Question about Mental MathSecret Online Learning Plans

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Posted on Jan 02, 2017

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any numbers that are not dividable by 3

so take each number between 1 and 100 , divide it by 3 and if you don.t get a remainder that number is not what you are looking for

grade 2 maths really

so take each number between 1 and 100 , divide it by 3 and if you don.t get a remainder that number is not what you are looking for

grade 2 maths really

Sep 20, 2016 | Office Equipment & Supplies

Let's do the preocess so it will work on any calculator.

As an example, convert 68 from decimal to binary.

The decimal columns are 10^0, 10^1, 10^2, 10^3, etc.

The binary columns are 2^0, 2^1, 2^2, 2^3, etc.

Flipping to the normal left to right, we get 2^6, 2^5, 2^4, 2^3, 2^2, 2^1, 2^0.

64 32 16 8 4 2 1

We divide our number, 68, by 64, and get 1 with a remainder of 4. We next divide our remainder by 32, 16, 8, and finally 4, where we get 1 with no reminder.

In binary, this works out to 1000100. To check, we multiply the ones by the respective column values and get 64 + 4 = 68.

Good luck.

Paul

As an example, convert 68 from decimal to binary.

The decimal columns are 10^0, 10^1, 10^2, 10^3, etc.

The binary columns are 2^0, 2^1, 2^2, 2^3, etc.

Flipping to the normal left to right, we get 2^6, 2^5, 2^4, 2^3, 2^2, 2^1, 2^0.

64 32 16 8 4 2 1

We divide our number, 68, by 64, and get 1 with a remainder of 4. We next divide our remainder by 32, 16, 8, and finally 4, where we get 1 with no reminder.

In binary, this works out to 1000100. To check, we multiply the ones by the respective column values and get 64 + 4 = 68.

Good luck.

Paul

Feb 28, 2016 | Casio FX-85GT Plus Scientific Calculator...

Where to start. Most things we do in math are in base 10, probably because we have 10 fingers. Instead of base 10, binary is base 2. In computers, binary rules because a bit can be set to ON or OFF, 1 being ON, and 0 being OFF.

So the next thing is counting. 0 1 10 11 100 101 110 111 1000 1001

Decimal equivalent 0 1 2 3 4 5 6 7 8 9

How to convert from binary to decimal? Line up the columns and multiply down. For example, 1101. The columns, starting from the right are 2^0, 2^1, 2^2, 2^3, reading ^ as exponent.

See if I can line these up. 1 1 0 1

2^3 2^2 2^1 2^0

8 4 2 1

multiplying down 8 4 0 1

Next step is to add them up. 8+4+1 = 13!

Going the other way, we have to divide by the largest 2^x number, so what is left over and continue dividing until nothing is left.

For example, 56. 2^5 (32) is the largest 2^x number that goes into 56, so we put a 1 in this column. Our remainder is 24. 2^4 (16) goes into this once, so we put a 1 in this column. Our remainder is 8. 2^3(8) goes into this once, so we put a 1 in this column. Now the remainder is 0 so we put a 0 in the 2^2 (4) column, 2^1(2) column, and 2^0 (1) column.

We end up with 111000.

Let me know if you have any questions.

Good luck.

Paul

So the next thing is counting. 0 1 10 11 100 101 110 111 1000 1001

Decimal equivalent 0 1 2 3 4 5 6 7 8 9

How to convert from binary to decimal? Line up the columns and multiply down. For example, 1101. The columns, starting from the right are 2^0, 2^1, 2^2, 2^3, reading ^ as exponent.

See if I can line these up. 1 1 0 1

2^3 2^2 2^1 2^0

8 4 2 1

multiplying down 8 4 0 1

Next step is to add them up. 8+4+1 = 13!

Going the other way, we have to divide by the largest 2^x number, so what is left over and continue dividing until nothing is left.

For example, 56. 2^5 (32) is the largest 2^x number that goes into 56, so we put a 1 in this column. Our remainder is 24. 2^4 (16) goes into this once, so we put a 1 in this column. Our remainder is 8. 2^3(8) goes into this once, so we put a 1 in this column. Now the remainder is 0 so we put a 0 in the 2^2 (4) column, 2^1(2) column, and 2^0 (1) column.

We end up with 111000.

Let me know if you have any questions.

Good luck.

Paul

Oct 26, 2015 | Office Equipment & Supplies

There are an infinite number of numbers that qualify. The smallest such positive number is 125. The next such number is 251.

Sep 29, 2014 | Office Equipment & Supplies

I am afraid the question does not make complete sense.

However to find the remainder of an integer division

You use the fraction [a b/c] key

Example remainder of 29 divided by 15

29 [a b/c] 25 [=]

That gives you 29/15

Press [SHIFT][a b/c] (d/c), you get 1 u 14 u 15 or 1 14/15. The numerator of the fraction part is the remainder.

However to find the remainder of an integer division

You use the fraction [a b/c] key

Example remainder of 29 divided by 15

29 [a b/c] 25 [=]

That gives you 29/15

Press [SHIFT][a b/c] (d/c), you get 1 u 14 u 15 or 1 14/15. The numerator of the fraction part is the remainder.

Jan 07, 2014 | Casio FX991MS Scientific Calculator

For any polynomial A(x) there is P(x)=A(x)(x-1)(x-2)+2 and this polynomial fulfills above requirements.

Then, remainder of P(x) divide by (x-1)(x-2) is also 2!

Then, remainder of P(x) divide by (x-1)(x-2) is also 2!

Sep 04, 2013 | Texas Instruments Office Equipment &...

The quotient is easy. Since the calculator drops any fractional portion when in base mode, simply do the division. For example, to get the quotient of 5 and 3, divide 5 by 3 and see 1.

The remainder is a bit harder. Subtract the product of the quotient and the divisor from the dividend. For example, to get the remainder of 5 and 3, first calculate the quotient as above. Then subtract 1*3 from 5 and see 2.

The remainder is a bit harder. Subtract the product of the quotient and the divisor from the dividend. For example, to get the remainder of 5 and 3, first calculate the quotient as above. Then subtract 1*3 from 5 and see 2.

Apr 27, 2013 | Casio FX991MS Scientific Calculator

Yes, it's possible because not all numbers are multiples of ten. For example if you divide 63 by 30 (which is multiple of 10) you get 2 and remainder 3 (because 63=2*30+3).

Sep 06, 2011 | Computers & Internet

for converting 486 to the base 10 to base 6 dived 486 by 6 and note the quotients and remainder.

486/6 = quotient = 81 remainder = 0.now divide quotient by 6 and note quotient and remainder.

81/6 = quotient 13 remainder= 3

13/6 = quotient 2 remainder = 1 .

2/6 = quotient 0 remainder= 2.

Hence reading remainder from below we get 2130.

So 486 tot he base 10 is equivalent to 2130 to the base 6.

Thank you.

486/6 = quotient = 81 remainder = 0.now divide quotient by 6 and note quotient and remainder.

81/6 = quotient 13 remainder= 3

13/6 = quotient 2 remainder = 1 .

2/6 = quotient 0 remainder= 2.

Hence reading remainder from below we get 2130.

So 486 tot he base 10 is equivalent to 2130 to the base 6.

Thank you.

Jun 25, 2010 | Mathsoft Solving and Optimization...

It would seem to me that the answer was found at a grade 3 or 4 level

If you divide 288 by 4 you get 97. Then the 1 is carried to the 2 leaving 12. 12 divided be 4 is 3 leaving a result of 397.

Second one....

217 divided by 5 is 43.4 or 43 with a remainder of 2.

Leaving 5 divided by 5 equaling 1.

Combining the 1 with the 43 with a remainder of 2 bringing you a total of 143 r2

This as mentioned would be at a grade 3 or 4 calculation with no understanding of how to properly divide.

I hope this helps and gives you the "A" you're looking for.

All the best.

If you divide 288 by 4 you get 97. Then the 1 is carried to the 2 leaving 12. 12 divided be 4 is 3 leaving a result of 397.

Second one....

217 divided by 5 is 43.4 or 43 with a remainder of 2.

Leaving 5 divided by 5 equaling 1.

Combining the 1 with the 43 with a remainder of 2 bringing you a total of 143 r2

This as mentioned would be at a grade 3 or 4 calculation with no understanding of how to properly divide.

I hope this helps and gives you the "A" you're looking for.

All the best.

Sep 16, 2009 | Computers & Internet

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