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Posted on Jan 02, 2017

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I need some help here. If we take the sum of 2 integers from 1 to 9, and they can be the same number, the maximum number is 18. I don't know how you are supposed to get four consecutive digits, unless you pad the number with zeros. Am I missing something?

Good luck,

Paul

Good luck,

Paul

May 29, 2016 | Office Equipment & Supplies

The integers of the numbers on three raffle tickets are consecutive integers whose sum is 7,530 are 2509, 2510, and 2511.

Feb 24, 2015 | SoftMath Algebrator - Algebra Homework...

Let x be the smallest number.

Let x + 2 be the other number (consecutive even integer)

Now to translate the rest;)

three times the smaller 3(x)

19 more -19

sum of the two integers - (x) +( x+2)

Pulling it together,

3x -19 = x + x +2

collect like terms

3x - 19 = 2x + 2

Put all the constants on one side by adding 19 to both sides.

3x - 19 +19= 2x + 2 + 19

3x = 2x +21

Subtract 2x from both sides to have all the x's on one side.

3x - 2x = 2x +21 - 2x

x = 21

The other number is 21 + 2, or 23

Check:three times the smaller = 3 x 21 = 63

sum of the two integers = 21 + 23 or 44

is 63 at least 19 more than 44

Let x + 2 be the other number (consecutive even integer)

Now to translate the rest;)

three times the smaller 3(x)

19 more -19

sum of the two integers - (x) +( x+2)

Pulling it together,

3x -19 = x + x +2

collect like terms

3x - 19 = 2x + 2

Put all the constants on one side by adding 19 to both sides.

3x - 19 +19= 2x + 2 + 19

3x = 2x +21

Subtract 2x from both sides to have all the x's on one side.

3x - 2x = 2x +21 - 2x

x = 21

The other number is 21 + 2, or 23

Check:three times the smaller = 3 x 21 = 63

sum of the two integers = 21 + 23 or 44

is 63 at least 19 more than 44

Feb 19, 2015 | Office Equipment & Supplies

129

If this is homework, be sure to show your work.

If this is homework, be sure to show your work.

Jan 16, 2015 | Mathematical Technologies Inc. MTI Tristan...

38.

The three numbers are 34, 36, and 38.

The three numbers are 34, 36, and 38.

Jun 03, 2014 | Office Equipment & Supplies

Here's a simple (and inefficient) 35s program. It simply goes through a loop 25 times, adding up the numbers.

A001 LBL A

A002 25

A003 STO A

A004 0

A005 RCL+ A

A006 DSE A

A007 GTO A005

The sum of the first N positive integers can be calculated more efficiently as N(N+1)/2 .

A001 LBL A

A002 25

A003 STO A

A004 0

A005 RCL+ A

A006 DSE A

A007 GTO A005

The sum of the first N positive integers can be calculated more efficiently as N(N+1)/2 .

Mar 10, 2014 | HP 35s Programmable Scientific Calculator...

X + ( X + 2 ) + ( X + 4 ) = 105

3X + 6 = 105

3X = 105 - 6

3X = 99

X = 99/3

X = 33

So 33 + 35 + 37 = 105

3X + 6 = 105

3X = 105 - 6

3X = 99

X = 99/3

X = 33

So 33 + 35 + 37 = 105

Oct 06, 2010 | American Standard Plumbing

Let X be the lowest of the 3 integers

The sum of the 3 integers can be represented as X + (X+1) + (X+2).

Set this sum equal to 378 and solve for X.

X + (X+1) + (X+2) = 378

3X + 3 = 378

3X = 375

X = 125

Since X is the lowest of the 3 integers the other 2 will be X+1 and X+2 or 126 and 127.

Therefore, the answer is 125, 126 and 127

The sum of the 3 integers can be represented as X + (X+1) + (X+2).

Set this sum equal to 378 and solve for X.

X + (X+1) + (X+2) = 378

3X + 3 = 378

3X = 375

X = 125

Since X is the lowest of the 3 integers the other 2 will be X+1 and X+2 or 126 and 127.

Therefore, the answer is 125, 126 and 127

Aug 23, 2010 | SoftMath Algebrator - Algebra Homework...

Aug 29, 2017 | Canon Cameras

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