two real roots.

To find the various roots you must use the solve( application.

Nov 11, 2010 | Casio FX-9750GPlus Calculator

The short story is that this calculator does have a computer algebra system or CAS and thus cannot factor polynomials with arbitrary (unknown) coefficients or known coefficients.

However if the coefficients are given you can ,if you are willing to travel that way, factor approximately a polynomial P(x).

Basically, the idea is that any polynomial P(X) of degree n can be written in the factored form (X-x_1)(X-x_2)...(X-x_n), where x_1, x_2, x_3,...x_n are the roots (real or complex) of the equation P(X)=0.

The procedure ( for a 3rd degree polynomial) is as follows:

If you want to factor a cubic polynomial P3(X) = aX^3 bX^2 cX d , you write the corresponding cubic equation as**aX^3 bX^2 cX d =0** , then you divide all terms of the equation by** a** to obtain

**X^3 (b/a)X^2 (c/a)X (d/a)=0.**

You use the calculator to solve (approximately) this equation.

Suppose you find the 3 roots**X1,X2,and X3.**
Then the polynomial X^3 (b/a)X^2 (c/a)X (d/a) can be cast in the
factored form (X-X1)(X-X2)(X-X3) and the original polynomial P3(X) can
be written as

**P3(X) = a*(X-X1)(X-X2)(X-X3) **

You can handle the quadratic polynomial the same way.

P2(X) =a*(X-X1)(X-X2) where X1, X2 are the two real roots.

However if the coefficients are given you can ,if you are willing to travel that way, factor approximately a polynomial P(x).

Basically, the idea is that any polynomial P(X) of degree n can be written in the factored form (X-x_1)(X-x_2)...(X-x_n), where x_1, x_2, x_3,...x_n are the roots (real or complex) of the equation P(X)=0.

The procedure ( for a 3rd degree polynomial) is as follows:

If you want to factor a cubic polynomial P3(X) = aX^3 bX^2 cX d , you write the corresponding cubic equation as

You use the calculator to solve (approximately) this equation.

Suppose you find the 3 roots

You can handle the quadratic polynomial the same way.

P2(X) =a*(X-X1)(X-X2) where X1, X2 are the two real roots.

Sep 11, 2010 | Casio FX-9750GPlus Calculator

In mathematics, a division is called a **division by zero** if the divisor is zero. Such a division can be formally expressed as *a* / 0 where *a* is the dividend. Whether this expression can be assigned a well-defined value depends upon the mathematical setting. In ordinary (real number) arithmetic, the expression has no meaning, as there is no number which, multiplied by 0, gives *a* (*a*?0).

In computer programming, an attempt to divide by zero may, depending on the programming language, generate an error message or may result in a special not-a-number value (see below).

Historically, one of the earliest recorded references to the mathematical impossibility of assigning a value to*a* / 0 is contained in George Berkeley's criticism of infinitesimal calculus in *The Analyst*; see Ghosts of departed quantities.

In computer programming, an attempt to divide by zero may, depending on the programming language, generate an error message or may result in a special not-a-number value (see below).

Historically, one of the earliest recorded references to the mathematical impossibility of assigning a value to

Sep 03, 2010 | Computers & Internet

no decimals (1.5, .56) no fractions (1/2, 1 3/4)

whole numbers are just whole numbers

1, 2, 3 and on 9,10,11 .....

not

1.5, 2.5, 2.356

1 1/5, 2 2/6,3 1/5

whole numbers are just whole numbers

1, 2, 3 and on 9,10,11 .....

not

1.5, 2.5, 2.356

1 1/5, 2 2/6,3 1/5

Jun 19, 2010 | Mathsoft StudyWorks! Mathematics Deluxe...

Hii,here is list of basic real numbers properties applying them you can solve the problems easily.

Assuming a,b,c,d are real numbers:

**1)Commutative Property **

**a) Property of Addition**: a+b = b+a

**b)Property of Multiplication**: ab = ba

**2)Associative Property **

**a)Property of Addition**: (a+b) + c = a + (b + c)

**b)Property of Multiplication**: ( ab )c = a ( bc )

**3)Additive Identity**:

a+0 = a where 0 is the additive identity

**4)Additive Inverse**:

For real number a, there exists -a such that

a+(-a) = 0

**5)Multiplicative Identity**:

For real number a,

1 X a = a

where 1 is the multiplicative identity

**6)Multiplicative Inverse**:

For real number X where a≠0, there exists 1/asuch that

a X(1/a) = 1

**7)Zero Product Law**:

If ab = 0, then a=0 or b=0 or both a and b = 0.

**8)Distributive Properties**:

**a)Left distributive law**

a (b + c ) = ab + ac

** b)Right distributive law**

(a + b) c = ac+ bc

Assuming a,b,c,d are real numbers:

a+0 = a where 0 is the additive identity

For real number a, there exists -a such that

a+(-a) = 0

For real number a,

1 X a = a

where 1 is the multiplicative identity

For real number X where a≠0, there exists 1/asuch that

a X(1/a) = 1

If ab = 0, then a=0 or b=0 or both a and b = 0.

a (b + c ) = ab + ac

(a + b) c = ac+ bc

Jun 09, 2010 | Vivendi Excel@ Mathematics Study Skills...

The reason is related to the associated multiplication question. If you
divide 6 by 3 the answer is 2 because 2 times 3 IS 6. If you divide 6 by
zero, then you are asking the question, "What number times zero gives 6?"
The answer to that one, of course, is no number, for we know that zero
times any real number is zero not 6. So we say that division by zero is
undefined, for it is not consistent with division by other numbers.

You can try to make up a good set of rules, but it always leads to nonsense, so to avoid all the trouble we just say that it doesn't make sense to divide by zero.

What happens if you add apples to oranges? It just doesn't make sense, so the easiest thing is just to say that it doesn't make sense, or, as a mathematician would say, "it is undefined."

Maybe that's the best way to look at it. When, in mathematics, you see a statement like "operation XYZ is undefined", you should translate it in your head to "operation XYZ doesn't make sense."

Other details can find in Why can't we divide by zero?

Hope help with this (remember rated this).

You can try to make up a good set of rules, but it always leads to nonsense, so to avoid all the trouble we just say that it doesn't make sense to divide by zero.

What happens if you add apples to oranges? It just doesn't make sense, so the easiest thing is just to say that it doesn't make sense, or, as a mathematician would say, "it is undefined."

Maybe that's the best way to look at it. When, in mathematics, you see a statement like "operation XYZ is undefined", you should translate it in your head to "operation XYZ doesn't make sense."

Other details can find in Why can't we divide by zero?

Hope help with this (remember rated this).

Feb 06, 2010 | 1988 Lincoln Mark VII

Hello,

Th CFX-9850GB Plus is programmed to perform 10 types of regressions, namely

LinearReg: Linear y=ax+b

Med-Med also linear y=ax+b

QuadReg :Quadratic y= ax^2+bx+c

Cubic: y=ax^3+bx^2+cx+d

Quartic: y=ax^4+bx^3+cx^2+dx+e

LogReg, logarithmic: y=a+b*ln(x)

ExpReg, exponential y=a*e^(bx)

PowerReg, power: y= ax^b

SinReg, sinusoidal: y=a*sin(bx+c) +d

LogisticReg, logistic; y= c/(1+a*e^(-bx))

There may be more regression models appropriate for more advanced (specialized) statistics but the ones in the list are all the CFX-9850GB plus offers. However, since the calculator knows a programming language, you may want to implement a particular model.

Hope that helps.

Th CFX-9850GB Plus is programmed to perform 10 types of regressions, namely

LinearReg: Linear y=ax+b

Med-Med also linear y=ax+b

QuadReg :Quadratic y= ax^2+bx+c

Cubic: y=ax^3+bx^2+cx+d

Quartic: y=ax^4+bx^3+cx^2+dx+e

LogReg, logarithmic: y=a+b*ln(x)

ExpReg, exponential y=a*e^(bx)

PowerReg, power: y= ax^b

SinReg, sinusoidal: y=a*sin(bx+c) +d

LogisticReg, logistic; y= c/(1+a*e^(-bx))

There may be more regression models appropriate for more advanced (specialized) statistics but the ones in the list are all the CFX-9850GB plus offers. However, since the calculator knows a programming language, you may want to implement a particular model.

Hope that helps.

Oct 24, 2009 | Casio CFX 9850GB Plus Calculator

Hello,

The Casio FX-300ES does not handle symbolic algebra. So it cannot factor a general polynomial expression. The methods can be found in any book on Algebra.

However if you are interested in approximate factorization of quadratic and cubic polynomials, you can use the calculator to do that. It can solve aX^3 +bX^2+cX+d =0 and the quadratic equations.

If you want to factor a cubic polynomial P3(X) = aX^3+bX^2+cX+d , you write the corresponding cubic equation as**aX^3+bX^2+cX=d =0** , then you divide all terms of the equation by** a** to obtain

**X^3+(b/a)X^2+(c/a)X+(d/a)=0.**

You use the calculator to solve (approximately) this equation.

Suppose you find the 3 roots**X1,X2,and X3.** Then the polynomial X^3+(b/a)X^2+(c/a)X+(d/a) can be cast in the factored form (X-X1)(X-X2)(X-X3) and the original polynomial P3(X) can be written as

**P3(X) = a*(X-X1)(X-X2)(X-X3) **

You can handle the quadratic polynomial the same way.

P2(X) =a*(X-X1)(X-X2) where X1, X2 are the two real roots

Hope it helps.

The Casio FX-300ES does not handle symbolic algebra. So it cannot factor a general polynomial expression. The methods can be found in any book on Algebra.

However if you are interested in approximate factorization of quadratic and cubic polynomials, you can use the calculator to do that. It can solve aX^3 +bX^2+cX+d =0 and the quadratic equations.

If you want to factor a cubic polynomial P3(X) = aX^3+bX^2+cX+d , you write the corresponding cubic equation as

You use the calculator to solve (approximately) this equation.

Suppose you find the 3 roots

You can handle the quadratic polynomial the same way.

P2(X) =a*(X-X1)(X-X2) where X1, X2 are the two real roots

Hope it helps.

Sep 27, 2009 | Casio fx-300ES Calculator

You have two methods for drawing a circle on the FX-9750GPlus.

- Use the Conics graphing: The general equation of a circle is aX^2 + aY^2 + bX+cY+d=0
- Use the function graphing. But before you can do that you must transform the general equation (above) in such a way that you can write it as Y^2= X^2+EX+F. From this you can find the two branches Y1=SQRT(X^2+EX+F) and Y2=-SQRT(X^2+EX+F)

Oct 09, 2007 | Casio FX-9750GPlus Calculator

May 26, 2017 | Xerox Office Equipment & Supplies

May 26, 2017 | Educational Insights Office Equipment &...

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