If u square the product of 3 and 4, then whats the answer?

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Posted on Jan 02, 2017

Hi Paula:

A mathematical logic question.

You need to get all of the measurements in the same units.

- A cubic yard is 1 yard x 1 yard x 1 yard

- equals 3 ft x 3 ft x 3 ft

- equals 27 cubic feet,

so once you have the volume of the pipe in cubic feet, you divide by 27 to get the volume in cubic yards.

- Volume of a cylinder (the pipe) is the cross sectional area X length.

- Area equals Pi x r squared.

- equals 22/7 x 1 x 1

equals 3.14#####

times length (20)

equals 62.857### cubic feet volume

divide by 27 cubic feet

equals 2.328### cubic yards.

- The answer is always the easy part.

- what is important is knowing exactly what the question is, and

- determing what calculations are needed to get the answer.

Wasn't that better than if I'd just said 2 1/3 cubic yards?

Cheers

A mathematical logic question.

You need to get all of the measurements in the same units.

- A cubic yard is 1 yard x 1 yard x 1 yard

- equals 3 ft x 3 ft x 3 ft

- equals 27 cubic feet,

so once you have the volume of the pipe in cubic feet, you divide by 27 to get the volume in cubic yards.

- Volume of a cylinder (the pipe) is the cross sectional area X length.

- Area equals Pi x r squared.

- equals 22/7 x 1 x 1

equals 3.14#####

times length (20)

equals 62.857### cubic feet volume

divide by 27 cubic feet

equals 2.328### cubic yards.

- The answer is always the easy part.

- what is important is knowing exactly what the question is, and

- determing what calculations are needed to get the answer.

Wasn't that better than if I'd just said 2 1/3 cubic yards?

Cheers

Jan 05, 2016 | Office Equipment & Supplies

Download the full solutions of IITJEE 2011 from below given links.

IITJEE 2011 FULL SOLUTIONS PAPER 1

IITJEE 2011 FULL SOLUTIONS PAPER 2

IIT-JEE 2011 AnalysisIIT JEE 2011 was conducted on 10th April 2011 in 131 cities all over India in 1051 centres for 4,85,262 registered candidates. For the first time, JEE has announced that scanned images of the Optical Response Sheets (ORS) with the candidates' details and their responses (answers) will be displayed on the JEE website after 25th May 2011. Answer Keys to JEE 2011 questions will be displayed on the JEE website on 15th May 2011 after completing the evaluation of OMR Sheets.

There were 10 versions for IIT-JEE 2011 - 0 to 9. The order of subjects in both papers were the same - Chemistry, Mathematics and Physics but the total marks, the number of questions and types of questions in both papers were distinct from each other.

**Paper-1**Paper1 had 69 questions in total for 240 marks - in the order of Chemistry, Physics and Mathematics. Each subject had 23 questions and the pattern was exactly the same for all the subjects.

**Chemistry**

This is a moderate level paper leaning more towards easy level of difficulty. The usual weightage of Physical > Organic > Inorganic Chemistry is maintained. Most of the questions in this paper evaluate the conceptual clarity of the student.

**Physics**

Overall the difficulty level of the paper was moderate. Still there were a few numerical questions involving elaborate mathematical calculations making them time consuming and hence difficult. No representation of Optics in this paper. Major focus in this paper was on Mechanics (for a total marks of 31)

**Mathematics**

Mathematics part of the 2011 JEE paper 1 was considered easier than the paper 1 of 2010. Few questions in Integer answer type require in-depth understanding of the concepts with perseverance in solving problems. Trigonometry had a good representation in the paper; the passage on matrices required quick thinking to interpret and solve the questions. One question about '3 x 3 non-singular skew symmetric matrices' has a basic flaw since odd ordered skew symmetric matrices are always singular. Paper 1 was a moderately difficult paper.

**Pattern of Paper-1:**

Paper-2Paper 2 had 60 questions in total - in the order of Chemistry, Physics and Mathematics. Each subject had 20 questions and as in paper 1 the pattern was exactly the same across the subjects. Questions had differential markings, each subject had 80 marks and the maximum mark for the paper was 240.

**Chemistry**

Paper 2 of IIT-JEE 2011 was difficult compared to paper 1. Weightage wise the Physical > Organic > Inorganic formula is maintained. Generally the nature of the questions in Physical chemistry is calculation oriented and hence the difficulty. Also complexity of Organic questions made this paper a challenging one.

**Physics**

Questions from certain areas which were not represented in paper 1 (gravitation, optics etc.) appeared in paper 2 thus balancing the Syllabus coverage. The difficulty level of this paper was slightly less than paper 1 especially the Integer Answer Type.

**Mathematics**

Paper 2 Mathematics part was tougher than the first paper - for the complexity in combining topic areas, for e.g. the matrix match had questions from 4 different areas posing a challenge for the student in the exam hall. Likewise, this paper required more calculations in solving than the first paper. Overall Mathematics part of IIT-JEE 2011 was less difficuly and less time consuming than that of 2010. The second paper was restricted to lesser number of areas, for e.g. there were no questions from Trigonometry. But this time Differential Calculus and Coordinate Geometry were well

represented.

**Pattern of Paper 2:**

*Courtesy: TIME*

IITJEE 2011 FULL SOLUTIONS PAPER 1

IITJEE 2011 FULL SOLUTIONS PAPER 2

IIT-JEE 2011 AnalysisIIT JEE 2011 was conducted on 10th April 2011 in 131 cities all over India in 1051 centres for 4,85,262 registered candidates. For the first time, JEE has announced that scanned images of the Optical Response Sheets (ORS) with the candidates' details and their responses (answers) will be displayed on the JEE website after 25th May 2011. Answer Keys to JEE 2011 questions will be displayed on the JEE website on 15th May 2011 after completing the evaluation of OMR Sheets.

There were 10 versions for IIT-JEE 2011 - 0 to 9. The order of subjects in both papers were the same - Chemistry, Mathematics and Physics but the total marks, the number of questions and types of questions in both papers were distinct from each other.

This is a moderate level paper leaning more towards easy level of difficulty. The usual weightage of Physical > Organic > Inorganic Chemistry is maintained. Most of the questions in this paper evaluate the conceptual clarity of the student.

Overall the difficulty level of the paper was moderate. Still there were a few numerical questions involving elaborate mathematical calculations making them time consuming and hence difficult. No representation of Optics in this paper. Major focus in this paper was on Mechanics (for a total marks of 31)

Mathematics part of the 2011 JEE paper 1 was considered easier than the paper 1 of 2010. Few questions in Integer answer type require in-depth understanding of the concepts with perseverance in solving problems. Trigonometry had a good representation in the paper; the passage on matrices required quick thinking to interpret and solve the questions. One question about '3 x 3 non-singular skew symmetric matrices' has a basic flaw since odd ordered skew symmetric matrices are always singular. Paper 1 was a moderately difficult paper.

- Q.No.1 to 7 - Single Correct Choice Type (7 questions for 21 marks). +3 for correct answer and -1 for wrong answer
- Q.No. 8 to 11 - Multiple Correct Choice Type (4 questions for 16 marks). +4 for correct answer with NO negatives
- Q.No. 12 to 16 - Paragraph Type(5 questions for 15 marks). There were 2 paragraphs- one paragraph with 2 questions and the second one with 3 questions. All questions were of Single Correct Choice Type. +3 for correct answer and -1 for wrong answer
- Q.No.17 to 23- Integer Type (7 questions for 28 marks). Answers were of single digit (ie, 0 to 9) . +4 for correct answer with NO negatives.

Paper-2Paper 2 had 60 questions in total - in the order of Chemistry, Physics and Mathematics. Each subject had 20 questions and as in paper 1 the pattern was exactly the same across the subjects. Questions had differential markings, each subject had 80 marks and the maximum mark for the paper was 240.

Paper 2 of IIT-JEE 2011 was difficult compared to paper 1. Weightage wise the Physical > Organic > Inorganic formula is maintained. Generally the nature of the questions in Physical chemistry is calculation oriented and hence the difficulty. Also complexity of Organic questions made this paper a challenging one.

Questions from certain areas which were not represented in paper 1 (gravitation, optics etc.) appeared in paper 2 thus balancing the Syllabus coverage. The difficulty level of this paper was slightly less than paper 1 especially the Integer Answer Type.

Paper 2 Mathematics part was tougher than the first paper - for the complexity in combining topic areas, for e.g. the matrix match had questions from 4 different areas posing a challenge for the student in the exam hall. Likewise, this paper required more calculations in solving than the first paper. Overall Mathematics part of IIT-JEE 2011 was less difficuly and less time consuming than that of 2010. The second paper was restricted to lesser number of areas, for e.g. there were no questions from Trigonometry. But this time Differential Calculus and Coordinate Geometry were well

represented.

- Q.No.1 to 8 - Single Correct Choice Type (8 questions for 24 marks). +3 for correct answer and -1 for wrong answer
- Q.No. 9 to 12 - Multiple Correct Choice Type (4 questions for 16 marks). +4 for correct answer with NO negatives. There was NO partical marking as well.
- Q.No. 13 to 18 - Integer Type (6 questions for 24 marks). Answers were of single digit (ie, 0 to 9) . +4 for correct answer with NO negatives.
- Q.No.19 & 20- Matrix Match Type (2 questions with 4 rows each - for 16 marks). There were 4 elements in the first column to be matched with 5 elements in the second column. Each row carried 2 marks. There were NO negarive marking.

on Apr 11, 2011 | Computers & Internet

To find the answer, take the square of the first number and subtract from it the square root of the second number:

5 squared is 25

sgrt of 4 is 2; 25-2=23

9 squared is 81

sqrt of 9 is 3; 81-3=78

so:

3 squared is 9

sqrt of 81 is 9; 9-9=**0**

The answer is** zero**!

5 squared is 25

sgrt of 4 is 2; 25-2=23

9 squared is 81

sqrt of 9 is 3; 81-3=78

so:

3 squared is 9

sqrt of 81 is 9; 9-9=

The answer is

Feb 07, 2013 | Vivendi Excel@ Mathematics Study Skills...

2012 is answer

(5) square = 25 , 25-5 = 20 , (5)square = 25 , 25+5 = 30 so == 2030, (3)square = 9 , 9+3 = 12, (5)square = 25 , 25-5 = 20 so == 1220, now

5) square = 25 ., 25-5 = 20, 3)square = 9 , 9+3 = 12

the +,-,+,- series is continued.

(5) square = 25 , 25-5 = 20 , (5)square = 25 , 25+5 = 30 so == 2030, (3)square = 9 , 9+3 = 12, (5)square = 25 , 25-5 = 20 so == 1220, now

5) square = 25 ., 25-5 = 20, 3)square = 9 , 9+3 = 12

the +,-,+,- series is continued.

Apr 12, 2012 | Vivendi Excel@ Mathematics Study Skills...

3:4=n:12

3:4=9:12

n=12

Divide 12 to 4 you get 3. Multiply 3 to 3 and you get 9.

Please rate my answer if you appreciate it.

3:4=9:12

n=12

Divide 12 to 4 you get 3. Multiply 3 to 3 and you get 9.

Please rate my answer if you appreciate it.

Sep 08, 2011 | Samson Technology Hayes School Publishing...

In mathematics, **special products** are of the form:

(a+b)(a-b) = a2 - b2 (Product of sum and difference of two terms) which can be used to quickly solve multiplication such as:

301 * 299 = (300 +1)(300-1) = 3002 - 12 = 90000 - 1 = 89999__types__

1. Square of a binomial

(a+b)^2 = a^2 + 2ab + b^2

carry the signs as you solve

2. Square of a Trinomial

(a+b+c)^2 = a^2 + b^2 + c^2 + 2ab + 2ac + 2bc

carry the sings as you solve

3. Cube of a Binomial

(a+b)^3 = a^3 + 3(a^2)b + 3a(b^2) + b^3

4. Product of sum and difference

(a+b)(a-b) = a^2 - b^2

5. Product of a binomial and a special multinomial

(a+b)(a^2 - ab + b^2) = a^3-b^3

(a-b)(a^2 + ab + b^2) = a^3-b^3

(a+b)(a-b) = a2 - b2 (Product of sum and difference of two terms) which can be used to quickly solve multiplication such as:

301 * 299 = (300 +1)(300-1) = 3002 - 12 = 90000 - 1 = 89999

(a+b)^2 = a^2 + 2ab + b^2

carry the signs as you solve

2. Square of a Trinomial

(a+b+c)^2 = a^2 + b^2 + c^2 + 2ab + 2ac + 2bc

carry the sings as you solve

3. Cube of a Binomial

(a+b)^3 = a^3 + 3(a^2)b + 3a(b^2) + b^3

4. Product of sum and difference

(a+b)(a-b) = a^2 - b^2

5. Product of a binomial and a special multinomial

(a+b)(a^2 - ab + b^2) = a^3-b^3

(a-b)(a^2 + ab + b^2) = a^3-b^3

Jul 28, 2011 | Computers & Internet

Hi
5+3=28, 9+1=810, 8+6=214, 5+4=19, 38+20=1858

First find difference and then sum............. If we take 5+3 =28, 5-3=2 and 5+3=8 so answer is 28 like wise

7+3 = 410 So answer is 410

First find difference and then sum............. If we take 5+3 =28, 5-3=2 and 5+3=8 so answer is 28 like wise

7+3 = 410 So answer is 410

Jul 16, 2010 | Vivendi Excel@ Mathematics Study Skills...

Perfect squares are the product of a whole number and itself. Given that 22 squared = 484, and 23 squared = 529, I'd say the answer to your question is that there is no square number between 490 and 500.

Jan 18, 2010 | Mathsoft StudyWorks! Mathematics Deluxe...

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