# If there was eight dogs, twenty people , thirty four chickens, and they were riding a truck how many feet are there?

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Hi,
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Posted on Jan 02, 2017

SOURCE: 2000 chev truck runs ruff

Run the scanner and computer test in order to get better result and exaclty diagnostic. Othewise you must waste your time and money.

God bless you

Posted on Jul 25, 2012

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11 is a prime number so the only number it is divisible by is 1 or itself. So if it was a piece of material it would measure 11 feet by 1 foot so the perimeter is the sum of the four sides (11+11+1+1) which equals 24 feet.
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### How to solve this problem in a different way,A FARM BOY TENDS PIGS AND CHICKENS IN THEIR YARD,hE COUNTED 21 HEADS AND 54 FEET. hOW MANY PIGS AND CHICkENs ARE THERE?pls.share me a strategy without using...

P = number of pigs

Then P is the number of pig-heads, and 4*P is the number of pigs-feet.

C = number of chickens

Then C is the number of chicken-heads, and 2*C is the number of chicken-feet.

Thus: 21 = P + C

Equivalently: 42 = 2*P + 2*C

Also: 54 = 4*P + 2*C

Thus (54-42) = 4*P + 2*C - 2*P - 2*C

Factoring: 12 = 2*P + ( 2*C - 2*C)

Reducing: 6 = P
------------------------------------------------

Or, do it on graph-paper, with 'P' on the X-axis and 'C' on the Y-axis,
and each unit representing one animal (pig or chicken).

Draw one line between (0,21) and (21,0) (no pigs & 21 chickens, versus 21 pigs & 0 chickens)

Draw one line between (0,27) [no pigs and 27 pairs of chicken-feet]
and (13,1) [13 pigs have 52 feet, with 1 pair of chicken-feet]

The two lines cross at exactly one point on the graph, namely at the solution.
--------------------------------------------------------------------------

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### Write a program that accept a number and output its equivalent in words.

Below is the program written in Turbo C.

#include<stdio.h>
void pw(long,char[]);
char *one[]={" "," one"," two"," three"," four"," five"," six"," seven","
eight"," Nine"," ten"," eleven"," twelve"," thirteen"," fourteen","
fifteen"," sixteen"," seventeen"," eighteen"," nineteen"};
char *ten[]={" "," "," twenty"," thirty"," forty"," fifty"," sixty","
seventy"," eighty"," ninety"};

void main()
{
long n;
clrscr();
printf("
Enter any 9 digit no: ");
scanf("%9ld",&n);
if(n<=0)
printf("Enter numbers greater than 0");
else
{
pw((n/10000000),"crore");
pw(((n/100000)%100),"lakh");
pw(((n/1000)%100),"thousand");
pw(((n/100)%10),"hundred");
pw((n%100)," ");
}
getch();
}

void pw(long n,char ch[])
{
(n>19)?printf("%s %s ",ten[n/10],one[n%10]):printf("%s ",one[n]);
if(n)printf("%s ",ch);
}

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### Help me solve

1. Four Hundred Seventy-Eight Ten Thousandths
2. One Thousand Four Hundred Thirty Five Ten Thousandths.
3. Three Thousand Two Hundred Five Ten Thousandths.
4. Four thousand Seven Hundred Eighty Four Ten Thousandths.
5. Four Hundred Ninety Seven Ten Thousandths.

OR

1. Zero point zero four seven eight.
2. Zero point one four three five
3. Zero point three two zero five
4. Zero point four seven eight four
5. Zero point zero four nine seven

Thanks and please take a moment to rate as fixya.

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