Question about Mathsoft StudyWorks! Mathematics Deluxe 5.0 (11513) for PC

__Kervin:__

Since there are 7 days in each week, then multiply 28 by 7

28 weeks x 7 days =

196 days **(answer)**

Posted on Oct 05, 2010

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Posted on Jan 02, 2017

Date difference from Jan 11, 1944 to Jan 7, 2016 The total number of days between Tuesday, January 11th, 1944 and Thursday, January 7th, 2016 is **26,294 days**.

This is equal to**71 years, 11 months, and 27 days**.

This does not include the end date, so it's accurate if you're measuring your age in days, or the total days between the start and end date. But if you want the duration of an event that includes both the starting date and the ending date, then it would actually be 26,295 days.

If you're counting workdays or weekends, there are**18,782 weekdays** and **7,512 weekend days**.

If you include the end date of Jan 7, 2016 which is a Thursday, then there would be**18,783 weekdays** and **7,512 weekend days** including both the starting Tuesday and the ending Thursday.

26,294 days is equal to**3,756 weeks and 2 days**.

The total time span from 1944-01-11 to 2016-01-07 is 631,056 hours.

This is equivalent to 37,863,360 minutes.

You can also convert 26,294 days to 2,271,801,600 seconds.

Number of days between January 11th 1944 and January 7th 2016

This is equal to

This does not include the end date, so it's accurate if you're measuring your age in days, or the total days between the start and end date. But if you want the duration of an event that includes both the starting date and the ending date, then it would actually be 26,295 days.

If you're counting workdays or weekends, there are

If you include the end date of Jan 7, 2016 which is a Thursday, then there would be

26,294 days is equal to

The total time span from 1944-01-11 to 2016-01-07 is 631,056 hours.

This is equivalent to 37,863,360 minutes.

You can also convert 26,294 days to 2,271,801,600 seconds.

Number of days between January 11th 1944 and January 7th 2016

Jan 10, 2017 | Watches

First of all avoid setting the day and day of the week between 9.00 pm and 6.00 am. The day and day of the week may not change in the following day if you do.

Try this,

1) Pull the crown to the first click.

2) Set the day by rotating the crown counterclockwise.

3) Set the day of the week by rotating the crown clockwise.

4) Push the crown back to its normal position.

Hope this will help.

Cheers

Try this,

1) Pull the crown to the first click.

2) Set the day by rotating the crown counterclockwise.

3) Set the day of the week by rotating the crown clockwise.

4) Push the crown back to its normal position.

Hope this will help.

Cheers

May 16, 2016 | Casio Watches

Hey ,Mother's day is very special for everyone we know that, only two day left on mothers day.

You have only two days left to do something special for mom , Here you mentioned that you want give cookies and cake to your mom on this mothers day ,and it was an amazing ideas .

Here i will give you best Address to buy fresh and affordable cake .you can buy it from giftblooms ,it is online gift sore where you can buy 100+ different delicious cake .

Mother Day Cake Delivery Mother Day Cake Ideas

You have only two days left to do something special for mom , Here you mentioned that you want give cookies and cake to your mom on this mothers day ,and it was an amazing ideas .

Here i will give you best Address to buy fresh and affordable cake .you can buy it from giftblooms ,it is online gift sore where you can buy 100+ different delicious cake .

Mother Day Cake Delivery Mother Day Cake Ideas

Apr 22, 2016 | Baking

There are 24 hours in a day, 60 minutes in an hour, 60 seconds in a minute, so there are:

24 hours per day

24* 60 = 1,440 minutes per day

1440 * 60 = 86,400 seconds per day

13 days = 312 hours 0 minutes 0 seconds

or

13 days = 18,720 minutes 0 seconds

or

13 days = 1,123,200 seconds

24 hours per day

24* 60 = 1,440 minutes per day

1440 * 60 = 86,400 seconds per day

13 days = 312 hours 0 minutes 0 seconds

or

13 days = 18,720 minutes 0 seconds

or

13 days = 1,123,200 seconds

Jul 18, 2014 | Watches

#include <stdio.h>

#include <conio.h>

#include <math.h>

#include <iostream.h>

#include <fstream.h>

int getdaycode(int year)

{

return(year+(year-1)/4-(year-1)/100+(year-1)/400)%7;

}

int bool getleapcode(int year)

{

return year%4==0&&year%100!=0''year%400==0;

}

main()

{

clrscr();

int choice,month,days,day,daycode;

printf("\t\t\tSCHEDULER-CALENDAR PROGRAM\n\n\n");

printf("Please choosefrom the Menu:\n");

printf("\t1- Calendar Dislplay\n");

printf("\t2- Schedule Editor\n");

printf("\nChoice: ");

scanf("%d",&choice);

if(choice==1)

{

clrscr();

int year;

printf("\tCalendar Display\n\n");

printf("Type the YEAR to be Displayed: ");

scanf("%d",&year);

printf("\nYear = %d",year);

bool leapcode;

daycode=getdaycode(year);

leapcode=getleapcode(year);

for(month=1;month<=12;month++)

{

switch(month)

{

case 1:

{

printf("\nJanuary");

days=31;

}

break;

case 2:

{

printf("\n\nFebruary");

if(leapcode)

{

days=29;

}

else

{

days=28;

}

}

break;

case 3:

{

printf("\n\nMarch");

days=31;

}

break;

case 4:

{

printf("\n\nApril");

days=30;

}

break;

case 5:

{

printf("\n\nMay");

days=31;

}

break;

case 6:

{

printf("\n\nJune");

days=30;

}

break;

case 7:

{

printf("\n\nJuly");

days=31;

}

break;

case 8:

{

printf("\n\nAugust");

days=30;

}

break;

case 9:

{

printf("\n\nSeptember");

days=31;

}

break;

case 10:

{

printf("\n\nOctober");

days=30;

}

break;

case 11:

{

printf("\n\nNovember");

days=31;

}

break;

case 12:

{

printf("\n\nDecember");

days=30;

}

break;

}

printf("\n\nSun Mon Tue Wed Thu Fri Sat\n");

for(day=1;day<=daycode*5;day++)

{

printf(" ");

}

for(day=1;day<=days;day++)

{

printf(" %d ",day);

if((day+daycode)%7>0)

{

printf(" ");

}

daycode=(daycode+days)%7;

}

}

}

if(choice==2)

{

printf("Schedule Editor\n\n");

FILE *fptr1;

char filename1[]="sched.txt";

int reval=SUCCESS;

if((fptr1==fopen(filename1,"w"))

{

printf("File cannot be opened\n");

reval=FAIL;

}

else

{

CharReadWrite(fptr1);

fclose(fptr1);

}

int

getch();

return 0;

}

#include <conio.h>

#include <math.h>

#include <iostream.h>

#include <fstream.h>

int getdaycode(int year)

{

return(year+(year-1)/4-(year-1)/100+(year-1)/400)%7;

}

int bool getleapcode(int year)

{

return year%4==0&&year%100!=0''year%400==0;

}

main()

{

clrscr();

int choice,month,days,day,daycode;

printf("\t\t\tSCHEDULER-CALENDAR PROGRAM\n\n\n");

printf("Please choosefrom the Menu:\n");

printf("\t1- Calendar Dislplay\n");

printf("\t2- Schedule Editor\n");

printf("\nChoice: ");

scanf("%d",&choice);

if(choice==1)

{

clrscr();

int year;

printf("\tCalendar Display\n\n");

printf("Type the YEAR to be Displayed: ");

scanf("%d",&year);

printf("\nYear = %d",year);

bool leapcode;

daycode=getdaycode(year);

leapcode=getleapcode(year);

for(month=1;month<=12;month++)

{

switch(month)

{

case 1:

{

printf("\nJanuary");

days=31;

}

break;

case 2:

{

printf("\n\nFebruary");

if(leapcode)

{

days=29;

}

else

{

days=28;

}

}

break;

case 3:

{

printf("\n\nMarch");

days=31;

}

break;

case 4:

{

printf("\n\nApril");

days=30;

}

break;

case 5:

{

printf("\n\nMay");

days=31;

}

break;

case 6:

{

printf("\n\nJune");

days=30;

}

break;

case 7:

{

printf("\n\nJuly");

days=31;

}

break;

case 8:

{

printf("\n\nAugust");

days=30;

}

break;

case 9:

{

printf("\n\nSeptember");

days=31;

}

break;

case 10:

{

printf("\n\nOctober");

days=30;

}

break;

case 11:

{

printf("\n\nNovember");

days=31;

}

break;

case 12:

{

printf("\n\nDecember");

days=30;

}

break;

}

printf("\n\nSun Mon Tue Wed Thu Fri Sat\n");

for(day=1;day<=daycode*5;day++)

{

printf(" ");

}

for(day=1;day<=days;day++)

{

printf(" %d ",day);

if((day+daycode)%7>0)

{

printf(" ");

}

daycode=(daycode+days)%7;

}

}

}

if(choice==2)

{

printf("Schedule Editor\n\n");

FILE *fptr1;

char filename1[]="sched.txt";

int reval=SUCCESS;

if((fptr1==fopen(filename1,"w"))

{

printf("File cannot be opened\n");

reval=FAIL;

}

else

{

CharReadWrite(fptr1);

fclose(fptr1);

}

int

getch();

return 0;

}

Sep 07, 2011 | Computers & Internet

hi.

the trick with this is to work out how many people you could feed for 1 day.

6 people for 8 days will be (6x8) 48 people for 1 day.

divide by 12people to give 4 days food for 12 people.

hope this helps.

the trick with this is to work out how many people you could feed for 1 day.

6 people for 8 days will be (6x8) 48 people for 1 day.

divide by 12people to give 4 days food for 12 people.

hope this helps.

Jul 12, 2011 | Cycling

Apr 20, 2010 | JVC Everio GZ-MG30 Camcorder

Here is the answer:

Daisy did 2/5ths or %40 of the barn in those two days as she can do the whole lot in 5 days she did 2/5ths or %40 in 2 days so thats %40 of the barn done.

Didith did 2/8ths or %25 of the barn in those two days,

so the amount of barn painted in the first two days is: 1/4 + 2/5 which equals %65 of the barn complete in the first two days. so there is %35 of the barn left to paint and only Daisy (who can paint %20 of the barn in one day)

so to figure out how many days it takes Daisy to paint %35 of the barn this is what to do:

%20 = 1day %35 - %20 = %15 5x5x5x5 = 20 5x5x5 = 15 therefore it takes Daisy 1/4 of a day to paint %5 of the barn therefore it takes Daisy 3/4 of a day to paint %15 of the barn (i hope you are following me here!) 1 + 3/4 = one and three quarters of a day

Therefore it took Daisy one and three quarter days to paint the remaining %35 of the barn.

So it took Days one and three quarter days to finish the job after Didith left.

Hope this is helpful

Emmanuel

Daisy did 2/5ths or %40 of the barn in those two days as she can do the whole lot in 5 days she did 2/5ths or %40 in 2 days so thats %40 of the barn done.

Didith did 2/8ths or %25 of the barn in those two days,

so the amount of barn painted in the first two days is: 1/4 + 2/5 which equals %65 of the barn complete in the first two days. so there is %35 of the barn left to paint and only Daisy (who can paint %20 of the barn in one day)

so to figure out how many days it takes Daisy to paint %35 of the barn this is what to do:

%20 = 1day %35 - %20 = %15 5x5x5x5 = 20 5x5x5 = 15 therefore it takes Daisy 1/4 of a day to paint %5 of the barn therefore it takes Daisy 3/4 of a day to paint %15 of the barn (i hope you are following me here!) 1 + 3/4 = one and three quarters of a day

Therefore it took Daisy one and three quarter days to paint the remaining %35 of the barn.

So it took Days one and three quarter days to finish the job after Didith left.

Hope this is helpful

Emmanuel

Sep 17, 2008 | Computers & Internet

i am scared of putting to much force turning the crown

It is very hard or stiff ND CAN'T LIFT CROWN TO BR ABLE TO SET DATE AND TIME

It is very hard or stiff ND CAN'T LIFT CROWN TO BR ABLE TO SET DATE AND TIME

Nov 22, 2007 | Rolex Day-Date President 118238 Wristwatch

Nov 08, 2011 | Mathsoft StudyWorks! Mathematics Deluxe...

Jul 26, 2010 | Mathsoft StudyWorks! Mathematics Deluxe...

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