I want 8085 programm code to make calculater which can perform addition and subtraction

40 X 68 = 2720

minus

90 X 45 = 4050

2720 -4050 =

equals the negative number = -1330

- 1330 plus 932 equals

the negative number -938

You perform multiplications and divisions before you perform additions and subtractions, moving left to right.
http://www.mathgoodies.com/lessons/vol7/order_operation
s.html

When you perform an arithmetic operation such as addition, subtraction, multiplication, or division the result has a specific name. The result of addition is called the sum; the result of a subtraction is called the difference; the result of multiplication is the PRODUCT. Finally the result of a division is the quotient.

When you perform an arithmetic operation such as addition, subtraction, multiplication, or division the result has a specific name. The result of addition is called the sum; the result of a subtraction is called the difference; the result of multiplication is the PRODUCT. Finally the result of a division is the quotient.

The Fx-300ES does not have any of the nifty features you are not allowed to have. You cannot program it=non programmable. It does not have a QWERTY keyboard and it is totally mute.
It does have a few variables that can be used to store values (A, B,C,D,E, X,Y but I believe that does not disqualify it.
You may want to check your state's exam website for a list of allowed calculators.

Press [2nd F] [x: multiply sign] to enter Hexadecimal base calculation. The digits are 0,1, ...9, A, B, C,D,E, and F.
Enter a number in Hex, press the + sign to perform and addition or - for a subtraction. Press the = sign to obtain the result.

Assuming that the input numbers are given by the user:print "Menu"print "1. Addition"print "2. Subtraction"print "3. Multiplication"print "4. Division"print "0. Quit"
a = input("Please make a selection:")if a == 1: x = input("Please enter a number:") y = input("Please enter another number:") answer = x + yprint "%r plus %r = %r" % (x,y,answer)elif a == 2: x = input("Please enter a number:") y = input("Please enter another number:") answer = x - yprint "%r minus %r = %r" % (x,y,answer)
The same goes for everything else just with different signs. Don't forget that "*" is multiplication and "/" is division. Also, for 0. Just use:
elif a == 0: quit

A fraction is just a number like (almost) any other. On most calculators, as you enter 6/5 the calculator displays its decimal value. When you press - the calculator waits for a number 2 then / then 5. Once you press the equal sign it will calculate 2/5 then subtracts it from the preceding result. The priority rules favor multiplication and division over addition and subtraction.

On some calculators you can keep a fraction in fraction format and operate on it with other fractions, and the result may be obtained as a fraction.
The gist of the story is that ON A CALCULATOR operations on fractions as performed like operations on any number.

Hello,
There is a rule of Algebra, that says
(a^m)[x] (a^n) = a^(m+n)

a is the base of the power, n, and m are the exponents. As you can see, multiplying two powers of the same base is equal to the power of the (common) base with the sum of the exponents.
If that is what you had in mind, the calculator uses the rule correctly and no intervention from you is necessary.
If you enter (2^4)[x](2^6), the calculator will give 1024, which is 2^10.

I may be wrong, but what you call add exponents refers really to performing addition where addends (the terms you add) are arbitrary powers, such as
2^7 + (5.5^3) - (1/3)^4

Once you enter a power term, the calculator calculates it and the result is now just a number. It can be added, subtracted, multiplied

For the exemple above
2 [Y to the x] 7 + (5.5)[Y to the x] 3 -(1/3) [Y to the x] 4 [=] yields 294.3626543

For the cube of 5.5 you can use the key combination [2nd][X^3]

Hope it helps.

I'm assuming you mean this is a programming problem, not the power supply problem you posted under. Here's an example in C, java and such are similar.

Assuming that InputKey is the operator you want to check.
char InputKey;

switch (InputKey) {
case '+':
// do addition here
break;
case '-':
// do subtraction here
break;
default:
// If it's none of the above, do this
};

hi if the code isnt 12345 then the chances are somebody has changed it and you will only get 5 trys at guessing the code.
The problem with your model of phone is that the newer panasonic phones cant be unlocked using a code you will need to get a flash lead and the panasonic flash programme to reset the phone and reset the code.
You can either try and track down a flash lead and programme if you are unable to locate the lead and software then the only other way is to goto a phone repair shop and pay them to unlock the phone and reset the security code.
Give this a try first though if you use ask.com and type in "panasonic unlock calculater" or try "free panasonic unlock calculater" you might find a code generater programme thats only if somebody has manged to crack the code calculater i know their is one for nokia so give it a try.
The only other way you can get this done if the phone shop dont do it for you is find a web site that can unlock the phone remotely these usually charge for this service but not to much about $10 or £5 about that much and these can unlock your phone remotely you can also use ask.com to search for this service their should be a few online so have a look.
If you need further assistance let me know or if you dont understand what i told you then just ask or if you cant locate the unlock calculater.
Try also searching for "free security unlock calculater"
Let me know how you get on ok