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I am a number rounding me to the nearest thousand makes me a 1000.All my digits are even their sum is 12 they are in order from greatest to least and no digit is repeated what number am I

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  • Anonymous Mar 18, 2014

    if the digits may repeat?

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642.
They are all even numbers and they are all in order from greatest to lease. Their sum must add up to 12 also. so 6 +4 +2 = 12.
If you round it to the nearest 1000 you get 642.
Take each thing they are saying as 1 of your rules to get the number. And use that to eliminate numbers for example. 1 3 5 7 are all eliminated. then use numbers to get to 12 that must be even. Finally make sure they are from greatest to least.

Posted on Jun 15, 2011

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SOURCE: I am a number rounding me to the nearest thousand

642.
They are all even numbers and they are all in order from greatest to lease. Their sum must add up to 12 also. so 6 +4 +2 = 12.
If you round it to the nearest 1000 you get 642.
Take each thing they are saying as 1 of your rules to get the number. And use that to eliminate numbers for example. 1 3 5 7 are all eliminated. then use numbers to get to 12 that must be even. Finally make sure they are from greatest to least.

Posted on Jun 15, 2011

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I am a number rounding me to the nearest thousand makes me a 1000.All my digits are even their sum is 12 they are in order from greatest to least and no digit is repeated what number am I ?


642.
They are all even numbers and they are all in order from greatest to lease. Their sum must add up to 12 also. so 6 +4 +2 = 12.
If you round it to the nearest 1000 you get 642.
Take each thing they are saying as 1 of your rules to get the number. And use that to eliminate numbers for example. 1 3 5 7 are all eliminated. then use numbers to get to 12 that must be even. Finally make sure they are from greatest to least.

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