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Find the antilog on the TI-83 Plus for finding pH in chemistry problems

I need to know how to find the antilog on a TI[-83 Plus calculator to solve pH problems in chemistry.

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  • 2 more comments 
  • rcormier999 Sep 20, 2008

    How do I calculate the antilog 1.3 = with my TI-84 silver?

  • Anonymous Oct 28, 2008

    I have the same problem

    I have tried -log(x)

    and log(-x)

    and {log(x)}\1


  • mcgillad1412 Dec 06, 2008

    how do I grapg logarithmic functions?

  • Anonymous Dec 07, 2008

    how do i get antilog of this number 5.45 using ti 83

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I reccently had the same problem, but I have a Ti-84 Plus,and I am disgusted by how poorly this matter is covered by Texas Intruments. Esp. since the solution is rather simple.

The antilog key is [2nd] [log] or the 10^x. On your screen it should apear as 10^( and then you just input the value that you want to find the antilog of.

When used to solve pH problems remember to input the pH value as a negative number, since pH= -log[H+] then [H+]= antilog(-pH).

Hope that helped))))) ^^

Posted on Nov 25, 2008

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I get to the part where you puch [2nd] [log] and then not sure what to do after that.

My formula is meant to be:

-log(1.2*10-3)

The answer is: Find the antilog on the TI-83 Plus for finding pH  - moz-screenshot.pngmoz-screenshot-1.png2.9208187539524

The way I'm trying to enter the formula on the ti 83 is:

- [log]1.2x[2nd][log] -3 )

I just get a syntax error!

Any ideas?

Posted on Mar 07, 2010

  • ecoimpact Mar 07, 2010

    Ok, I sorted out this one.

    The formula is:

    - [log]1.2 x [2nd][log] (-) 3 )

    Next push [enter] twice, otherwise you just get '0' as the answer!

    The '(-)' button is next to the [enter] button.

  • kenji trotter Oct 10, 2012

    When the concentration of [Ag+] = Ksp/[I-] = (8.3X10^-17)/(6.76X10^-4)= 1.23 X 10^-13M What is the p[Ag+]? Solving for the negative log of [Ag+]: type in to the TI-83 Plus the following: log(10^(-13)*1.23) = -12.91, since p[Ag+] is the negative log, the answer is therefore 12.91 (hint:in the 10^(-13) portion of the equation, the negative sign is from the "(-)" button not the "-" button)

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How do i find the anilog on my calculator i have a texas instrument ti-30

Posted on Oct 15, 2008

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SOURCE: Find the antilog on the TI-84 Plus for finding pH in chemistry problems

I'm not specifically familiar with the TI83 or TI84 but I've used a lot of TI calculators in my time, so I'll give it a try. If your trying to find the antilog of a number in base 10 enter the number and hit the (10 to the X) button. If you're trying to find the antilog of a number in in base e (natural log), enter the number and hit the (e to the X) button.

Posted on May 29, 2009

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1 Answer

Antilog on ti-84


The common antilog is the shifted function of the common log key (marked LOG, just to the left of the 7 key). The natural antilog is the shifted function of the natural log key (marked LN, just to the left of the 4 key).

Apr 13, 2014 | Texas Instruments TI-83 Plus Calculator

1 Answer

Keystrokes fo finding the Antilog of 1.5283 for example. just need the key strokes.


What you call the ANTILOG is just the 10^x key.
To calculate i,t use the shifted key of LOG. Press [2nd][LOG] 1.5283, close the right parenthesis and press [ENTER].
If you are looking for the `ANTILOG` of a natural logarithm, use the exponential function key [2nd][e^x]

Apr 21, 2011 | Texas Instruments TI-83 Plus Calculator

1 Answer

How do I calculate: What is the [H3O+] of a solution with a pH of 4.5 on the TI-83 Plus


If you have the pH, and want to calculate the concentration that yields that value of the pH, you proceed as follows
c[H3O ] = 10^(-pH)
Ex pH=8.23
c[H3O ] : [2nd][LOG] [(-)] 8.23 [)] where
[(-)] is the change sign key.

Here is a screen capture to show you how to calculate the pH (first example) and the concentration (2nd example)

7bb73d3.jpg

Sep 03, 2010 | Texas Instruments TI-83 Plus Calculator

1 Answer

How to use antilog?


Hello,

As you well know the pH is the negative of the log in base 10 of the H+/H3O+ ion concentration. If we use [H+] to represent that concentration, then pH=-log[H+].
To obtain the [H+] you need to calculate the antilog. You write the definition in the form log[H+] =-pH and then calculate 10 to the power of each member. The equality remains valid as both members are treated similarly. Thus
10^( log[H+] ) = 10^(-pH)
Since raising 10 to a power is the inverse function of taking the log in base 10, 10^(log(x))=log(10^(x)) = x (they are inverse of one another), you are left with

[H+]=10^(-pH)

Your calculator has a function [10 to x] accessed by pressing the [2nd] function key. To use it you must enter the negative value of the pH, press the [2nd] function key then the [10 to x], then the = key to get the result (concentration)
Exemple: let the pH=5.5, what is the H+ concentration?
With [(-)] being the change sign key, then
[H+]:[ (-) ] 5.5 [2nd][10 to x] [=]
The result is 0.000003162 or 3.16 x 10^(-6)

Hope it helps.


Dec 07, 2009 | Texas Instruments TI-30XA Calculator

1 Answer

How to calculate the antilog please


The antilog is the inverse of the logarithm. Not too surprisingly, it's invoked as the 2ND shift of the appropriate log key.

For the common antilog, use the 10^x key (2ND LOG). For example, 2ND LOG 3 ENTER gives 1000 as the common antilog of 3.

For the natural antilog, use the e^x key (2ND LN). For example, 2ND LN 3 ENTER gives 20.08553692 as the natural antilog of 3.

Sep 27, 2009 | Texas Instruments TI-83 Plus Calculator

2 Answers

Find the antilog on the TI-84 Plus for finding pH in chemistry problems


I'm not specifically familiar with the TI83 or TI84 but I've used a lot of TI calculators in my time, so I'll give it a try. If your trying to find the antilog of a number in base 10 enter the number and hit the (10 to the X) button. If you're trying to find the antilog of a number in in base e (natural log), enter the number and hit the (e to the X) button.

May 29, 2009 | Texas Instruments TI-83 Plus Calculator

1 Answer

How do I get an antilog?


For common antilog: 2ND 10^x (-) 13.51 ) ENTER

For natural antilog: 2ND e^x (-) 13.51 ) ENTER

Mar 20, 2009 | Texas Instruments TI-83 Plus Calculator

1 Answer

Chemistry problem


You enter a pH value and change the sign to minus, then hit 2nd LOG which is 10^x. The x value is what you're looking for. To put the answer in scientific notation, press 2nd 5 to do so.

Example:

For a pH = 4.1

-4.1 2nd LOG will return 0.0000794

Hiting 2nd 5 will express it as 7.94 -5, giving you the [H+] concentration.

Apr 22, 2008 | Texas Instruments TI-30XA Calculator

1 Answer

Antilog in chemistry problem


pH is minus (log to base 10) of the hydrogen ion activity of an aqueous solution, or (log to base 10) of (1/hydrogen ion activity)

To get the inverse log, i.e the hydrogen ion activity corresponding to a specified pH, simply enter the pH value and press

2nd
LOG
1/x

Answer 0.001

Apr 22, 2008 | Texas Instruments TI-30XA Calculator

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