Question about Texas Instruments TI-84 Plus Calculator

Hi,

I'm trying to calculate something for chemistry and the function I need to perform is the inverse log operation. To calculate the ph of a substance the formula is -log(value) but to calculate what i need to now I need to use an inverse log function and removing the - sign before the log key is not working. I have also tried the L1 function and it doesn't work either.

Thanks

The problem is simple. You're trying to get an [H+] concentration which is obviously going to have a value of some number times ten raised to a negative power. Therefore, you have to insert the negative value of the pH into the 10^(x). When you insert said negative number you will come out with the right answer.

i.e.

The pH of a sample of human blood was calculated to be 7.41. What is the [H+] concentration of the blood?

10^(-7.41) = [H+]

[H+] = 3.9 E-8

(the answer should only have two sig. figs because the pH has two digits after the decimal.

Posted on May 18, 2009

Okay, I've finally got this. Haha I've spent an hour messing around with my calculator & I'm pretty sure I know the answer.

If you have a TI-84, Press the 2ND button and the LOG button after (this will give you a small 10^( on the screen) and insert the ion concentration (for chem). You should get the answer that way.

So it would look like this:

10^(12.40)

2.51188...

Posted on May 07, 2009

If I understand you correctly, the inverse of the log operation is exponentiation. So if your log = x, the inverse is 10 raised to the x power. On most TI calculators this is on the same key as the log function.

michael

Posted on Jun 13, 2008

Dude it's simple.

given something like [h30]=1.5x10^-3

- button, log button, 1.5 then shift button, log button (to get the 10x) then, the - button (if your integer is negative, then 3 then two parentheses.

so it looks like this:

-LOG(1.5 10^(-3))

answer should be 2.82 if not then you did something wrong.

Posted on Dec 07, 2009

Try this: (log(V)^(-1), and if that don't work, I'm stumped. :(

Posted on May 07, 2009

GIVEN [H] =3.8X10^-4 WHATS THE PH & POH &OH

Posted on Nov 07, 2011

To get the inverse trigonometric functions press the 2nd key then the trig function key. If you'll look at the key legends above the SIN, COS, and TAN keys you'll see the standard math notations for their inverse function.

Apr 05, 2012 | Texas Instruments TI-84 Plus Calculator

It is much more enlightning to tell us what you want to do rather than talk about something that does not exist. And one thing that does not mean anything is that ellusive INVERSE key that everyone and his dog is looking for.

The additive inverse of a number a is its opposite (-a). The key to use is the change key (-).

The multiplicative inverse of non-zero number a is its reciprocal 1/a

The inverse of the natural log (LN) function is the EXPONENTIAL function e^(x). On most calculators if one function is accessed diectly (the marking is on the key), its inverse is accessed by pressing [SHIF] (Casio, or [2nd] (TI) or [2ndF] (Sharp).

The inverse of the function raise 10 to a power [10^x] is [LOG]

Similarly, the inverse of the sine function SIN is the arcsine [sin^-1]. To access the latter, it you press [2nd][SIN]. The same is true for arcosine [2nd][COS], and arctangent [2nd][TAN]

The inverse of the square functions [x^2] is the square root function [2nd][x^2]

Inverse of x^3 is cubic root

This is just a quick overview.

The additive inverse of a number a is its opposite (-a). The key to use is the change key (-).

The multiplicative inverse of non-zero number a is its reciprocal 1/a

The inverse of the natural log (LN) function is the EXPONENTIAL function e^(x). On most calculators if one function is accessed diectly (the marking is on the key), its inverse is accessed by pressing [SHIF] (Casio, or [2nd] (TI) or [2ndF] (Sharp).

The inverse of the function raise 10 to a power [10^x] is [LOG]

Similarly, the inverse of the sine function SIN is the arcsine [sin^-1]. To access the latter, it you press [2nd][SIN]. The same is true for arcosine [2nd][COS], and arctangent [2nd][TAN]

The inverse of the square functions [x^2] is the square root function [2nd][x^2]

Inverse of x^3 is cubic root

This is just a quick overview.

Feb 16, 2012 | Texas Instruments TI-84 Plus Silver...

The inverse of the log function is the power function.

For log in base 10 that inverse is 10 to a power of

More generally, let b be the base of the logarithm. If y=log_b (x) then x=b^y

For your case log=log_10, to calculate the inverse you perform 10^(-2)=0.01=1/100

On calculators the log in base 10 and its inverse share the same physical key. One is accessed directly, the other is the shifted key function.

For log in base 10 that inverse is 10 to a power of

More generally, let b be the base of the logarithm. If y=log_b (x) then x=b^y

For your case log=log_10, to calculate the inverse you perform 10^(-2)=0.01=1/100

On calculators the log in base 10 and its inverse share the same physical key. One is accessed directly, the other is the shifted key function.

Sep 09, 2011 | Texas Instruments TI-30XA Calculator

For the inverse natural log, press 2nd LN. For the inverse common log, press 2nd LOG.

For example, to calculate the inverse natural log of 2, press 2nd LN 2 ENTER and you'll get about 7.389 .

For example, to calculate the inverse natural log of 2, press 2nd LN 2 ENTER and you'll get about 7.389 .

Jan 25, 2011 | Texas Instruments TI-86 Calculator

There are very few instances where you have two press two keys AT THE SAME TIME, the most notable of them is when you want to force the calculator into the BOOT SCREEN. Most key combinations are key sequences, meaning you press a key and THEN press another.

This said, let us get back to your question.

When you apply a function on an expression, then apply the inverse of the function on the result you get the original expression back.

If f is a function and f^-1 its inverse, by definition f^-1[f(x)]=f[f^-1(x)] =x

As you can see you do not need a calculator to find the result.

Concerning the logarithmic functions

For the natural logarithms (logarithms in base e) labeled [ln], the inverse of the logarithm is the exponential function e^

ln[e^(x)] =e^[ln(x)] =x

For the common logarithms (logarithms in base 10), labeled [log], the inverse function of the log is the raising 10 to the power of. It is usually called the antilogarithm or antilog.

y= log(x) is equivalent to x=10^(y)

Try the following exemple

log(14) = 1.146128036

10^(1.146128036) =14

To access the 10^x function you press [2nd][LOG]

To access the exponential function you press [2nd][LN]

This said, let us get back to your question.

When you apply a function on an expression, then apply the inverse of the function on the result you get the original expression back.

If f is a function and f^-1 its inverse, by definition f^-1[f(x)]=f[f^-1(x)] =x

As you can see you do not need a calculator to find the result.

Concerning the logarithmic functions

For the natural logarithms (logarithms in base e) labeled [ln], the inverse of the logarithm is the exponential function e^

ln[e^(x)] =e^[ln(x)] =x

For the common logarithms (logarithms in base 10), labeled [log], the inverse function of the log is the raising 10 to the power of. It is usually called the antilogarithm or antilog.

y= log(x) is equivalent to x=10^(y)

Try the following exemple

log(14) = 1.146128036

10^(1.146128036) =14

To access the 10^x function you press [2nd][LOG]

To access the exponential function you press [2nd][LN]

Jan 06, 2010 | Texas Instruments TI-84 Plus Calculator

Hello,

As you well know the pH is the negative of the log in base 10 of the H+/H3O+ ion concentration. If we use [H+] to represent that concentration, then**pH=-log[H+]**.

To obtain the [H+] you need to calculate the antilog. You write the definition in the form**log[H+] =-pH **and then calculate 10 to the power of each member. The equality remains valid as both members are treated similarly. Thus

10^( log[H+] ) = 10^(-pH)

Since raising 10 to a power is the inverse function of taking the log in base 10, 10^(log(x))=log(10^(x)) = x (they are inverse of one another), you are left with

**[H+]=10^(-pH)**

Your calculator has a function [10 to x] accessed by pressing the [2nd] function key. **To use it you must enter the negative value of the pH, press the ** [2nd] function key then the [10 to x], then the = key to get the result (concentration)

Exemple: let the pH=5.5, what is the H+ concentration?

With [(-)] being the change sign key, then

[H+]:**[ (-) ] 5.5 [2nd][10 to x] [=] **

The result is 0.000003162 or 3.16 x 10^(-6)

Hope it helps.

As you well know the pH is the negative of the log in base 10 of the H+/H3O+ ion concentration. If we use [H+] to represent that concentration, then

To obtain the [H+] you need to calculate the antilog. You write the definition in the form

10^( log[H+] ) = 10^(-pH)

Since raising 10 to a power is the inverse function of taking the log in base 10, 10^(log(x))=log(10^(x)) = x (they are inverse of one another), you are left with

Exemple: let the pH=5.5, what is the H+ concentration?

With [(-)] being the change sign key, then

[H+]:

Dec 07, 2009 | Texas Instruments TI-30XA Calculator

Hi,

Sorry to contradict you but there are many types of logarithms, the most important ones are

**[LOG]**, and the natural logarithms are labeled** [LN]**.

The inverse function of the natural log function is the exponential (e^(x)), and the inverse of the log in base ten function is the function ten to the power of. It is called (sometimes) the antilog

Ex:

Question What is the antilog of 3.5678?

Answer The antilog of 3.5678 is 10^(3.5678) = 3696.579068

Verification: log(3696.57908) =3.5678

Hope it helps.

Sorry to contradict you but there are many types of logarithms, the most important ones are

- the common logarithms (log in base 10),
- the natural logarithms (logarithms in base e)
- the binary logarithms (logarithms in base 2)

The inverse function of the natural log function is the exponential (e^(x)), and the inverse of the log in base ten function is the function ten to the power of. It is called (sometimes) the antilog

Ex:

Question What is the antilog of 3.5678?

Answer The antilog of 3.5678 is 10^(3.5678) = 3696.579068

Verification: log(3696.57908) =3.5678

Hope it helps.

Nov 29, 2009 | Texas Instruments TI-30XA Calculator

"2nd" + "log"

May 29, 2009 | Texas Instruments TI-84 Plus Silver...

I'm not specifically familiar with the TI83 or TI84 but I've used a lot of TI calculators in my time, so I'll give it a try. If your trying to find the antilog of a number in base 10 enter the number and hit the (10 to the X) button. If you're trying to find the antilog of a number in in base e (natural log), enter the number and hit the (e to the X) button.

May 29, 2009 | Texas Instruments TI-83 Plus Calculator

pH is minus (log to base 10) of the hydrogen ion activity of an aqueous solution, or (log to base 10) of (1/hydrogen ion activity)

To get the inverse log, i.e the hydrogen ion activity corresponding to a specified pH, simply enter the pH value and press

2nd

LOG

1/x

Answer 0.001

To get the inverse log, i.e the hydrogen ion activity corresponding to a specified pH, simply enter the pH value and press

2nd

LOG

1/x

Answer 0.001

Apr 22, 2008 | Texas Instruments TI-30XA Calculator

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Where is the inverse log key?

With the TI-84 plus this the log key and 10x key are the same but they don't give you the same answers. For example to find the pH of x=8.9e-4 I use -log(x) and get a pH of 3.05 however when I 3.05 to 10^x I do not get the original 8.9e-4 value but instead1122.01. This is a real issue!!!

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