Ad

In mathematics, a division is called a **division by zero** if the divisor is zero. Such a division can be formally expressed as *a* / 0 where *a* is the dividend. Whether this expression can be assigned a well-defined value depends upon the mathematical setting. In ordinary (real number) arithmetic, the expression has no meaning, as there is no number which, multiplied by 0, gives *a* (*a*?0).

In computer programming, an attempt to divide by zero may, depending on the programming language, generate an error message or may result in a special not-a-number value (see below).

Historically, one of the earliest recorded references to the mathematical impossibility of assigning a value to *a* / 0 is contained in George Berkeley's criticism of infinitesimal calculus in *The Analyst*; see Ghosts of departed quantities.

Posted on Sep 03, 2010

Ad

Hi,

a 6ya expert can help you resolve that issue over the phone in a minute or two.

Best thing about this new service is that you are never placed on hold and get to talk to real repairmen in the US.

the service is completely free and covers almost anything you can think of.(from cars to computers, handyman, and even drones)

click here to download the app (for users in the US for now) and get all the help you need.

Goodluck!

Posted on Jan 02, 2017

Ad

Where to start. Most things we do in math are in base 10, probably because we have 10 fingers. Instead of base 10, binary is base 2. In computers, binary rules because a bit can be set to ON or OFF, 1 being ON, and 0 being OFF.

So the next thing is counting. 0 1 10 11 100 101 110 111 1000 1001

Decimal equivalent 0 1 2 3 4 5 6 7 8 9

How to convert from binary to decimal? Line up the columns and multiply down. For example, 1101. The columns, starting from the right are 2^0, 2^1, 2^2, 2^3, reading ^ as exponent.

See if I can line these up. 1 1 0 1

2^3 2^2 2^1 2^0

8 4 2 1

multiplying down 8 4 0 1

Next step is to add them up. 8+4+1 = 13!

Going the other way, we have to divide by the largest 2^x number, so what is left over and continue dividing until nothing is left.

For example, 56. 2^5 (32) is the largest 2^x number that goes into 56, so we put a 1 in this column. Our remainder is 24. 2^4 (16) goes into this once, so we put a 1 in this column. Our remainder is 8. 2^3(8) goes into this once, so we put a 1 in this column. Now the remainder is 0 so we put a 0 in the 2^2 (4) column, 2^1(2) column, and 2^0 (1) column.

We end up with 111000.

Let me know if you have any questions.

Good luck.

Paul

So the next thing is counting. 0 1 10 11 100 101 110 111 1000 1001

Decimal equivalent 0 1 2 3 4 5 6 7 8 9

How to convert from binary to decimal? Line up the columns and multiply down. For example, 1101. The columns, starting from the right are 2^0, 2^1, 2^2, 2^3, reading ^ as exponent.

See if I can line these up. 1 1 0 1

2^3 2^2 2^1 2^0

8 4 2 1

multiplying down 8 4 0 1

Next step is to add them up. 8+4+1 = 13!

Going the other way, we have to divide by the largest 2^x number, so what is left over and continue dividing until nothing is left.

For example, 56. 2^5 (32) is the largest 2^x number that goes into 56, so we put a 1 in this column. Our remainder is 24. 2^4 (16) goes into this once, so we put a 1 in this column. Our remainder is 8. 2^3(8) goes into this once, so we put a 1 in this column. Now the remainder is 0 so we put a 0 in the 2^2 (4) column, 2^1(2) column, and 2^0 (1) column.

We end up with 111000.

Let me know if you have any questions.

Good luck.

Paul

Oct 26, 2015 | Office Equipment & Supplies

This calculator does not have a key that you can use to find the prime factor of an integer.

You can however use the calculator to find the factors

1.** If number is even divide it by 2**

Keep dividing by 2, while keeping track of how many times you divided by 2.

If you divided 5 times by 2 before getting an odd number, then your first factor is 2^5

2.**Now try dividing by 3**, keep track of the number of times you divided by 3 before you could not divide by 3 any more. If you divided 0 times by 3, your second factor is 3^0, or 1 and 3 is not a factor.

If you divided 4 times by 3, your second factor is 3^4

3.**Divide by 5,** until you can't any more. Keep track of the number of times you divided by 5.

4. Divide by all other prime numbers 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, etc. For each prime number, keep track of how many times you divided by it, until you could not any more.

**Example: 23100**

*Division by 2*

23100/2=11550 ---------> 1 division by 2

11550/2=5775 ----------> 2 divisions by 2

Note that 5775 is not divisible by 2.** No more divisions by 2. **

First factor is 2^2

*Division by 3:*

5775/3=1925 ----------> 1 division by 3

1925/3=641. 66667 Not an integer. No more divisions by 3.

**2nd factor is 3^1**

*Division by 5 (number ends in 5)*

1925/5 =385 -------> 1 division by 5

385/5=77 ----------> 2 divisions by 5 and no more (quotient does not end in 0 or 5)

**3rd factor is 5^2**

*Division by 7 *

77/7=11 --------> 1 division by 7, and no more

**4th factor is 7^1=7**

*Division by 11*

11/11=1

**5th factor is 11^1=11**

Assembling the factors 2^2, 3^1, 5^2, 7, 11

Prime factorization of 23100 is

**23100=(2^2)(3)(5^2)(7)11**

You can however use the calculator to find the factors

1.

Keep dividing by 2, while keeping track of how many times you divided by 2.

If you divided 5 times by 2 before getting an odd number, then your first factor is 2^5

2.

If you divided 4 times by 3, your second factor is 3^4

3.

4. Divide by all other prime numbers 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, etc. For each prime number, keep track of how many times you divided by it, until you could not any more.

23100/2=11550 ---------> 1 division by 2

11550/2=5775 ----------> 2 divisions by 2

Note that 5775 is not divisible by 2.

First factor is 2^2

5775/3=1925 ----------> 1 division by 3

1925/3=641. 66667 Not an integer. No more divisions by 3.

1925/5 =385 -------> 1 division by 5

385/5=77 ----------> 2 divisions by 5 and no more (quotient does not end in 0 or 5)

77/7=11 --------> 1 division by 7, and no more

11/11=1

Assembling the factors 2^2, 3^1, 5^2, 7, 11

Prime factorization of 23100 is

Dec 18, 2013 | Texas Instruments TI-30XA Calculator

Without knowing exactly what you're doing I can't be sure, but I suspect you're entering the 10^9 as something like 1 0 EE 9 .

1 0 EE 9 gives you 10 * 10^9, which is 10^10. You should be doing this as 1 5 0 0 / 1 EE 9 = .

1 0 EE 9 gives you 10 * 10^9, which is 10^10. You should be doing this as 1 5 0 0 / 1 EE 9 = .

Nov 06, 2012 | Texas Instruments TI-30XA Calculator

Press . 0 0 0 0 8 6 1 y^x 1 0 =

The y^x key is just above the divide key.

The y^x key is just above the divide key.

Jun 12, 2012 | Texas Instruments TI-30XA Calculator

Is the original problem (log 10,000 - log 1,000) / (4 log 1.0125) ? If so, press

( 1 0 0 0 0 LOG - 1 0 0 0 LOG ) / ( 4 * 1 . 0 1 2 5 LOG =

and you should see the expected result.

( 1 0 0 0 0 LOG - 1 0 0 0 LOG ) / ( 4 * 1 . 0 1 2 5 LOG =

and you should see the expected result.

Jul 25, 2011 | Office Equipment & Supplies

To do this calculation on a Canon P23-DHV Calculator press [1] [0] [0] [(divide)] [.] [0] [4] [=] this should give you

2,500.

2,500.

Mar 17, 2011 | Canon P23-DHV Calculator

Almost exactly the way you typed it.

8 0 0 ( 1 + 0 . 0 2 ) ^ 2 0 ENTER

^ is the key just above the divide key.

8 0 0 ( 1 + 0 . 0 2 ) ^ 2 0 ENTER

^ is the key just above the divide key.

Feb 16, 2011 | Texas Instruments TI-83 Plus Calculator

This is from wikipedia:

When division is explained at the elementary arithmetic level, it is often considered as a description of dividing a set of objects into equal parts. As an example, consider having ten apples, and these apples are to be distributed equally to five people at a table. Each person would receive = 2 apples. Similarly, if there are 10 apples, and only one person at the table, that person would receive = 10 apples.

So for dividing by zero - what is the number of apples that each person receives when 10 apples are evenly distributed amongst 0 people? Certain words can be pinpointed in the question to highlight the problem. The problem with this question is the "when". There is no way to distribute 10 apples amongst 0 people. In mathematical jargon, a set of 10 items cannot be partitioned into 0 subsets. So , at least in elementary arithmetic, is said to be meaningless, or undefined.

Similar problems occur if we have 0 apples and 0 people, but this time the problem is in the phrase "**the** number". A partition is possible (of a set with 0 elements into 0 parts), but since the partition has 0 parts, vacuously every set in our partition has a given number of elements, be it 0, 2, 5, or 1000. If there are, say, 5 apples and 2 people, the problem is in "evenly distribute". In any integer partition of a 5-set into 2 parts, one of the parts of the partition will have more elements than the other.

In all of the above three cases, , and , one is asked to consider an impossible situation before deciding what the answer will be, and that is why the operations are undefined in these cases.

To understand division by zero, we must check it with multiplication: multiply the quotient by the divisor to get the original number. However, no number multiplied by zero will produce a product other than zero. To satisfy division by zero, the quotient must be bigger than all other numbers, i.e., infinity. This connection of division by zero to infinity takes us beyond elementary arithmetic (see below).

A recurring theme even at this elementary stage is that for every undefined arithmetic operation, there is a corresponding question that is not well-defined. "How many apples will each person receive under a fair distribution of ten apples amongst three people?" is a question that is not well-defined because there can be no fair distribution of ten apples amongst three people.

There is another way, however, to explain the division: if we want to find out how many people, who are satisfied with half an apple, can we satisfy by dividing up one apple, we divide 1 by 0.5. The answer is 2. Similarly, if we want to know how many people, who are satisfied with nothing, can we satisfy with 1 apple, we divide 1 by 0. The answer is infinite; we can satisfy infinite people, that are satisfied with nothing, with 1 apple.

Clearly, we cannot extend the operation of division based on the elementary combinatorial considerations that first define division, but must construct new number systems.

[edit]

Oct 08, 2010 | Puzzle Massey Ferguson Tractor

Here are a couple of ways to do this:

- 1 0 0 0 x^-1 ENTER x^-1 is the inverse key, just below the MATH key on the leftmost column of the keyboard.
- 1 0 0 0 ^ (-) 1 ENTER ^ is just above the divide key on the rightmost column of the keyboard. (-) is to the right of the decimal point on the bottom row of the keyboard.

Sep 16, 2010 | Texas Instruments TI-83 Plus Calculator

It's all due to the "base" in which you count,

and your definition of "exactly" divided,

right down to each of the 7 pieces being the *SAME* number of atomic particles, placed end-to-end.

If you used "base-seven", then 22 (base-ten) would be written as 31 (base-seven). So, 31 (base-seven) divided by 7 (base-7) would be '3.1' (3 times 1*7**0 + 1/7**1), where '3.1' (base-seven) is *NOT* an irrational number.

and your definition of "exactly" divided,

right down to each of the 7 pieces being the *SAME* number of atomic particles, placed end-to-end.

If you used "base-seven", then 22 (base-ten) would be written as 31 (base-seven). So, 31 (base-seven) divided by 7 (base-7) would be '3.1' (3 times 1*7**0 + 1/7**1), where '3.1' (base-seven) is *NOT* an irrational number.

Jun 12, 2010 | Mathsoft StudyWorks! Middle School Deluxe...

Nov 24, 2017 | Computers & Internet

Nov 23, 2017 | Computers & Internet

130 people viewed this question

Usually answered in minutes!

×