Question about Acer Aspire One PC Notebook

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Posted on Jan 02, 2017

You need to calibrate the heat mass before reassembling the choke unit. This is from John Twist of University Motor. Hope it helps.

Loosen the 1/2" headed bolt that fastens the water jacket to the heat mass. Then, disconnect the two hoses from the water jacket and plug them with 7/16" bolts. Remove the bolt the rest of the way and CAREFULLY lever the water jacket away from the heat mass. Then, remove the three screws that hold the heat mass to the auto choke.

Remove the heat mass and carefully remove the black plastic insulator. Now you can work with the auto choke and calibrate the heat mass.

Copiously oil the inside of the autochoke, and exercise it -- hold the throttle wide open and move the little lever which engages the bi-metal strip of the heat mass from its 3:00 position to the 12:00 position -- about twenty times.

Place the heat mass in a pan of water and bring it to a boil. Pick the heat mass from the boiling water and inspect the alignment of the bi-metal strip -- well, really the rectangle -- and the line scribed in the circumference of the heat mass. That line is usually ill-defined or worse, completely obliterated. Cut a new line with your hacksaw wherever the rectangle is positioned.

Now reassemble the unit, taking GREAT care to match the finger of the choke with the rectangle of the bi-metal strip. Position all three lines (the boss on the auto choke body, the raised line on the black plastic insulator, and the line you just made with the hacksaw), in line.

Loosen the 1/2" headed bolt that fastens the water jacket to the heat mass. Then, disconnect the two hoses from the water jacket and plug them with 7/16" bolts. Remove the bolt the rest of the way and CAREFULLY lever the water jacket away from the heat mass. Then, remove the three screws that hold the heat mass to the auto choke.

Remove the heat mass and carefully remove the black plastic insulator. Now you can work with the auto choke and calibrate the heat mass.

Copiously oil the inside of the autochoke, and exercise it -- hold the throttle wide open and move the little lever which engages the bi-metal strip of the heat mass from its 3:00 position to the 12:00 position -- about twenty times.

Place the heat mass in a pan of water and bring it to a boil. Pick the heat mass from the boiling water and inspect the alignment of the bi-metal strip -- well, really the rectangle -- and the line scribed in the circumference of the heat mass. That line is usually ill-defined or worse, completely obliterated. Cut a new line with your hacksaw wherever the rectangle is positioned.

Now reassemble the unit, taking GREAT care to match the finger of the choke with the rectangle of the bi-metal strip. Position all three lines (the boss on the auto choke body, the raised line on the black plastic insulator, and the line you just made with the hacksaw), in line.

Feb 25, 2015 | 1956 MG Midget TF

If you would like to know the circumference of a 15" diameter circle this is the formula:

circumference = radius x 2 x pi

circumference = diameter x pi

in our case:

circumference = 15" x 3,14

circumference = 47 ,1" (that's 119,634 cm)

circumference = radius x 2 x pi

circumference = diameter x pi

in our case:

circumference = 15" x 3,14

circumference = 47 ,1" (that's 119,634 cm)

May 06, 2014 | Cars & Trucks

The circumference of a circle is given by the expression

Circumference= 2* PI* Radius of circle

**C=2*Pi*R**

The area is given by

**Area of a disk with radius R** **= Pi* R*R** or **PI*R^2**

**Area= PI*R^2**

Circumference= 2* PI* Radius of circle

The area is given by

Mar 11, 2014 | SoftMath Algebrator - Algebra Homework...

The circumference of any circle is pi (lowercase Greek letter pi) multiplied by the diameter. For a four-foot diameter circle the circumference is about 12 feet 7 inches.

Feb 24, 2014 | Mathsoft Computers & Internet

40 inches is the diagonal measurement of the rectangular shape of the screen, when you say circumference , you may be asking for the area of a rectangular object with a diagonal measurement of 40 inches.

Feb 20, 2014 | Computers & Internet

d/2=r, circumference = 2 x pi x r , pi = 3.14159, so circumference = 2 x 3.14159 x (d/2)

Jan 08, 2014 | Computers & Internet

Create a flowchart that computes for the circumference of circle. Assume that the value for radius is 7.23.Your flowchart should be able to show the value of the circumference.The pie value is 3.1416 which is constant and never be changed.You can compute the circumference by using this formula 2piR?

Jul 06, 2011 | Computers & Internet

The diameter of the circle is the diagonal of the rectangle use Pythagoras this rectangle is a made from two 3,4,5 triangles, so the diameter is 5cm, the radius will be 2.5cm don't forget the BODMAS ordering rule (Brackets of Division Multiplication Addition and Subtraction) Also rounding to 2 decimal places. This solution is based on all four corners of the rectangle touching the circumference of the circle.

Area of a circle is P (22/7) i x Radius (squared ^2) ====> 22/7 x 2.5cm ^ 2 ====> 22/7 x 6.25cm

TOTAL AREA of CIRCLE = 19.64 cm^2

Area of the rectangle is length x width ====> 4 cm x 3 cm

TOTAL AREA of RECTANGLE = 12 cm ^2

The remaining portion is the circle area minus the rectangle 19.64-12 = 7.64 cm^2

SIMPLES brought to you by SpideRaY @ http://www.windowstipsclub.com

Area of a circle is P (22/7) i x Radius (squared ^2) ====> 22/7 x 2.5cm ^ 2 ====> 22/7 x 6.25cm

TOTAL AREA of CIRCLE = 19.64 cm^2

Area of the rectangle is length x width ====> 4 cm x 3 cm

TOTAL AREA of RECTANGLE = 12 cm ^2

The remaining portion is the circle area minus the rectangle 19.64-12 = 7.64 cm^2

SIMPLES brought to you by SpideRaY @ http://www.windowstipsclub.com

Jan 31, 2011 | Computers & Internet

The problem is not related with PC or Laptops. But it is true the question may be related with computer language.

Ans in QBASIC:

10 REM DETERMINE CIRCUMFERENCE OF A CIRCLE 20 PRINT "DIA = D = 2.3cm CIRCUMFERENCE=C PI=3.14" 30 D=2.3 40 C=3.14*D 50 PRINT "CIRCUMFERENCE, C=";C 60 END

Ans in C:

#include<stdio.h> define pi 3.14 main() { float d=2.3,c; printf("\nDiameter D=2.3cm given"); c=pi*d; printf("So the circumference is(in cm) =%.3f",c); getch(); }

Ans in QBASIC:

10 REM DETERMINE CIRCUMFERENCE OF A CIRCLE 20 PRINT "DIA = D = 2.3cm CIRCUMFERENCE=C PI=3.14" 30 D=2.3 40 C=3.14*D 50 PRINT "CIRCUMFERENCE, C=";C 60 END

Ans in C:

#include<stdio.h> define pi 3.14 main() { float d=2.3,c; printf("\nDiameter D=2.3cm given"); c=pi*d; printf("So the circumference is(in cm) =%.3f",c); getch(); }

Jun 08, 2010 | Computers & Internet

30" diameter? Radius is 15" (half of diameter).

30" circumference (distance around) is a little more complicated...

The number is the ratio of the circumference of a circle to the diameter. The value of is approximately 3.14159265358979323846...The diameter of a circle is twice the radius. Given the diameter or radius of a circle, we can find the circumference. We can also find the diameter (and radius) of a circle given the circumference. The formulas for diameter and circumference of a circle are listed below. We round to 3.14 in order to simplify our calculations.

30" circumference (distance around) is a little more complicated...

The number is the ratio of the circumference of a circle to the diameter. The value of is approximately 3.14159265358979323846...The diameter of a circle is twice the radius. Given the diameter or radius of a circle, we can find the circumference. We can also find the diameter (and radius) of a circle given the circumference. The formulas for diameter and circumference of a circle are listed below. We round to 3.14 in order to simplify our calculations.

Nov 17, 2009 | Gateway FPD1975W 19" LCD Monitor

Jun 24, 2014 | Acer Aspire One PC Notebook

May 30, 2014 | Acer Aspire One PC Notebook

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