Question about Super Tutor Trigonometry (ESDTRIG) for PC

1/sin-sin

1-(sin*sin)/sin

(cos*cos)/sin

Posted on Sep 02, 2008

Cos^tan^=sin^

Posted on Aug 12, 2008

How to determine the area of a triagle abc, if a=110mm, b=80mm and c=120degrees

Posted on Jul 16, 2008

Change csc to 1/sin. Find a common denominator and add the two left terms.

1/sin - sin = (1 -sin^2)/sin. Rewrite formula

(1 - sin^2)/sin = cos^2/sin Divide out the /sin.

1 - sin^2 = cos^2 Rearange.

1 = cos^2 + sin^2 Yes, that's true. It's like the Pythagorean formula.

Posted on Jun 13, 2008

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Posted on Jan 02, 2017

Sorry I do not like to work with secant and cosecant.

sec(a)+tan(a)=(1+sin(a))/cos(a)

ln(sec(a)+tan(a))=** ln( (1+sin(a))/cos(a))=X**

2*cosh(X)= e^(X)+e^(-X)

**e^(X)=(1+sin(a))/cos(a)**

**e^(-X)= cos(a)/(1+sin(a))**

2cosh(X)=(1+sin(a))/cos(a) +cos(a)/(1+sin(a))= 2/cos(a)

**cosh(X)=1/cos(a)=sec(a)**

Now that you see how you can do it, I trust you will discover any mistake I might have made.

If you want to use the classPad function sequence**Action>Transformation>simplify(,** do it step by step as I have detailed above.

Good Luck.

sec(a)+tan(a)=(1+sin(a))/cos(a)

ln(sec(a)+tan(a))=

2*cosh(X)= e^(X)+e^(-X)

2cosh(X)=(1+sin(a))/cos(a) +cos(a)/(1+sin(a))= 2/cos(a)

Now that you see how you can do it, I trust you will discover any mistake I might have made.

If you want to use the classPad function sequence

Good Luck.

Dec 07, 2013 | Casio ClassPad 300 Calculator

SEC, CSC & COT are the INVERSE of COS, SIN & TAN and are usually require hitting the "2nd F" or "Func" key of the calc to make:

SIN button work as COSEC,

COS button work as SEC

TAN button work as COT

Formulas are below:

sec x = __1 __

cos x

cosec x = __ 1
__

sin x

cot x = __ 1 __ = __cos x__

tan x sin x

Good luck!

Feb 05, 2013 | Sharp EL531 Scientific Calculator

No calculator can have EVERY mathematical function. Very few calculators have the secondary trig functions like cosecant because they're so simple to calculate in other ways. By definition csc(x) is equal to 1/sin(x) and you can calculate it that way. Similarly, calculate sec(x) as 1/cos(x) and cot(x) as 1/tan(x).

Jun 04, 2012 | Texas Instruments TI-36X Scientific...

cos(5PI)=cos(4PI+PI)=cos(PI)=-1

sin(19PI/6)=sin(18PI/6+ PI/6)=sin(3PI +Pi/6)=sin(2PI+PI+PI/6)=sin(PI+PI/6)=sin(-PI/6)=-sin(PI/6)=-1/2

sin(19PI/6)=sin(18PI/6+ PI/6)=sin(3PI +Pi/6)=sin(2PI+PI+PI/6)=sin(PI+PI/6)=sin(-PI/6)=-sin(PI/6)=-1/2

Dec 12, 2011 | Super Tutor Trigonometry (ESDTRIG) for PC

There are no keys for cosecant, secant, and cotangent. You can calculate those ratios as

csc(x) = 1/sin(x)

sec(x) = 1/cos(x)

cot(x) = 1/tan(x)

Simply calculate the trig ratio on the right and then take its reciprocal.

csc(x) = 1/sin(x)

sec(x) = 1/cos(x)

cot(x) = 1/tan(x)

Simply calculate the trig ratio on the right and then take its reciprocal.

Dec 14, 2010 | Texas Instruments TI-83 Plus Calculator

By definition

On this calculator, you have two ways to calculate one of these functions. EX cosecant of 37 degrees

- cosecant of X =1/sin(X), must not be confused with arc sine [sin^-1]
- secant of X =1/cos(X), must not be confused with arc cosine [cos^-1]
- cotangent of X =1/tan(X), must not be confused with arc tangent [tan^-1]

On this calculator, you have two ways to calculate one of these functions. EX cosecant of 37 degrees

- You enter 1 / [sin] 37 [ ) ] [ENTER] result is 1.661640141
- You enter [sin] [ ) ] 37 [ENTER] followed by [X^-1] to take the reciprocal of the previous answer. The [X^-1] key is the one just below [MATH].

Jan 21, 2010 | Texas Instruments TI-84 Plus Calculator

Hello,

You have 3 keys for the main trigonometric functions: [SIN], [COS] and [TAN]

To use them correctly you must set the angle unit to the one your problem calls for.

Press [SIFT][MODE] [3:Deg] for degree, [4:Rad] for radian, [5:Grad] for grad. Dependig on angle unit chosen a small D, R, or G appears on the top of the screen.

If you need the inverse trigonometric functions arcsine, arccosine, arctangent, you access them by first pressing the [SHIFT] key

Thus

arcsine [SHIFT][SIN] (sin^-1)

arcosine [SHIFT][COS] (cos^-1)

arctangent [SHIFT][TAN] (tan^-1)

The syntax for the function is

[SIN] # [ ) ] [=]; [SIN] 30 [ ) ] [=] gives 0.5

[COS] # [ ) ] [=] [COS] 19 [ ) ] [=] gives 0.945518576

Note: if the argument of the functions are numbers, the right parenthesis is not necessary. But if the argument is an expression (with various operations) better put the parenthesis to make sure the calculator is performing as one wants it to.

By the way, there are no keys, or key combinations to calculate cotangent, cosecant, and secant, but you can use the definitions:

**cotangent (x) = 1/tan(x) Do not confuse it with tan^-1**

**cosecant(x) = 1/sin(x) Do not confuse it with sin^-1**

**secant(x) = 1/cos(x) Do not confuse it with cos^-1**

Hope it helps.

You have 3 keys for the main trigonometric functions: [SIN], [COS] and [TAN]

To use them correctly you must set the angle unit to the one your problem calls for.

Press [SIFT][MODE] [3:Deg] for degree, [4:Rad] for radian, [5:Grad] for grad. Dependig on angle unit chosen a small D, R, or G appears on the top of the screen.

If you need the inverse trigonometric functions arcsine, arccosine, arctangent, you access them by first pressing the [SHIFT] key

Thus

arcsine [SHIFT][SIN] (sin^-1)

arcosine [SHIFT][COS] (cos^-1)

arctangent [SHIFT][TAN] (tan^-1)

The syntax for the function is

[SIN] # [ ) ] [=]; [SIN] 30 [ ) ] [=] gives 0.5

[COS] # [ ) ] [=] [COS] 19 [ ) ] [=] gives 0.945518576

Note: if the argument of the functions are numbers, the right parenthesis is not necessary. But if the argument is an expression (with various operations) better put the parenthesis to make sure the calculator is performing as one wants it to.

By the way, there are no keys, or key combinations to calculate cotangent, cosecant, and secant, but you can use the definitions:

Hope it helps.

Oct 30, 2009 | Casio fx-300ES Calculator

I shall attempt :D

1) cosec A + cot A = 3

we know that (cot A)^2 + 1 = (cosec A)^2

Hence, (cosec A)^2 - (cot A)^2 = 1

thus, (cosec A + cot A) (cosec A - cot A) = 1

3 (cosec A - cot A) = 1

(cosec A - cot A) = 1/3

(cosec A - cot A) = 1/3

(cosec A + cot A) = 3

Summing them, 2 cosec A = 3 1/3

cosec A = 6 2/3 = 5/3

sin A = 0.15

Thus, cos A = sqrt (1 - (sin A)^2) = 0.989

2) Prove that (1+tan x - sec x)(1 + cot x + cosec x) =2

expand

LHS= 1 + cot x + cosec x + tan x + 1 + tan x cosec x - sec x - sec x cot x - sec x cosec x

We can calculate that

tan x cosec x = sec x (since tan x = sin x / cos x)

sec x cot x = cosec x

so the above is

LHS = 1 + cot x + cosec x + tan x + 1 + sec x - sec x - cosec x - sec x cosec x

LHS = 2 + cot x + tan x - sec x cosec x

LHS = 2 + cos x / sin x + sin x / cos x - 1 / (sin x cos x)

LHS = 2 + [{cos x}^2 + {sin x}^2 - 1] / (sin x cos x)

LHS = 2 (proved)

1) cosec A + cot A = 3

we know that (cot A)^2 + 1 = (cosec A)^2

Hence, (cosec A)^2 - (cot A)^2 = 1

thus, (cosec A + cot A) (cosec A - cot A) = 1

3 (cosec A - cot A) = 1

(cosec A - cot A) = 1/3

(cosec A - cot A) = 1/3

(cosec A + cot A) = 3

Summing them, 2 cosec A = 3 1/3

cosec A = 6 2/3 = 5/3

sin A = 0.15

Thus, cos A = sqrt (1 - (sin A)^2) = 0.989

2) Prove that (1+tan x - sec x)(1 + cot x + cosec x) =2

expand

LHS= 1 + cot x + cosec x + tan x + 1 + tan x cosec x - sec x - sec x cot x - sec x cosec x

We can calculate that

tan x cosec x = sec x (since tan x = sin x / cos x)

sec x cot x = cosec x

so the above is

LHS = 1 + cot x + cosec x + tan x + 1 + sec x - sec x - cosec x - sec x cosec x

LHS = 2 + cot x + tan x - sec x cosec x

LHS = 2 + cos x / sin x + sin x / cos x - 1 / (sin x cos x)

LHS = 2 + [{cos x}^2 + {sin x}^2 - 1] / (sin x cos x)

LHS = 2 (proved)

May 12, 2009 | ValuSoft Bible Collection (10281) for PC

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Oct 07, 2008 | Computers & Internet

if the sides of a triangle are 15cm ,16cm, and 17 cm ,then the area of the triangle is what ?

May 09, 2008 | Texas Instruments TI-30XA Calculator

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what are the primary operations used in trigonometry?was it like in geometry and advanced algebra?

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