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Log^-1(11/20) please solve step by step. - Texas Instruments TI-83 Plus Calculator

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Assuming you want the common antilog of 11/20:
2nd 10^x 1 1 / 2 0 ENTER

10^x is on the LOG key, to the left of the 7 key.

Posted on Nov 15, 2010

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2log(base4)x + log(base4)3=log(base4)x-log(base4)2


Hi,
It is easier to use the rules for logarithms to clean this equation before trying to solve it. And the calculator is no help here.
Let me represent the logs as follows log b in base a = log(a,b). The first argument is the base.

2*log(4,x) - log(4,3)= log(4,x)- log(4,2)

Here you have two similar terms 2*log(4,x) on the left and log(4,x) on the right. Gather them both on the same side, say the left. You have

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Take the constant term to the left, while changing its sign in the process. On the right remains 0, which is also the log of 1 in any base So log(4,x)+log(4,6) =0 =log(4,1)

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log(4,6x)=log(4,1) which is equivalent to 6x=1. The solution is x=1/6

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Hope it helps.


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so instead input log 8 base 2 you need to input log 8 / log 2
your example answer is about 0.919... if i get right what did you write.
Glad to help :)

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