Question about Inverter Pure Sine Wave 1500w Inverter

Hi,

a 6ya expert can help you resolve that issue over the phone in a minute or two.

best thing about this new service is that you are never placed on hold and get to talk to real repairmen in the US.

the service is completely free and covers almost anything you can think of (from cars to computers, handyman, and even drones).

click here to download the app (for users in the US for now) and get all the help you need.

goodluck!

Posted on Jan 02, 2017

SOURCE: Connection to car battery

The answer is yes...BUT make sure the polarity is correct and the inverter turned off when you make the connection

Posted on May 07, 2009

SOURCE: trying to find out what gauge of wire i need for a

At 12 volts DC it will pull 125 amps at full load of 1500 Watts.This requires at least #2 copper AWG

Posted on Jul 15, 2009

SOURCE: Overloaded my inverter -now only works when hooked to car battery

It sounds like the fuse that protects you cigarette lighter is blown.

After you have replaced the fuse, check the voltage again. 0.015vdc would not have powered anything that in manufactured to operate on 12vdc.

When powering anything over about 250W, I would suggest connecting directly to the battery to avoid overloading the lighter circuit.

Posted on Nov 27, 2009

SOURCE: getting fault light, what can I do?

Check the Following:

- Ground from inverter to frame is intact
- Positive leads are intact and clean
- Negative leads are intact and clean.

Posted on Apr 04, 2010

SOURCE: Hi. I have a 5000 watt inverter in my truck. The

A 5000 wat inverter is very large. Your alternator could not supply it alone without the batteries. The moderate to low usage is the key. Calculate the wattage of the load you want to connect. Depending on what else you're doing with the truck, lights, heater, air condition etc, you could probably draw somewhere between 1,0000-1500 watts on that alternator. Rember even if your alternator is rated for 150amps (large alt) it is not a 100% duty cycle. Alternators are usually around 50% duty cycle, so figure about 75amps continuous, or around 900 watts. That's considerably less than your 5,000 watt inverter. Buy a generator.

Posted on Jul 01, 2010

15 100watt bulbs

Jul 18, 2014 | Vector Electronics - Others

You dont want to install directly to the battery as the battery will constantly produce energy draining the battery instead install it to the yellow ignition wire usually accessable under the dash so as it only runs when the vehicle is on You can also usually locate the ignition at the fuse panel

May 20, 2012 | Cobra Electronics 1500 Watt Triple-Outlet...

You may not have adequate input voltage. And unless you are hooking up to a forklift battery, the battery will not have adequate current delivery capability for any more than a few seconds at full power of the inverter.

1200 Watts is 100 Amps. 1500 Watts is in the neighborhood of 130 Amps.

1200 Watts is 100 Amps. 1500 Watts is in the neighborhood of 130 Amps.

Jan 17, 2012 | Cobra Electronics - Others

A 5000 wat inverter is very large. Your alternator could not supply it alone without the batteries. The moderate to low usage is the key. Calculate the wattage of the load you want to connect. Depending on what else you're doing with the truck, lights, heater, air condition etc, you could probably draw somewhere between 1,0000-1500 watts on that alternator. Rember even if your alternator is rated for 150amps (large alt) it is not a 100% duty cycle. Alternators are usually around 50% duty cycle, so figure about 75amps continuous, or around 900 watts. That's considerably less than your 5,000 watt inverter. Buy a generator.

Jul 01, 2010 | Inverter Aims Pure Sine Wave Power...

a very thick one,,,like a baby battery lead on your car,,,its a very bad idear to have it so far away from the battery point, you would be far better off finding a closer place to put it as the volts drop off would have a big drop in out put on the inverter,,,also thats one big mother of a fridge to use 3000 watts????

you need a small power station to run it,,and if it do use 3000 watts your inverter is far to small to do the job, read the out put plate on the inverter,,it says 3000 watts max? not all the time,,,,thats about 2000 watts realy running contently and the whire to feed the inverter will need to carry about 30 amps so your car battery is say 90 amp hours plus the volts drop off, you would be lucky to have the inverter running for 3-4 hours before your battery go's is very flat on you!

you need a small power station to run it,,and if it do use 3000 watts your inverter is far to small to do the job, read the out put plate on the inverter,,it says 3000 watts max? not all the time,,,,thats about 2000 watts realy running contently and the whire to feed the inverter will need to carry about 30 amps so your car battery is say 90 amp hours plus the volts drop off, you would be lucky to have the inverter running for 3-4 hours before your battery go's is very flat on you!

Mar 28, 2010 | Inverter Aims Pure Sine Wave Power...

Your said your battery is rated for 85 amps / hour. This means 1 hour at 85 amps, 42 hours at 2 amps, 85 hours at 1 amp or any number of hours in between determined by 85 divided by the number of amps of the load connected. The microwave uses 600 watts. Since we can't reliably determine amps in an AC circuit - I can get close using the DC calculation. I'll assume 120 Volts at 600 watts for the microwave. Watts = Volts multiplied by Amps, so the microwave uses about 5 amps (120 x 5 = 600). HOWEVER, this is not an accurate way to determine AC amps when voltage and watts are known. I'll bet the microwave has the actual amount of amps (along with the model, voltage, wattage etc.) on a label on the back, side or inside the door. This is the information that is accurate. Use the amp rating provided on the name plate to determine how long the batter will last. Assume 8.5 amps is the value provided on the name plate.. 85 amp hour (85 AH) battery would supply an 8.5 amp (8.5 A) load for 10 hours because: 85 AH divided by 8.5 A = 10 H. The quality of the battery, and the losses contributed by the inverter will reduce the actual amount of time that the battery could supply the microwave.

I hope this helps!

I hope this helps!

Sep 18, 2009 | Panasonic Microwave Ovens

Your inverter has a peak of 3000 watts rating and should power that hair dryer. Make sure your batteries are in good shape. The inverter can only put out what it takes in. 1800 watt demand on the inverter requires 1800 watts from the batteries.

Jul 14, 2009 | Inverter Aims Pure Sine Wave Power...

Ok, Heres the deal. A gel cell battery is 7.2 Ampere hrs, so to get 14,4 Ampere hours you would need two batteries connected in parallel. A F&P machine such as mine consumes around 60 Watts of power. Using Ohms law we get W= IxE or Watts = volts X amps[or amperes = watts / volts] so that a 60 Watt machine has a current draw of 60/110< =0.55A so that a 14.4 A/hr battery will run this machine for around 20hrs (allowing a residual charge of 25%)

Jun 23, 2009 | Duracell Standby Power Plug 400 Watt...

If you want to get more precise, figure out everything in terms of power (watts).

Basic electrical rule 1, 2 and 3:

voltage x current = power

or re-arranged:

current = power divided by voltage

or re-arranged:

voltage = power divided by current

For example, 12V X 2 amps = 24 watts.

or another example, 400 watts divided by 120 Volts = 3.33 amps

A 55W headlight that uses 12V would draw 55 /12 = 4.6 amps @ 12V

A 55 watt light bulb in a lamp at home would draw 55 / 120 = 0.46 amps @ 120V

As the previous post mentioned, inverters are not perfect when convertering 12V into 120V. If the converter consumes 1000W from the 12V battery, then a 90% effecient converter would generate 900W of 120V AC power best case. The other 100W is lost primarily as heat.

The other thing that gets tricky is that these ratings and the formula above are used for resistive loads, like light bulbs or hair dryers. Anything with a motor or transformer is considered an inductive load and can get much more tricky to calculate.

Consequently you need to give your self a safety margin when figuring out how big an inverter you need.

How does work in a practical sense?

Lets say you want an inverter for TV, DVD and Sat. Receiver. Look at the back of TV or in the manual. It should say how many watts it consumes. Lets say it is 400W. The DVD might be 100W and the Sat. receiver 50W - just as an example.

400 + 100 + 50 = 550 Watts. (just as an example)

You might think, well no problem, I'll use a 600 Watt inverter and have 50 watts left over. Depending on your inverter, that 600W might really be 600 x 90% effecient = 540 Watts of AC, less a 20% margin of error for the inductive transformers in the electronic of the TV, DVD and Sat. receiver 540 - 20% = 432 Watts.

Now you can see your 600 Watt inverter isn't big enough to do the job.

If we really need 550 watts of AC, add 10% to make up the effiency loss, then add a safety margin for inductive loads.

550 + 10% = 605 + 20% = 726 Watts.

Sounds more like an 800W inverter fits the job.

What does that mean in terms of wiring the 12V batteries to the inverter?

from the formula above:

current = power divided by voltage

In our example, we have an 800W inverter that runs on 12V

The current would thererfore be:

current = power divided by voltage

current = 800 watts divided by 12V

current = 66 amps.

That is important info because you can not use light gauge wire to carry 66 amps worth of 12V to the inverter nor could you use a 20A fuse to protect your inverter.

Now that's a lot of science for a guy who just wants to run a toaster on an inverter right?

800W / 120V = 6.66 amps

Using garryp's ratio 11:1, 6.66 x 11 = 73 amps.

That is a good ratio with a good safety margin.

This is all just MHO and should not taken as solid technical advise. In other words, don't blame me if you blow yourself up.

Basic electrical rule 1, 2 and 3:

voltage x current = power

or re-arranged:

current = power divided by voltage

or re-arranged:

voltage = power divided by current

For example, 12V X 2 amps = 24 watts.

or another example, 400 watts divided by 120 Volts = 3.33 amps

A 55W headlight that uses 12V would draw 55 /12 = 4.6 amps @ 12V

A 55 watt light bulb in a lamp at home would draw 55 / 120 = 0.46 amps @ 120V

As the previous post mentioned, inverters are not perfect when convertering 12V into 120V. If the converter consumes 1000W from the 12V battery, then a 90% effecient converter would generate 900W of 120V AC power best case. The other 100W is lost primarily as heat.

The other thing that gets tricky is that these ratings and the formula above are used for resistive loads, like light bulbs or hair dryers. Anything with a motor or transformer is considered an inductive load and can get much more tricky to calculate.

Consequently you need to give your self a safety margin when figuring out how big an inverter you need.

How does work in a practical sense?

Lets say you want an inverter for TV, DVD and Sat. Receiver. Look at the back of TV or in the manual. It should say how many watts it consumes. Lets say it is 400W. The DVD might be 100W and the Sat. receiver 50W - just as an example.

400 + 100 + 50 = 550 Watts. (just as an example)

You might think, well no problem, I'll use a 600 Watt inverter and have 50 watts left over. Depending on your inverter, that 600W might really be 600 x 90% effecient = 540 Watts of AC, less a 20% margin of error for the inductive transformers in the electronic of the TV, DVD and Sat. receiver 540 - 20% = 432 Watts.

Now you can see your 600 Watt inverter isn't big enough to do the job.

If we really need 550 watts of AC, add 10% to make up the effiency loss, then add a safety margin for inductive loads.

550 + 10% = 605 + 20% = 726 Watts.

Sounds more like an 800W inverter fits the job.

What does that mean in terms of wiring the 12V batteries to the inverter?

from the formula above:

current = power divided by voltage

In our example, we have an 800W inverter that runs on 12V

The current would thererfore be:

current = power divided by voltage

current = 800 watts divided by 12V

current = 66 amps.

That is important info because you can not use light gauge wire to carry 66 amps worth of 12V to the inverter nor could you use a 20A fuse to protect your inverter.

Now that's a lot of science for a guy who just wants to run a toaster on an inverter right?

800W / 120V = 6.66 amps

Using garryp's ratio 11:1, 6.66 x 11 = 73 amps.

That is a good ratio with a good safety margin.

This is all just MHO and should not taken as solid technical advise. In other words, don't blame me if you blow yourself up.

Nov 26, 2008 | Coleman 5640B807 Compact Refrigerator

It would depend on the load being driven by the inverter (which would determine the current drawn by the inverter), the capacity of the batteries and the shutdown voltage of the inverter.

Oct 01, 2008 | Statpower PW-1750 Triple Outlet 1750 Watt...

144 people viewed this question

Usually answered in minutes!

×