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2x2-3x+5=0 solving the quadratic equation - Computers & Internet

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Here you are :
2X2-3x+5=0 => 4-3x+5=0; (2X2=4) => -3x+9=0; (4+5=9) => 9 = 3x; (-3x moved to the right-hand side and it became 3x) => 9/3=x; (3 moved to the right hand side, so it becomes 1/3, i.e 1/3X9= 9/3) i.e. x=9/3 => x=3
Hence x equals to 3.

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Posted on Oct 08, 2010

  • Lebanon Raingam
    Lebanon Raingam Oct 08, 2010

    Repost.....................


    2X2-3x 5=0


    => 4-3x 5=0; (2X2=4)


    => -3x 9=0; (4 5=9)


    => 9 = 3x; (-3x moved to the right-hand side and it became 3x)


    => 9/3=x; (3 moved to the right hand side, so it becomes 1/3, i.e 1/3X9= 9/3)

    i.e. x=9/3


    => x=3


    Hence x equals to 3.

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2x^2-3x-5=0

Posted on Oct 08, 2012

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