Question about Lufkin C213C 600" x 38" Long Consecutive Inch Chrome Clad Tape

Find three consecutive even integers if five times the second integer is 10 less than six times the first integer.?

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Posted on Sep 15, 2010

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The integers of the numbers on three raffle tickets are consecutive integers whose sum is 7,530 are 2509, 2510, and 2511.

Feb 24, 2015 | SoftMath Algebrator - Algebra Homework...

Find the smallest two consecutive even integers such that three times the smaller is at least 19 more than the sum of the two integers

Let x be the smallest number.
Let x + 2 be the other number (consecutive even integer)

Now to translate the rest;)
three times the smaller 3(x)
19 more -19
sum of the two integers - (x) +( x+2)

Pulling it together,
3x -19 = x + x +2
collect like terms
3x - 19 = 2x + 2
Put all the constants on one side by adding 19 to both sides.
3x - 19 +19= 2x + 2 + 19
3x = 2x +21
Subtract 2x from both sides to have all the x's on one side.
3x - 2x = 2x +21 - 2x
x = 21
The other number is 21 + 2, or 23
Check:three times the smaller = 3 x 21 = 63
sum of the two integers = 21 + 23 or 44
is 63 at least 19 more than 44

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There are three consecutive integers.nine times

52, 53, 54
If this is homework, be sure to show your work.

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Consecutive even integers

38.
The three numbers are 34, 36, and 38.

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Find two consecutive even integers such that twice the smaller exceeds the larger by 18.

Let x be first (smaller) integer and y second (larger) integer.
1. They are consecutive (and even) : y=x+2
2. Twice the smaller exceeds the larger by 18: 2*x=y+18
3. Substitute first equation into second: 2x=x+2+18
4. 2x-x=2+18
5. x=20
6. y=x+2=22

These two numbers are 20 and 22.

Oct 03, 2011 | Office Equipment & Supplies

Two consecutive even integers such that the smaller added to three times the larger gives a sum of 22

We'll call x the smaller integer and y the larger. So we know x+3y=22. We can rearrange this to say:
x=22-3y. Now we guess, I'll guess y=6, now we solve and get x=22-3(6)=4. 4 and 6 are two even consecutive integers! So the answer is 4 and 6.

Sep 15, 2011 | Texas Instruments TI-84 Plus Calculator

The smallest of 3 consecutive odd integers is added to twice the largest, giving a result 24 less than 5 times the middle. Find the integers

Let x be the smallest integer, then x+2 is the middle and x+4 the largest one. Resolve the equation

x + 2 * ( x + 4 ) = 5 * ( x + 2 ) - 24
=> x = 11

The three numbers are therefore 11, 13, and 15. The fact they are odd is irrelevant for finding the answer.

Jan 17, 2011 | Texas Instruments TI-84 Plus Calculator

Find three consecutive odd integers whose sum is 105

X + ( X + 2 ) + ( X + 4 ) = 105
3X + 6 = 105
3X = 105 - 6
3X = 99
X = 99/3
X = 33
So 33 + 35 + 37 = 105

Oct 06, 2010 | American Standard Plumbing

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