Question about Mathsoft Solving and Optimization Extension Pack III (46513) for PC

MPT: MP=15: MT=22

SAD: SA=??: SD=2x10

Insufficient information to solve for X.

Posted on Oct 07, 2010

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Posted on Jan 02, 2017

A SSA does not prove congruent triangles. In most cases there are 2 possible triangles that can be made

Mar 30, 2017 | The Computers & Internet

If all sides are equal then 2x + 5 = 4x - 3

2x = 8

x = 4

so the perimeter is 3 times either expression above

3 * (8 + 5) = 39

.

2x = 8

x = 4

so the perimeter is 3 times either expression above

3 * (8 + 5) = 39

.

Jan 12, 2017 | The Computers & Internet

Three congruent angles means it is an equilateral triangle, so by definition it has 3 congruent sides. Or, by the Sine Rule of triangles

a/sinA = b/sinB = c/sinC

and since A = B = C (given) then a = b = c.

.

a/sinA = b/sinB = c/sinC

and since A = B = C (given) then a = b = c.

.

Apr 08, 2016 | Computers & Internet

It is a number of dots which can form an equilateral triangle when so arranged. So these numbers are 1 (trivial), 3, 6, 10, 15, 21, ....n(n+1)/2 where n is the n'th triangle number eg the 4th triangle number is 4(5)/2 = 10 as above

Apr 21, 2014 | Computers & Internet

Here is to get you started. To increase the size of the image do a CTRL Plus (+) in your browser.

You need to calculate the slant height of the pyramid for the formula of the lateral area. You should find a value of** (1/2)*SQRT(203) **or about 7.1239 cm

You need to calculate the altitude (height) of the pyramid from the apex (summit) to the center of the base triangle (center of inscribed circle, barycenter, orthocenter). The hypotenuse of such triangle is the slant height. One leg is the altitude (to be found),**the measure of the second leg is (1/3) the altitude** **of the equilateral triangle** that forms the base. You should find (1/3) m MH= (1/3)* **(11/2)*SQRT(3)**

1. Calculate the area of the base (use a formula for the equilateral triangle or the general formula for a triangle: you have its height MH ).

2. Lateral area = 3 times the area of triangle Triangle ECD (in yellow above).

3. Total area = area of base + lateral area.

4. Volume= (1/3)(Area of base)* (height of pyramid)

If you can see the details on the screen capture below, fine, Press CTRL + in your browser to increase the size.

You need to calculate the slant height of the pyramid for the formula of the lateral area. You should find a value of

You need to calculate the altitude (height) of the pyramid from the apex (summit) to the center of the base triangle (center of inscribed circle, barycenter, orthocenter). The hypotenuse of such triangle is the slant height. One leg is the altitude (to be found),

1. Calculate the area of the base (use a formula for the equilateral triangle or the general formula for a triangle: you have its height MH ).

2. Lateral area = 3 times the area of triangle Triangle ECD (in yellow above).

3. Total area = area of base + lateral area.

4. Volume= (1/3)(Area of base)* (height of pyramid)

If you can see the details on the screen capture below, fine, Press CTRL + in your browser to increase the size.

Mar 29, 2014 | Office Equipment & Supplies

-3x + 15 = 2x -10

-3x -2x = -10 -15

-5x = -25

x = -25/-5

x = 5

-3x -2x = -10 -15

-5x = -25

x = -25/-5

x = 5

Oct 18, 2011 | Office Equipment & Supplies

If we assume the width of the frame is X. Then the one dimension of the framed picture will be 2X + 20 and the other dimension of the picture will be 2X + 34. We know the total area of the framed picture should be 640 in^2. Therefore:

(2X + 10) * (2X + 34) = 640

If you multiply this out you get:

4X^2 + 88X + 340 = 640

Subtract 640 from both sides:

4X^2 + 88X - 300 = 0

Divide both sides by 4:

X^2 + 22X - 75 = 0

Use the quadratic equation to solve for X, with A=1, B=22, C=75

X = [-22 +/- sqr(22^2-4*(-75)] /2

This reduces to:

(-22 +/- 48) / 2

The negative solution doesn't make sense in this case. Therefore: X = (-22 + 28) /2 = 6/3 = 3

Therefore the width of the frame should be 3 inches.

(2X + 10) * (2X + 34) = 640

If you multiply this out you get:

4X^2 + 88X + 340 = 640

Subtract 640 from both sides:

4X^2 + 88X - 300 = 0

Divide both sides by 4:

X^2 + 22X - 75 = 0

Use the quadratic equation to solve for X, with A=1, B=22, C=75

X = [-22 +/- sqr(22^2-4*(-75)] /2

This reduces to:

(-22 +/- 48) / 2

The negative solution doesn't make sense in this case. Therefore: X = (-22 + 28) /2 = 6/3 = 3

Therefore the width of the frame should be 3 inches.

Feb 16, 2011 | SoftMath Algebrator - Algebra Homework...

125: Error

Error detected in MT home position.

1) is an Error Message displayed? Yes

Turn ON power again.

2)Does the Error take place again? yes

Replace MT

Error detected in MT home position.

1) is an Error Message displayed? Yes

Turn ON power again.

2)Does the Error take place again? yes

Replace MT

Oct 27, 2010 | Xante Ilumina Digital Color Press Printer

2 triangles are congruent when they have the same angles but different lengths.

May 31, 2010 | Mathsoft StudyWorks! Mathematics Deluxe...

That camera has a SD card slot. I would ignore the internal 16MB of memory and use a SD card. (512's are really cheap)

The SD card can then be removed and placed into a SD to USB reader. ($10-15 range) When you use one of these it makes the SD card into another disk drive -- so you can then just copy or move the files to your HD and do with then anything you would do with any other jpg or video file. You can also carry multiple SD's and have extra digital "film" available to take more pictures. You can also take these SD cards to just about any Wal-Mart, Walgreens, or CVS and make real prints for about .20 a piece.

The SD card can then be removed and placed into a SD to USB reader. ($10-15 range) When you use one of these it makes the SD card into another disk drive -- so you can then just copy or move the files to your HD and do with then anything you would do with any other jpg or video file. You can also carry multiple SD's and have extra digital "film" available to take more pictures. You can also take these SD cards to just about any Wal-Mart, Walgreens, or CVS and make real prints for about .20 a piece.

Jan 08, 2008 | Cameras

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