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Posted on Jan 02, 2017
Allan is 19 and Roy is 13.
First we have 2 variables, their ages: I used Allan = x & Roy = y
Equation 1: X - 4 = 2*(Y-4) - 3
We can ignore the 5 years in the second part of the statement. Allan will always be 6 years older than Roy whether it be 5 years from now or ten years form now.
Equation 2: X = Y + 6
Substitute Y + 6 for X in equation 1:
X - 4 = 2*(Y-4) - 3 becomes Y + 6 - 4 = 2*(Y-4) - 3
That simplifies to Y + 2 = 2Y - 8 - 3
Rewrite it again: Y + 2 = 2Y - 11
Add 11 to both sides: Y + 13 = 2Y
Subtract Y from both sides: 13 = Y
Now plug 13 in for y in Equation 2
X = Y + 6
X = 13 + 6
X = 19
Posted on Oct 09, 2009
SOURCE: Father is 3 times as
So the father is 3 times as old as his daughter.
Let F represent the age of the fatherLet D represet the age of the daughter
So we know from the first sentence,
F = 3 * D
From the second sentence, 12 years from now the father is 1 year les than twice his daughters age,
First, lets assume it's not 12 years from now (to avoid confusion), we would haveF + 1= 2 * D
But since its 12 years from now, we have to add 12 to both ages
(F + 12) + 1 = 2 * (D + 12)
Let's simplify a bit,
F + 13 = 2 * D + 24F = 2D + 11
Now we have to solve these two equations together, we can plug the first equation into the second,
F = 3 * DF = 2 * D + 11
3 * D = 2 * D + 11D = 11
So the daughter is 11 years old, we can find out how old the father is by plugging into the first equation
F = 3 * DF = 3 * 11F = 33
So the father is 33 and the daughter is 11.
Posted on Jul 19, 2011
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