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The combined ages of reena and seena are 44years and reena is twice as old as seena was when reena was half as old as seena will be when seena is three times as old as reena was when reena was when three times as old as seena how old is reena???????? must question!!!!!!!!!

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6ya6ya
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Posted on Jan 02, 2017

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SOURCE: four years ago allan was three less than twice

Allan is 19 and Roy is 13.

Solution:

First we have 2 variables, their ages: I used Allan = x & Roy = y
Equation 1: X - 4 = 2*(Y-4) - 3
We can ignore the 5 years in the second part of the statement. Allan will always be 6 years older than Roy whether it be 5 years from now or ten years form now.
Equation 2: X = Y + 6

Substitute Y + 6 for X in equation 1:
X - 4 = 2*(Y-4) - 3 becomes Y + 6 - 4 = 2*(Y-4) - 3
That simplifies to Y + 2 = 2Y - 8 - 3
Rewrite it again: Y + 2 = 2Y - 11
Add 11 to both sides: Y + 13 = 2Y
Subtract Y from both sides: 13 = Y

Now plug 13 in for y in Equation 2
X = Y + 6
X = 13 + 6
X = 19

Posted on Oct 09, 2009

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SOURCE: one year ago pandit was three times his sister's

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Posted on Dec 24, 2010

SOURCE: Father is 3 times as

So the father is 3 times as old as his daughter.
Let F represent the age of the fatherLet D represet the age of the daughter
So we know from the first sentence,
F = 3 * D
From the second sentence, 12 years from now the father is 1 year les than twice his daughters age,
First, lets assume it's not 12 years from now (to avoid confusion), we would haveF + 1= 2 * D
But since its 12 years from now, we have to add 12 to both ages
(F + 12) + 1 = 2 * (D + 12)
Let's simplify a bit,

F + 13 = 2 * D + 24F = 2D + 11
Now we have to solve these two equations together, we can plug the first equation into the second,
F = 3 * DF = 2 * D + 11
3 * D = 2 * D + 11D = 11
So the daughter is 11 years old, we can find out how old the father is by plugging into the first equation
F = 3 * DF = 3 * 11F = 33
So the father is 33 and the daughter is 11.

Posted on Jul 19, 2011

  • 68 Answers

SOURCE: Jan is twice as old

Jan is 48 years old and Jake is 24 years old.
(Jan - N, Jake - K N=2K N+K=5K-48 N+K+48=5K N+48=4K N+48=2N 48=N K=N/2=48/2=24)
Thanks, that was fun.

Posted on Jul 26, 2011

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The sum of ages of marian, diana and carlos are 17. Two years from now marian will twice as old as diana. if carlos is half as old as marian four years from now. How ald are they now ? Pls show the...


Let m be Marian's age, d Diana's age and c Carlos age.
  • sum of ages is 17: m+d+c=17
  • two years from now Marian will be twice as old as Diana: m+2=2*(d+2) so m+2=2d+4 so 2d=m-2 or d=(m-2)/2=m/2-1
  • Carlos will be half as old as Marian 4 years from now: c+4=1/2(m+4) or c+4=m/2+2 or c=m/2-2
  • now: m+d+c=m+m/2-1+m/2-2=17
  • 2m=17+3=20
  • m=20/2=10 years
  • d=m/2-1=5-1=4 years
  • c=m/2-2=5-2=3 years
Marian is 10 years old, Diana 4 years old and Carlos is 3 years old.

I hope I helped :)

Sep 18, 2011 | Office Equipment & Supplies

1 Answer

Mary who is sixteen years old is four times as old as her brother.How old will mary be when his twice as old as her old brother?


Let the brother's age be x:
16years for Mary = 4x years for Brother

From equation: 4x = 16
x = 4
Therefore, the brother is 4 years old.

Mary Brother
16 4
After 4 years + 4 4
20 8
After the next 4 years + 4 4
24 12

24 is twice as old as 12; therefore for the sister to be twice as old as brother she will 24years when her brother is 12 years.

Or by calculation;

If 4 is the age for the brother, when the sister is 16, and y years will pass for the to be such that the sister is twice as old as the brother, then;

16 + y = 2(4 + y)
16 + y = 8 + 2y
16 - 8 = 2y - y
8 = y
Therefore, 8 years elapse before the sister is twice as old as the brother.

Sister will be: (16 + 8) = 24years
Brother will be: (4 + 8) = 12years

Aug 02, 2011 | Computers & Internet

1 Answer

Jan is twice as old as jake. The sum of their ages is 5 times jake's age less 48. How old are Jan and Jake


Jan is 48 years old and Jake is 24 years old.
(Jan - N, Jake - K N=2K N+K=5K-48 N+K+48=5K N+48=4K N+48=2N 48=N K=N/2=48/2=24)
Thanks, that was fun.

Jul 26, 2011 | Washing Machines

1 Answer

Father is 3 times as old as his daughter.In 12 years father will be 1 year less than twice his daugthers age.What is their age?


So the father is 3 times as old as his daughter.
Let F represent the age of the fatherLet D represet the age of the daughter
So we know from the first sentence,
F = 3 * D
From the second sentence, 12 years from now the father is 1 year les than twice his daughters age,
First, lets assume it's not 12 years from now (to avoid confusion), we would haveF + 1= 2 * D
But since its 12 years from now, we have to add 12 to both ages
(F + 12) + 1 = 2 * (D + 12)
Let's simplify a bit,

F + 13 = 2 * D + 24F = 2D + 11
Now we have to solve these two equations together, we can plug the first equation into the second,
F = 3 * DF = 2 * D + 11
3 * D = 2 * D + 11D = 11
So the daughter is 11 years old, we can find out how old the father is by plugging into the first equation
F = 3 * DF = 3 * 11F = 33
So the father is 33 and the daughter is 11.

Jul 19, 2011 | Computers & Internet

2 Answers

John is twice as old as bob and half as old as jean if jean is 40 years old how old is barry and who is the eldest of the three


No answer available - Barry isn't mentioned in the equation, and there are four people mentioned in the question.

Apr 05, 2011 | Computers & Internet

1 Answer

Give me one example of quadratic age word problem.


Within 11 years, the age of Peter will be half the square of the age he was 13 years ago. Calculate the current age of Peter.

Suzy is ten years older than Billy, and next year she will be twice as old as Billy. How old are they now?

Sep 22, 2010 | Computers & Internet

1 Answer

Alvin is now 20 years older than his son.In 10 years,he will be twice as old as his son's age.What are their present age's?


Christine,
(D=Dad's age, and S=Son's age)

D=S+20 (Dad is 20 years older than Son)
D+10 = 2xS (In ten years Dad will be twice Son's current age)
therefore (by substitution):
S+20+10 = 2xS
S+30 = 2S
2S = S+30
2S-S = 30 (subtract S from both sides)
S = 30 (Son's current age) *answer*
D = S+20
D = 30+20
D = 50 (Dad's current age) *answer*

In ten years, Dad will be 60, which is twice Son's current age of 30.

Please ask for -Gort.















Aug 27, 2010 | Mathsoft Solving and Optimization...

1 Answer

Jasmin is twice as old as rodney nine years ago


Hi,

Let the present age of the Rodney = X
present Age of the Jasmin = Y

As per the Situation,

Y-9 = 2 (X - 9)
Y-9 = 2X - 18
Y = 2X - 18 +9
Y = 2X-9

Second,

X + Y = 45
Y = 45 - X

Taking Both the situations,

2X - 9 = 45 - X
3X = 54
X = 54/3 = 18

Y = 45 - 18 = 27

Hence,

Age of Jasmin = 27

Let me know, if needed further assistance.

Hope i helped you.

Thanks for using ' Fixya ' and have a nice day!!

Mar 17, 2010 | Disney Watches

1 Answer

Find thier ages


Edwin is 14. Ruel is 7.

In 3 years Edwin will be 17. Edwin will be 10. (3*10 - 13 = 17)

Let x=Ruel's age now, and 2x=Edwin's age now.

2x+3=3(x+3)-13
2x+3=3x+9-13
2x+3=3x-4
2x+7=3x
7=x

If you are going to post these, the least you could do is rate them as Fixya. :-) Thanks!

Dec 11, 2008 | Computers & Internet

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