Question about Texas Instruments TI-89 Calculator

Ad

Unfortunately, TI-89s are not very good at infinite series. You're better off using something more powerful like Matlab or Mathematica. Sorry!

Posted on Oct 04, 2009

Ad

Hi,

A 6ya expert can help you resolve that issue over the phone in a minute or two.

Best thing about this new service is that you are never placed on hold and get to talk to real repairmen in the US.

The service is completely free and covers almost anything you can think of (from cars to computers, handyman, and even drones).

click here to download the app (for users in the US for now) and get all the help you need.

Good luck!

Posted on Jan 02, 2017

Ad

The fx-991ES does not do indefinite integrals.

For definite integrals, use the [integral] key just below and left of the big round cursor pad. For example, to calculate the definite integral of x^2 dx from 0 to 1, press [integral] [alpha] [X] [cursor-right] [0] [cursor-right] [1] [=]. After about a second you should see 1/3.

For definite integrals, use the [integral] key just below and left of the big round cursor pad. For example, to calculate the definite integral of x^2 dx from 0 to 1, press [integral] [alpha] [X] [cursor-right] [0] [cursor-right] [1] [=]. After about a second you should see 1/3.

Dec 20, 2014 | Casio Office Equipment & Supplies

You can calculate first derivatives of some functions at given points; you can calculate definite integrals over a given interval, but you cannot solve differential equations.

Aug 10, 2014 | Office Equipment & Supplies

I'm not sure of the question, but to plot arccos set mode to: graph='function' and angle to 'degrees' (for example). Go to WINDOW and set xmin=-1, xmax=1, xscl=0.1, ymin=0, ymax=180, yscl=50, and xres=1. Press GRAPH. You will get a plot of arccos from -1 to 1.

Mar 31, 2014 | Texas Instruments TI-89 Calculator

4/sqroot2 is the same value as 2sqroot2, about 2.828 . It's just a matter of how the calculator and the textbook chooses to represent the value.

Dec 30, 2012 | Office Equipment & Supplies

The key sequence [2nd] [Cos] calls the function arcosine or cos^-1. However that function takes its values in the range of the cosine function which is the interval [-1,1].

As you can see, your value of 1301.16 is clearly outside the interval [-1,1].

As you can see, your value of 1301.16 is clearly outside the interval [-1,1].

Dec 15, 2010 | Texas Instruments TI-84 Plus Calculator

Press the relevant function key [SIN],[COS],[TAN] followed by the angle value.

For inverse trigonometric functions [SIN^-1], COS^-1], or [TAN^-1], Press [SHIFT][SIN], [SHIFT][COS], or [SHIFT][TAN].

For other functions

sec(x)=1/cos(x)

csc(x)=1/sin(x)

cot(x)=1/tan(x)

When calculating trigonometric functions one must make sure that the angle unit the calculator is using is the correct one.

For inverse trigonometric functions [SIN^-1], COS^-1], or [TAN^-1], Press [SHIFT][SIN], [SHIFT][COS], or [SHIFT][TAN].

For other functions

sec(x)=1/cos(x)

csc(x)=1/sin(x)

cot(x)=1/tan(x)

When calculating trigonometric functions one must make sure that the angle unit the calculator is using is the correct one.

Aug 26, 2010 | Casio FX-115ES Scientific Calculator

You are indeed committing an error. The sequence [2nd][COS] is activating the function arcosine or arccos or cos^-1, the inverse of the cosine function. If you remember the properties of the cosine functions, you know that cos(x) is defined over the real line ]- infinity to infinity[, but its range spans the interval [-1,1].

Since the arcosine function is the inverse of the cosine, its domain of definition is the range of the cosine, namely the closed interval [-1,1].

Thus if you enter [2nd][COS][3180.04] the calculator flags this as a domain error, because 3180.04 is outside the interval [-1,1]

Restrict the argument of cos^-1 to any value inside the closed interval [-1,1].

When manipulating the trigonometric functions and their inverses you must keep in mind that the results you get are dependent on the angle unit your calculator is configured for (deg, rad).

Since the arcosine function is the inverse of the cosine, its domain of definition is the range of the cosine, namely the closed interval [-1,1].

Thus if you enter [2nd][COS][3180.04] the calculator flags this as a domain error, because 3180.04 is outside the interval [-1,1]

Restrict the argument of cos^-1 to any value inside the closed interval [-1,1].

When manipulating the trigonometric functions and their inverses you must keep in mind that the results you get are dependent on the angle unit your calculator is configured for (deg, rad).

Jun 29, 2010 | Texas Instruments TI-84 Plus Calculator

If you were trying to find the roots (zeros) of an algebraic equation
with the solve( command or the interactive solver you might have
supplied an interval where the function is always positive or always
negative. If the expression is always of the same sign on an interval,
the interval does not contain a root.

- If you extend the interval, the procedure may not converge fast enough and the calculator may not find the solution.
- Abetter way to do it is to sketch the graph of the function and use the graph to choose a reasonable interval that extends on both sides of the root, and a better initial guess.

- You attempted to calculate the I% variable when FV, N*PMT, and PV are all positive, or all negative.
- You tried to calculate Irr( when neither CFlist, nor CFO is positive
- You tried to calculate Irr( when neither CFlist,
nor CFO is negative

Jun 19, 2010 | Texas Instruments TI-84 Plus Silver...

To make things easy for the persons who would venture to help you, you should try to supply more information concerning what you are trying to do. We cannot always read people's mind.

If you were trying to find the roots (zeros) of an algebraic equation with the solve( command or the interactive solver you might have supplied an interval where the function is always positive or laways negative. If the expression is always of the same sign on an interval, the interval does not contain a root.

If you were trying to find the roots (zeros) of an algebraic equation with the solve( command or the interactive solver you might have supplied an interval where the function is always positive or laways negative. If the expression is always of the same sign on an interval, the interval does not contain a root.

- If you extend the interval, the procedure may not converge fast enough and the calculator may not find the solution.
- Abetter way to do it is to sketch the graph of the function and use the graph to choose a reasonable interval that extends on both sides of the root, and a better initial guess.

- You attempted to calculate the I% variable when FV, N*PMT, and PV are all positive, or all negative.
- You tried to calculate Irr( when neither CFlist, nor CFO is positive
- You tried to calculate Irr( when neither CFlist, nor CFO is negative

Feb 14, 2010 | Texas Instruments TI-84 Plus Silver...

Here's how in 4 easy steps (I substituted "A" for "X", my more favorite variable.):

1.) Set calculator to "Degree"

2.) Given-- (cos( X))

3.) Given--(4.37/7.25)==> (437/725)

4.) Add--(cos( X)+ (437/725)

1.) Set calculator to "Degree"

2.) Given-- (cos( X))

3.) Given--(4.37/7.25)==> (437/725)

4.) Add--(cos( X)+ (437/725)

Apr 15, 2009 | Texas Instruments TI-83 Plus Calculator

529 people viewed this question

Usually answered in minutes!

×