Question about Casio FX-115MS Plus Calculator

# How do I calculate 5 to the power of 6? - Casio FX-115MS Plus Calculator

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If you look on the calculator between the x to the second and the log buttons, there is a button that looks like an arrow point up. this button stands for "to the power of." so type in 5 "up arrow" 6

Posted on Nov 08, 2010

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## Related Questions:

### Can you help me with a math problem

(7y)^5 - (14xy)^6
7^5 * y*5 - 14^6 * x^6 * y^6
y^5 * (7^5 - 14^6 * x^6 * y)

Nov 07, 2016 | Office Equipment & Supplies

### 1.77955468. I need to multiply this to the 1/6 power. How do i do this on the calc?

Do you mean raise it to the 1/6th power?

Press 1 . 7 7 9 5 5 4 6 8 y^x ( 1 / 6 ) =

y^x is just above the 9 key, / is the divide key.

Oct 27, 2013 | Texas Instruments BA II PLUS Financial...

### How do i raise a number to the negative power for example 1.00625 to the -360 power

1 . 0 0 6 2 5 y^x +/- 3 6 0 =

+/- is the key just to the right of the decimal point key.

Jul 18, 2012 | Sharp EL-501WBBL Calculator

### How to calculate the 19th root

Raise a number to the 1/19 power.

For your example, press ( 6 0 7 8 7 6 / 2 5 8 2 9 5 - 1 ) y^x 1 9 1/x =

Jan 04, 2012 | Texas Instruments BA-II Plus Calculator

### How to calculate FV=\$24,890.65 X (1.06)4 power

Enter it almost exactly as your wrote it.

Assuming you're in the AOS mode, press 2 4 8 9 0 . 6 5 * 1 . 0 6 y^x 4 =

If you're in the chain mode, press 2 4 8 9 0 . 6 5 * ( 1 . 0 6 y^x 4 ) =

"y^x" is the key just above the "9" key. "*" is the multiply key, right and above the "9" key.

Jul 20, 2011 | Texas Instruments BA II PLUS Financial...

### TI-89 Titanium: I want to solve a Binomial Theorem problem (x+y)^6 how would i go about solving this in the calculator?

Using elementary algebria in the binomial theorem, I expanded the power (x + y)^n into a sum involving terms in the form a x^b y^c. The coefficient of each term is a positive integer, and the sum of the exponents of x and y in each term is n. This is known as binomial coefficients and are none other than combinatorial numbers.

Combinatorial interpretation:

Using binomial coefficient (n over k) allowed me to choose k elements from an n-element set. This you will see in my calculations on my Ti 89. This also allowed me to use (x+y)^n to rewrite as a product. Then I was able to combine like terms to solve for the solution as shown below.
(x+y)^6= (x+y)(x+y)(x+y)(x+y)(x+y)(x+y) = x^6+6x^5y+15x^4y^2+20x^3y^3+15x^2y^4+6xy^5+y^6

This also follows Newton's generalized binomial theorem:

Now to solve using the Ti 89.

Using sigma notation, and factorials for the combinatorial numbers, here is the binomial theorem:

The summation sign is the general term. Each term in the sum will look like that as you will see on my calculator display. Tthe first term having k = 0; then k = 1, k = 2, and so on, up to k = n.
Notice that the sum of the exponents (n ? k) + k, always equals n.

The summation being preformed on the Ti 89. The actual summation was preformed earlier. I just wanted to show the symbolic value of (n) in both calculations. All I need to do is drop the summation sign to the actual calculation and, fill in the term value (k), for each binomial coefficient.

This is the zero th term. x^6, when k=0. Notice how easy the calculations will be. All I'm doing is adding 1 to the value of k.

This is the first term or, first coefficient 6*x^5*y, when k=1.
Solution so far = x^6+6*x^5*y

This is the 2nd term or, 2nd coefficient 15*x^4*y^2, when k=2.
Solution so far = x^6+6*x^5*y+15*x^4*y^2

This is the 3rd term or, 3rd coefficient 20*x^3*y^3, when k=3.
Solution so far = x^6+6*x^5*y+15*x^4*y^2+20*x^3*y^3

This is the 4th term or, 4th coefficient 15*x^2*y^4, when k=4.
Solution so far = x^6+6*x^5*y+15*x^4*y^2+20*x^3*y^3+15*x^2*y^4

This is the 5th term or, 5th coefficient 6*x*y^5, when k=5.
Solution so far = x^6+6*x^5*y+15*x^4*y^2+20*x^3*y^3+15*x^2*y^4+6*x*y^5

This is the 6th term or, 6th coefficient y^6, when k=6.
Solution so far = x^6+6*x^5*y+15*x^4*y^2+20*x^3*y^3+15*x^2*y^4+6*x*y^5+y^6

Putting the coefficients together was equal or, the same as for when I used the expand command on the Ti 89.

binomial coefficient (n over k) for (x+y)^6
x^6+6*x^5*y+15*x^4*y^2+20*x^3*y^3+15*x^2*y^4+6*x*y^5+y^6

Jan 04, 2011 | Texas Instruments TI-89 Calculator

### I need to know how to use a scientific calculator to calculate Euler's number for an algebra problem. IE: 5000e to the 0.96th power

5 0 0 0 2ND [e^x] . 9 6 ENTER

computes 5000 e^.96

If you want (5000e)^.96 then it's

( 5 0 0 0 2ND [e^x] 1 ) ^ . 9 6

e^x is just to the left of the 4 key.

Mar 15, 2010 | Texas Instruments TI-83 Plus Calculator

### Is it possible to calculate cube root or higher with BA ii plus?

To extract the roots of orders higher than 2, you can use the universal power key labeled as [Y to x]. if the exponent is an integer 3, 4, 5, 6 etc.
it gives the cube the 4th power, 5th, 6th, etc.
If the exponent is 1/3, 1/4, 1/5, 1/6 you calculate the cubic root, the 4th root and so on.
When you use it to calculate the roots, the radicand (the number the root of which you are calculating) must be positive, otherwise you may get the result as a complex number.

The syntax of the command is value [Y to x] (1/ order of root)

Ex: cube root of 27 is entered as 27 [Y to x] (1/3)

Feb 21, 2010 | Texas Instruments BA-II Plus Calculator

### How to get 5m x 8k on the screen? To cut down on zero button.

How about using the powers of 10?
5 000 000 = 5*10^6
8000 =8*10³
5 000 000 *8 000 =5*8*10^(6+3)= 40*10^9=4*10^10
The power of 10 key is the one labeled x10 to the X, between the dot and Ans. It is in the middle of the bottom row of keys.

Jan 20, 2010 | Casio FX-115ES Scientific Calculator

### How do i display exponents besides 2, or 3 on the sharp EL-531WH?

EL-531W SHARP:

If you want to find 5 to the power of 6 (5^6)
you hit the 5 button, then the button that says yx ( the x is in the exponent spot) then the 6 so it will looks like this 5^6 then press enter to get the answer...hope that helps!

Jul 04, 2009 | Sharp EL-531VB Calculator

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