9x-5y=-25 and 5y-9x=25

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That is twice the same problem so no solution possible as it is one problem with 2 variable

Posted on Jul 01, 2008

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Posted on Jan 02, 2017

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solution is:

x-5y = 20

-5y = 20-x

5y = x-20

y = (x-20) / 5

x-5y = 20

-5y = 20-x

5y = x-20

y = (x-20) / 5

Dec 14, 2015 | Office Equipment & Supplies

1) 2x + 5y = 7

2) 3x + 6y = 3

I'm going to use the method of elimination to solve for x and y.

Multiply 1) by 3 and 2) by 2 to allow the x's to be eliminated.

1) 6x + 15y = 21

2) 6x + 12y = 6

Now subtract line 2 from line 1.

0x + 3y = 15

---- ----

3 3 divide both sides by 3 to get y by itself.

y =5.

Substitute into 1) to calculate x.

2x + 5(5) = 7

2x + 25 = 7

2x + 25 -25 = 7 - 25

2x = -18

---- ----- divide both sides by 2 to get x by itself

2 2

x = -9

Check by plugging in answer into the other equation, in this case 2)

3 (-9) + 6(5) = 3

-27 + 30 = 3

3 = 3

We did it correctly and checked to prove that we did it right.

Good luck.

Paul

2) 3x + 6y = 3

I'm going to use the method of elimination to solve for x and y.

Multiply 1) by 3 and 2) by 2 to allow the x's to be eliminated.

1) 6x + 15y = 21

2) 6x + 12y = 6

Now subtract line 2 from line 1.

0x + 3y = 15

---- ----

3 3 divide both sides by 3 to get y by itself.

y =5.

Substitute into 1) to calculate x.

2x + 5(5) = 7

2x + 25 = 7

2x + 25 -25 = 7 - 25

2x = -18

---- ----- divide both sides by 2 to get x by itself

2 2

x = -9

Check by plugging in answer into the other equation, in this case 2)

3 (-9) + 6(5) = 3

-27 + 30 = 3

3 = 3

We did it correctly and checked to prove that we did it right.

Good luck.

Paul

Mar 12, 2015 | Office Equipment & Supplies

This is best written as two separate equations:

8x+3y = -23 and 34x+ 5y = -23

Solving the first one for x:

8x = -23-3y

x = -23/8 - 3/8y

Substituting this value for x into the second equation:

34(-23/8 - 3/8y) + 5y = -23

-97.75 - (34)(.375)y + 5y = -23

-97.75 - 12.75y + 5y = -23

-97.75 -7.75y = -23

-7.75y = 97.75-23=74.75

**y **= -74.75/7.75 =** -9.645161**

Substitution back into the equation for x:

x = -23/8 - 3/8(-9.645161)

x = -2.875 + 3.616935

**x** **=.741935**

8x+3y = -23 and 34x+ 5y = -23

Solving the first one for x:

8x = -23-3y

x = -23/8 - 3/8y

Substituting this value for x into the second equation:

34(-23/8 - 3/8y) + 5y = -23

-97.75 - (34)(.375)y + 5y = -23

-97.75 - 12.75y + 5y = -23

-97.75 -7.75y = -23

-7.75y = 97.75-23=74.75

Substitution back into the equation for x:

x = -23/8 - 3/8(-9.645161)

x = -2.875 + 3.616935

Dec 12, 2014 | Bagatrix Algebra Solved! 2005 (105101) for...

To find the x-intercept, set y equal to zero and solve for x.

To find the y-intercept, set x equal to zero and solve for y.

In this case the x-intercept is -3 1/8 and the y-intercept is -5.

To find the y-intercept, set x equal to zero and solve for y.

In this case the x-intercept is -3 1/8 and the y-intercept is -5.

Nov 06, 2014 | Computers & Internet

First of all you equation is not one : it has nothing on the right side of the = sign. But to answer the general question let us write the equation as **50+25x-5y=0**

**X-intercept (also know as roots) There may be several**

Definition: X-intercepts are those values of the independent variable x**for which y=0**. For a straight line there con be at most 1 x-intercept.

To find the intercept, set y=0 in the equation of the line and solve for x

50+25x-5(0)=0 or 50+25x=0. The solution is** x=-(50/25)=-2**

**Y-intercept (also know as the initial value.** There can only be 1 y-intercept, otherwise the expression does not represent a function.

Definition: It is the value of the dependent variable y when x=0 (where the function crosses the y-axis

To find it, set the x-value to 0 in the equation of the line.

**50+25x-5y=0**

50+25(0)-5y=0, or 50-5y=0. The solution is**y=50/5=10**

The straight line cuts the x-axis at the point (-2, 0) and the y-axis at the point (0,10)

Definition: X-intercepts are those values of the independent variable x

To find the intercept, set y=0 in the equation of the line and solve for x

50+25x-5(0)=0 or 50+25x=0. The solution is

Definition: It is the value of the dependent variable y when x=0 (where the function crosses the y-axis

To find it, set the x-value to 0 in the equation of the line.

50+25(0)-5y=0, or 50-5y=0. The solution is

The straight line cuts the x-axis at the point (-2, 0) and the y-axis at the point (0,10)

Jan 28, 2014 | Computers & Internet

Write the equality in the form y=(5X+3)/(4X-5). Insert parentheses to ensure a correct result.

- Multiply both sides of the equality by (4X-5). This gives (4X-5)y=(5X+3).
- Open the parentheses as 4Xy-5y=5X+3
- Subtract 5X from both sides 4Xy-5y-5X=5X-5X+3
- Add 5y to both sides 4Xy-5X-5y+5y=5y+3 or 4Xy-5X=5y+3
- Factor the X on the left side X(4y-5)=5y+3
- If 4y-5 does not vanish, you can isolate X by dividing both members of the equality by (4y-5).
- You get X=(5y+3)/(4y-5)=f(y)

Jun 24, 2012 | Mathsoft StudyWorks! Mathematics Deluxe...

Calcualte the slope of the line as

a=(7-(-11))/(10-(-5))=18/15=6/5

Use the fact that the line passes through one of the two points, for example (10,7)

7=(6/5)*10+b=12+b

Obtain b as b=7-12=-5

The equation of the line in functional form is y=(6/5)x-5

Multiply everything by 5 to clear the fraction

5y=6x-25 or 0=6x-5y-25

Finally, the equation in general form (standard?) is**6x-5y-25=0**.

Check the calculation by verifying that the point (10,7) lies on the line.

6(10)-5(7)-25=60-35-25=60-60=0 CHECKed!

Check that the second point (-5,-11) lies on the line also (if you want to)

6*(-5)-5*(-11)-25=-30+55-25=0

That checks OK.

a=(7-(-11))/(10-(-5))=18/15=6/5

Use the fact that the line passes through one of the two points, for example (10,7)

7=(6/5)*10+b=12+b

Obtain b as b=7-12=-5

The equation of the line in functional form is y=(6/5)x-5

Multiply everything by 5 to clear the fraction

5y=6x-25 or 0=6x-5y-25

Finally, the equation in general form (standard?) is

Check the calculation by verifying that the point (10,7) lies on the line.

6(10)-5(7)-25=60-35-25=60-60=0 CHECKed!

Check that the second point (-5,-11) lies on the line also (if you want to)

6*(-5)-5*(-11)-25=-30+55-25=0

That checks OK.

Dec 04, 2011 | Super Tutor Pre Algebra (ESDPALG)

X=25-y

4(25-y) + 5y=56

100-4y+5y=56

100+y=56

y= -44

x=25+44=69

x=69 y= -44

4(25-y) + 5y=56

100-4y+5y=56

100+y=56

y= -44

x=25+44=69

x=69 y= -44

Aug 22, 2008 | Curtis-Mathis CM25011 25" TV

Aug 16, 2014 | HP DeskJet F380 All-In-One Printer

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