# How to find Antilog on sharp EL-531wh calculator

Posted by on

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Posted on Jan 02, 2017

SOURCE: user's manual Sharp EL-531WH

Posted on Aug 10, 2007

Hello,

Let y=10^(x) 10 to the power of x
Take the log of both tems of the equality. You get
log(y)=log[10^(x)] where I used square brackets for clarity. But from the general properties of logarithms

log(b^(a)) = a*log(b)
Applied to our expression above
log(10^x)=x*log10
But since we are using log as log in base 10, log_10(10)=1
so
log(y)=x
We thus have two equivalent relations
y=10^x <----> x=log(y) The double arrow stands for equivalence.

If y is the log of x, then x is the antilog of y

Your question: With log_10 standing for logarith in base 10
pH=-log_10(c) c= concentration
Then log_10(c)=-pH the equivalence above translates as
log_10(c)=-pH is equivalent to c=10^(-pH)

The concentartion corresponding to a pH of 7.41 is
c=10^(-7.41)=3.89x10^(-8)

You enter it as follows
10[^]7.41[(-)][ENTER/=]

Hope it helps

Posted on Sep 07, 2009

Hello,
On Sharp calculators, the shift key is the [2ndF] key.
Hope it helps.

Posted on Sep 19, 2009

http://www.sharpusa.com/~/media/CF70E34972714230ABB931048EF5CB44.ashx?cal_man_EL531_509.pdf

Posted on Jul 30, 2010

Get it from the manufacturer's web site at
http://www.sharpusa.com/~/media/CF70E34972714230ABB931048EF5CB44.ashx?cal_man_EL531_509.pdf

Posted on Jul 30, 2010

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### How do i use the inv log for calculations on my sharp el-531wh

Hello,

Let y=10^(x) 10 to the power of x
Take the log of both tems of the equality. You get
log(y)=log[10^(x)] where I used square brackets for clarity. But from the general properties of logarithms

log(b^(a)) = a*log(b)
Applied to our expression above
log(10^x)=x*log10
But since we are using log as log in base 10, log_10(10)=1
so
log(y)=x
We thus have two equivalent relations
y=10^x <----> x=log(y) The double arrow stands for equivalence.

If y is the log of x, then x is the antilog of y

Your question: With log_10 standing for logarith in base 10
pH=-log_10(c) c= concentration
Then log_10(c)=-pH the equivalence above translates as
log_10(c)=-pH is equivalent to c=10^(-pH)

The concentartion corresponding to a pH of 7.41 is
c=10^(-7.41)=3.89x10^(-8)

You enter it as follows
10[^]7.41[(-)][ENTER/=]

Hope it helps

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Hello,
On Sharp calculators, the shift key is the [2ndF] key.
Hope it helps.

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### User's manual Sharp EL-531WH

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