Question about Sony Ericsson K800i Cellular Phone

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Please solve pls find the value of x in the equation 100x^4+361x^3+424r^2+110r-73=0

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You cant coz there are two variables (i.e 'x' and 'r')

Posted on Oct 15, 2008

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6ya6ya
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Posted on Jan 02, 2017

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How to predict using linear model


If you have the equation of the line (of best fit), enter a value of x in the equation to get the value of y. Similarly, if you have a target value of y, enter it in the equation and solve for the value of x. That's about it.

Jun 06, 2014 | Casio FX-9750GII Graphing Calculator

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What ia the sulution of 3y-6x=-3


To find the solution, first find the value of y for each equation.
Then substitue one equation into the other so that you only the x variable left.
Then just solve for x.
Once you have a value for x, then you can easily solve for y.


So for the first equation:

3y - 6x = -3
3y = 6x - 3

y = 2x - 1


Now for the second equation:

2y + 8x = 10
2y = -8x + 10

y = -4x + 5

Since both equations equal y, they also equal each other, therefore:

2x - 1 = -4x + 5

Now just solve for x:

2x + 4x = 5 + 1
6x = 6

x=1

Now substitute x=1 into either original equation:

y = 2x - 1
y = 2 (1) - 1
y = 2 - 1

y = 1


Therefore the solution is x=1 and y=1



Good luck, I hope that helps.


Joe.

Nov 09, 2011 | Texas Instruments TI-84 Plus Silver...

2 Answers

Input in standard form the equation of the given line. The line that passes through (1,5) and (-2,3)


You are looking for a line (y=m*x+b) and have two points. From this information you can generate two equations with two unknowns (m and b are unknown).
First plug in the first point (1,5) to the general form:
5(the y value of the point) = m*1(the x-value at this point)+b
Do the same for the second point you're given.
From here solve the first equation for m in terms of b.
Plug this value of 'm' into the second equation so you will end up with something like:
3=(something in terms of b)*(-2)+b
This final equation can be solved for b (try factoring)
You now have a value for the y-intercept. Plug that into y=m*x+b
Choose either of the two points, plug into the equation on the last line with the value of b known
You then know y, x, and b and have m as the remaining 1 unknown. Solve for that and put it all together for your final answer.

Apr 23, 2011 | Texas Instruments TI-83 Plus Calculator

1 Answer

Need help with fx - 991 ms to solve f(x)=100x-64*x^2+48*x^3 for different value of x


I am not quite sure what you mean by ``solve f(x)=100x-64*x^2+48*x^3 for different value of x``. Do you want to find the roots of the cubic equation 0=100x-64*x^2+48*x^3 , or do you want to generate values of f(x) for different values of the variable x.
For the first case, use the SOLVE program,
for the second, use the TABLE computational mode: Press MODE and select TABLE, then enter the expression to the right of the equal sign. In TABLE, X is the default variable.

Apr 12, 2011 | Casio FX-115ES Scientific Calculator

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I am trying to solve a quadratic function using the calculator but i dont seem to be able to do so. For example if i had a question like 5x^2 + 15x +3, how would i use the sharp el-w535 to find the x...


This expression 5x^2+15x+3 is not an equation, therefore it can have any value depending on the value of x. You have to make it an equation before looking for the particular value of x that satisfy your equation 5x^2+15x+3 =0

This calculator cannot solve equations because it does not have an equation solver.

Dec 15, 2010 | Sharp ELW535 Calculator

1 Answer

How to input cos x=0.75?


I assume that if you want to input the equation it is with the intent to solve it. If that be the case then what follows will help you input and solve any equation (linear, quadratic, trig, etc.)

Make sure the calculator angle unit is the same as your problem requires (degree, radian, grad). Here are some screen capture to help you. Change the equation to yours. 21c8779.jpg4b6c1ea.jpg
To enter the equation in screen above, use the right arrow.

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You have to enter an initial guess on line X=, a default value may be supplied by calculator: It depends on last value stored in X. Once a value is entered press the F6 key to SOLV
a5b0f3e.jpg
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Press F1: Rept if you want to solve another equation.

Nov 13, 2010 | Casio FX-9860G Graphic Calculator

1 Answer

A carpenter was contracted to repair a kitchen for $18000, the work took him 6 hours more than he has estimated and as a consequence, he earned $100 per hour less than he had estimated. how many hours had...


I will try to solve it systematically so it will be easier to understand. Note: The solution involves solving a quadratic equation.

Let amount of hours estimated be x:

Expected rate: $18000/(x hours)

Time spent extra: 6 hours.

Totals hours spent: (x + 6) hours

New rate: $18000/(x+6 hours)

Now:

18000/(x+6) x

The new rate is less than old rate by $100, therefore we can make the above inequality equality by adding $100 to the new rate.

18000/(x+6) + 100 = 18000/x

Solve by cross multiplaction:

(18000 + 100(x+6) * x = 18000 * (x+6)

18000x + 100x(x+6) = 18000x + 108000

Simplify:

100x(x+6) = 108000 (cancel 18000x on both sides)

x(x+6) = 1080 (divide by 100)

x^2 + 6x - 1080 = 0

Solve the above quadratic equation by any method (completing square, factorization or quadratic formula)

x = (-b+-(b^2 - 4ac)^.5)/2a where a = 1; b = 6; c = -1080

x = 30 or -36 (hours cannot be negative so disregard this result)

Therefore x = Estimated time = 30 hours

Check:

18000/30 = $600 per hour x+6 = 36 $18000/36 = $500 or $100 per hour less than estimated

Nov 12, 2010 | Office Equipment & Supplies

2 Answers

How do you enter the equation 4(5x+3)=2(7x+6) in the calculator?


http://support.casio.com/pdf/004/fx-115ES_991ES_Eng.pdf
Refer to page 12 of the manual under Inputting expressions and values. It is pretty straight forward if you need further assistance please let me know.
Thank you,
Lee

Nov 17, 2009 | Casio FX-115ES Scientific Calculator

2 Answers

Help please


Volume 1 x .4 + Volume 2 x .75 = 70 mL x .5

Volume 2 = 70 - Volume 1

V1 x .4 + (70-V1) x .75 = 70 mL x .5

solve for V1

Sep 30, 2009 | SoftMath Algebrator - Algebra Homework...

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