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Find three consecutive odd integers whose sum is 105

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If the product of two consecutive odd integers is decreased by 3, the result is 12. find the integers

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X + ( X + 2 ) + ( X + 4 ) = 105
3X + 6 = 105
3X = 105 - 6
3X = 99
X = 99/3
X = 33
So 33 + 35 + 37 = 105

Posted on Oct 06, 2010

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The Sum of 2 integers from 1 to 9 that are four consecutive numbers. Show that either one or three of the numbers on the counters were even


I need some help here. If we take the sum of 2 integers from 1 to 9, and they can be the same number, the maximum number is 18. I don't know how you are supposed to get four consecutive digits, unless you pad the number with zeros. Am I missing something?

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The numbers on three raffle tickets are consecutive integers whose sum is 7530. find the integers


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Find the smallest two consecutive even integers such that three times the smaller is at least 19 more than the sum of the two integers


Let x be the smallest number.
Let x + 2 be the other number (consecutive even integer)

Now to translate the rest;)
three times the smaller 3(x)
19 more -19
sum of the two integers - (x) +( x+2)

Pulling it together,
3x -19 = x + x +2
collect like terms
3x - 19 = 2x + 2
Put all the constants on one side by adding 19 to both sides.
3x - 19 +19= 2x + 2 + 19
3x = 2x +21
Subtract 2x from both sides to have all the x's on one side.
3x - 2x = 2x +21 - 2x
x = 21
The other number is 21 + 2, or 23
Check:three times the smaller = 3 x 21 = 63
sum of the two integers = 21 + 23 or 44
is 63 at least 19 more than 44






Feb 19, 2015 | Office Equipment & Supplies

1 Answer

Consecutive odd integers


83+85+87+89=344

Jul 05, 2014 | Plumbing

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Consecutive even integers


38.
The three numbers are 34, 36, and 38.

Jun 03, 2014 | Office Equipment & Supplies

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Consecutive even integers


The two numbers are 32 and 34. The rest is your homework, you do it.

Dec 19, 2013 | Office Equipment & Supplies

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What are the three consecutive integers whose sum is 378?


Let X be the lowest of the 3 integers
The sum of the 3 integers can be represented as X + (X+1) + (X+2).
Set this sum equal to 378 and solve for X.
X + (X+1) + (X+2) = 378
3X + 3 = 378
3X = 375
X = 125
Since X is the lowest of the 3 integers the other 2 will be X+1 and X+2 or 126 and 127.

Therefore, the answer is 125, 126 and 127

Aug 23, 2010 | SoftMath Algebrator - Algebra Homework...

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