Question about Texas Instruments TI-30XA Calculator
For common antilogarithm use 2nd [10^x]. For natural antilogarithm use 2nd [e^x]. Those are the shifted functions of the two logarithm keys.
These two functions operate on the expression already entered into the calculator.
Example: to calculate the natural antilogarithm of .7:
. 7 2nd [e^x] =
Posted on Sep 16, 2010
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Posted on Jan 02, 2017
SOURCE: How to use antilog?
As you well know the pH is the negative of the log in base 10 of the H+/H3O+ ion concentration. If we use [H+] to represent that concentration, then pH=-log[H+].
To obtain the [H+] you need to calculate the antilog. You write the definition in the form log[H+] =-pH and then calculate 10 to the power of each member. The equality remains valid as both members are treated similarly. Thus
10^( log[H+] ) = 10^(-pH)
Since raising 10 to a power is the inverse function of taking the log in base 10, 10^(log(x))=log(10^(x)) = x (they are inverse of one another), you are left with
Your calculator has a function [10 to x] accessed by pressing the [2nd] function key. To use it you must enter the negative value of the pH, press the [2nd] function key then the [10 to x], then the = key to get the result (concentration)
Exemple: let the pH=5.5, what is the H+ concentration?
With [(-)] being the change sign key, then
[H+]:[ (-) ] 5.5 [2nd][10 to x] [=]
The result is 0.000003162 or 3.16 x 10^(-6)
Hope it helps.
Posted on Dec 10, 2009
SOURCE: antilog in chemistry problem
pH is minus (log to base 10) of the hydrogen ion activity of an aqueous solution, or (log to base 10) of (1/hydrogen ion activity)
To get the inverse log, i.e the hydrogen ion activity corresponding to a specified pH, simply enter the pH value and press
Posted on Jan 01, 2009
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