# Explain 1 divided by 0 - Computers & Internet

Posted by on

• Level 3:

An expert who has achieved level 3 by getting 1000 points

All-Star:

An expert that got 10 achievements.

MVP:

An expert that got 5 achievements.

President:

An expert whose answer got voted for 500 times.

• Master

In mathematics, a division is called a division by zero if the divisor is zero. Such a division can be formally expressed as a / 0 where a is the dividend. Whether this expression can be assigned a well-defined value depends upon the mathematical setting. In ordinary (real number) arithmetic, the expression has no meaning, as there is no number which, multiplied by 0, gives a (a?0).
In computer programming, an attempt to divide by zero may, depending on the programming language, generate an error message or may result in a special not-a-number value (see below).
Historically, one of the earliest recorded references to the mathematical impossibility of assigning a value to a / 0 is contained in George Berkeley's criticism of infinitesimal calculus in The Analyst; see Ghosts of departed quantities.

Posted on Sep 03, 2010

Hi,
a 6ya expert can help you resolve that issue over the phone in a minute or two.
Best thing about this new service is that you are never placed on hold and get to talk to real repairmen in the US.
the service is completely free and covers almost anything you can think of.(from cars to computers, handyman, and even drones)
Goodluck!

Posted on Jan 02, 2017

×

my-video-file.mp4

×

## Related Questions:

### I AM TRYING TO UNDERSTAND BINARY

Where to start. Most things we do in math are in base 10, probably because we have 10 fingers. Instead of base 10, binary is base 2. In computers, binary rules because a bit can be set to ON or OFF, 1 being ON, and 0 being OFF.

So the next thing is counting. 0 1 10 11 100 101 110 111 1000 1001
Decimal equivalent 0 1 2 3 4 5 6 7 8 9

How to convert from binary to decimal? Line up the columns and multiply down. For example, 1101. The columns, starting from the right are 2^0, 2^1, 2^2, 2^3, reading ^ as exponent.

See if I can line these up. 1 1 0 1
2^3 2^2 2^1 2^0
8 4 2 1
multiplying down 8 4 0 1

Next step is to add them up. 8+4+1 = 13!

Going the other way, we have to divide by the largest 2^x number, so what is left over and continue dividing until nothing is left.

For example, 56. 2^5 (32) is the largest 2^x number that goes into 56, so we put a 1 in this column. Our remainder is 24. 2^4 (16) goes into this once, so we put a 1 in this column. Our remainder is 8. 2^3(8) goes into this once, so we put a 1 in this column. Now the remainder is 0 so we put a 0 in the 2^2 (4) column, 2^1(2) column, and 2^0 (1) column.

We end up with 111000.

Let me know if you have any questions.

Good luck.

Paul

Oct 26, 2015 | Office Equipment & Supplies

### How do i factor numbers on a ti-30xs calculator

This calculator does not have a key that you can use to find the prime factor of an integer.
You can however use the calculator to find the factors
1. If number is even divide it by 2
Keep dividing by 2, while keeping track of how many times you divided by 2.
If you divided 5 times by 2 before getting an odd number, then your first factor is 2^5
2. Now try dividing by 3, keep track of the number of times you divided by 3 before you could not divide by 3 any more. If you divided 0 times by 3, your second factor is 3^0, or 1 and 3 is not a factor.
If you divided 4 times by 3, your second factor is 3^4
3. Divide by 5, until you can't any more. Keep track of the number of times you divided by 5.
4. Divide by all other prime numbers 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, etc. For each prime number, keep track of how many times you divided by it, until you could not any more.

Example: 23100
Division by 2
23100/2=11550 ---------> 1 division by 2
11550/2=5775 ----------> 2 divisions by 2
Note that 5775 is not divisible by 2. No more divisions by 2.
First factor is 2^2

Division by 3:
5775/3=1925 ----------> 1 division by 3
1925/3=641. 66667 Not an integer. No more divisions by 3.
2nd factor is 3^1

Division by 5 (number ends in 5)
1925/5 =385 -------> 1 division by 5
385/5=77 ----------> 2 divisions by 5 and no more (quotient does not end in 0 or 5)
3rd factor is 5^2

Division by 7
77/7=11 --------> 1 division by 7, and no more
4th factor is 7^1=7

Division by 11
11/11=1
5th factor is 11^1=11

Assembling the factors 2^2, 3^1, 5^2, 7, 11
Prime factorization of 23100 is
23100=(2^2)(3)(5^2)(7)11

Dec 18, 2013 | Texas Instruments TI-30XA Calculator

### I dont understand why I keep getting the wrong exponet in trying to figure out 1500nm divided by 10^9. the answer I get is 1.5 *10^-7 -but the answer is 1.5*10^-6. What am I doing wrong?

Without knowing exactly what you're doing I can't be sure, but I suspect you're entering the 10^9 as something like 1 0 EE 9 .

1 0 EE 9 gives you 10 * 10^9, which is 10^10. You should be doing this as 1 5 0 0 / 1 EE 9 = .

Nov 06, 2012 | Texas Instruments TI-30XA Calculator

### 0.0000861 to the tenth power

Press . 0 0 0 0 8 6 1 y^x 1 0 =

The y^x key is just above the divide key.

Jun 12, 2012 | Texas Instruments TI-30XA Calculator

### Log 10,000 - log 1,000 divided by 4 log 1.0125 = 46.34 I cannot enter this into my calculator and get 46.34 as in the example. is there a trick in the way to enter this? I have a TI-30X calculator....

Is the original problem (log 10,000 - log 1,000) / (4 log 1.0125) ? If so, press
( 1 0 0 0 0 LOG - 1 0 0 0 LOG ) / ( 4 * 1 . 0 1 2 5 LOG =
and you should see the expected result.

Jul 25, 2011 | Office Equipment & Supplies

### 100.00 divided by 0.04

To do this calculation on a Canon P23-DHV Calculator press [1] [0] [0] [(divide)] [.] [0] [4] [=] this should give you
2,500.

Mar 17, 2011 | Canon P23-DHV Calculator

### Using the t1-83 show me how to do the following 800(1+0.02)to the 20th

Almost exactly the way you typed it.

8 0 0 ( 1 + 0 . 0 2 ) ^ 2 0 ENTER

^ is the key just above the divide key.

Feb 16, 2011 | Texas Instruments TI-83 Plus Calculator

### One divided by zero equal to infinity,why

This is from wikipedia:

When division is explained at the elementary arithmetic level, it is often considered as a description of dividing a set of objects into equal parts. As an example, consider having ten apples, and these apples are to be distributed equally to five people at a table. Each person would receive = 2 apples. Similarly, if there are 10 apples, and only one person at the table, that person would receive = 10 apples.

So for dividing by zero - what is the number of apples that each person receives when 10 apples are evenly distributed amongst 0 people? Certain words can be pinpointed in the question to highlight the problem. The problem with this question is the "when". There is no way to distribute 10 apples amongst 0 people. In mathematical jargon, a set of 10 items cannot be partitioned into 0 subsets. So , at least in elementary arithmetic, is said to be meaningless, or undefined.

Similar problems occur if we have 0 apples and 0 people, but this time the problem is in the phrase "the number". A partition is possible (of a set with 0 elements into 0 parts), but since the partition has 0 parts, vacuously every set in our partition has a given number of elements, be it 0, 2, 5, or 1000. If there are, say, 5 apples and 2 people, the problem is in "evenly distribute". In any integer partition of a 5-set into 2 parts, one of the parts of the partition will have more elements than the other.

In all of the above three cases, , and , one is asked to consider an impossible situation before deciding what the answer will be, and that is why the operations are undefined in these cases.

To understand division by zero, we must check it with multiplication: multiply the quotient by the divisor to get the original number. However, no number multiplied by zero will produce a product other than zero. To satisfy division by zero, the quotient must be bigger than all other numbers, i.e., infinity. This connection of division by zero to infinity takes us beyond elementary arithmetic (see below).

A recurring theme even at this elementary stage is that for every undefined arithmetic operation, there is a corresponding question that is not well-defined. "How many apples will each person receive under a fair distribution of ten apples amongst three people?" is a question that is not well-defined because there can be no fair distribution of ten apples amongst three people.

There is another way, however, to explain the division: if we want to find out how many people, who are satisfied with half an apple, can we satisfy by dividing up one apple, we divide 1 by 0.5. The answer is 2. Similarly, if we want to know how many people, who are satisfied with nothing, can we satisfy with 1 apple, we divide 1 by 0. The answer is infinite; we can satisfy infinite people, that are satisfied with nothing, with 1 apple.

Clearly, we cannot extend the operation of division based on the elementary combinatorial considerations that first define division, but must construct new number systems.

Oct 08, 2010 | Puzzle Massey Ferguson Tractor

### 1000 to the power of -1/ pkease can you right the steps

Here are a couple of ways to do this:
• 1 0 0 0 x^-1 ENTER x^-1 is the inverse key, just below the MATH key on the leftmost column of the keyboard.
• 1 0 0 0 ^ (-) 1 ENTER ^ is just above the divide key on the rightmost column of the keyboard. (-) is to the right of the decimal point on the bottom row of the keyboard.

Sep 16, 2010 | Texas Instruments TI-83 Plus Calculator

### If a thread of length 22units can be divided in 7

It's all due to the "base" in which you count,
and your definition of "exactly" divided,
right down to each of the 7 pieces being the *SAME* number of atomic particles, placed end-to-end.

If you used "base-seven", then 22 (base-ten) would be written as 31 (base-seven). So, 31 (base-seven) divided by 7 (base-7) would be '3.1' (3 times 1*7**0 + 1/7**1), where '3.1' (base-seven) is *NOT* an irrational number.

Jun 12, 2010 | Mathsoft StudyWorks! Middle School Deluxe...

## Open Questions:

#### Related Topics:

130 people viewed this question

Level 3 Expert

Level 3 Expert