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The length of the rectangle is two less than three times the width. if the perimeter of the rectangle is 76 cm, find the dimensions of the rectangle.

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54cm

Posted on Oct 02, 2010

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The length, l, of a rectangle is 5/2 its width, w. The length, l, of the rectangle is 10 inches. What is the perimeter of the rectangle? What Iis the area of the rectangle, in sauare inches?


We are given the following data:

length = 5/2 * width
length = 10 inWe know through the transitive

property of equality that the following must be true:

5/2 * width = 10 in

We then solve this equation algebraically for width:

width = (10 in) * 2/5
width = 4 in

The perimeter of the rectangle is given by substituting our known values of length and width into the following general equation:

Perimeter = 2 * length + 2 * width
Perimeter = 2(10 in) + 2(4 in) = 28 in

In a similar fashion, we substitute these known values into the general equation for the area of the rectangle to solve for the same:

Area = length * width
Area = (10 in)(4 in)=40 in^2

Nov 29, 2016 | The Computers & Internet

1 Answer

The perimeter of a rectangle is 600 yards. what are the dimensions of the rectangle if the length is 20 yards more then the width


160 by 140

The perimeter is 600, so 2w+2l=600 where w is the width and l is the length.
Divide both sides by 2: w+l=300
The length is 20 more than the width: l=w+20
Substituting in the previous equation: w+(w+20)=300
Collecting terms: 2w+20=300
Subtract 20 from both sides: 2w=280
Divide by 2: w=140
Thus the width is 140. Substituting into the equation for length: l=140+20
Simplifying: l=160
The width is 140 and the length is 160

Sep 15, 2014 | MathAid Algebra II

2 Answers

How do you solve a rectangle is eight inches longer than its width. find the dimensions of the rectangle if the perimeter is 60 cm


The rectangle is 11cm by 19cm.

The perimeter is 60, so the width and length must add to 30. The length is 8 more than the width, or width+width+8=30. Solve that for width, then you can calculate the length based on the width.

If this is homework, be sure to show your work.

Oct 11, 2013 | Lands Phones

1 Answer

Please show all of the information and answers to: The plane was purchased new in 2006; therefore, x =0 represents the year 2006. X - Axis (horizontal) = years starting from 0 = 2006 and increasing b


Translate the English into Mathematics.
W=L-5 (in inches)
P=2(L+W)=2(L+L-5)=2(2L-5)
Use distirbutive property of multiplication with respect to addition to open up the parentheses (brackets)
P=4L-10.
Set P= 50 (inches), to get 4L-10=50
Solve for L: Do it'!
Find W= L (the one you just found) -5 =

Now, with W the value you just calculated
the new length is L'=-4+3W
and the new perimeter is P'=2(L'+W)

Now your turn to do some work.

Jan 02, 2012 | Office Equipment & Supplies

1 Answer

Area of rectangle is 4122cm2 .width of rectangle is 3cm.how do i find the length of it


Area = length X width, and you know the area and the width. So,

4122 sq cm = length X 3 cm

length = 4122 sq cm / 3 cm

length = 1374 cm

(That is one long, skinny rectangle, isn't it?)

Mar 02, 2011 | Office Equipment & Supplies

1 Answer

A rectan Dear Madam Please look at the math questions below. Please help me solve the questions Question 1 : A rectangular tablecloth is 2.5 m long. Trim is to be sewn around the perimeter of the cloth...


1. Well this one is pretty simple. Since you are not supposed to trim the length trim the width instead.
to make the perimeter 0.4 m shorter cut the cloth by 0.2 m width the picture will make it clear.
champ_guru.jpg


2. let the length of rectangle be x cm
and breadth = 20 cm
now original perimeter = 2(x+20) cm


new length = x-30 cm
breadth remains same = 20 cm
new perimeter = 2(x-30+20) cm = 2(x-10) cm

According to question

new perimeter = old perimeter /2
2(x-10) = 2(x+20) /2
2x -20 = x + 20
x = 40 cm


hence length of longer side 40 cm.

If you want to directly comm ankitsharma.220@gmail.com

Feb 13, 2011 | Vivendi Excel@ Mathematics Study Skills...

1 Answer

Inst manual


The length of a rectangle is twice its width w. a second rectangle, which is 8 cm longer and 3 cm narrower than the first rectangle, has perimeter 154 cm. Make a sketch of the rectangles expressing all dimensions of w. Then find the dimensions of each rectangle.

Oct 03, 2008 | Texas Instruments BA Real Estate...

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