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Between Al and Fe WHICH IS A METAL CONDUCTOR AND WH

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Fe is Iron this is a ferrus metal, a magnet will stick to it
Al is Aluminium, this metal is non ferrus and a magnet will not stick to it.
Buy both conduct electricity.
Only part of your question got printed. so please write back if you need more information.

Posted on Aug 27, 2010

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WHAT IS THE ELECTRON CONFIGURATION OF Li,Mg,Ca,Al,Fe,Cu and Pb?


[Li]=[He]2s
[Mg]=[Ne]3s^2
[Ca]=[Ar]4s^2
[Al]=[Ne]3s^2 3p
[Fe]=[Ar]3d^6 4s^2
[Cu]=[Ar]3d^10 4s
[Pb]=[Xe] 4f^14 5d^10 6s^2 6p^2

Aug 14, 2013 | Computers & Internet

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What is the grounding requirements for a residential home?


Depending on your locality, these requirements may differ from what is specified by the National Electrical Code (NEC or "code"). The NEC is commonly regarded as the minimum requirements for electrical installations, and many states adopt it without modification as their requirements, too. Still others modify it and some counties and towns further modify the code. It is for these reasons, you should consult your local code enforcement office to learn what the authority having jurisdiction (AHJ) wants to see when (s)he inspects the work.

Typically, an 8' grounding electrode (or ground rod) is driven into the ground and an approved clamp is used to secure an unspliced grounding electrode conductor to the neutral bar in the meter socket or service entrance equipment. The size of this conductor is based on the service entrance (SE) conductors. Typical sizes are when:

100 amp SE conductors are #4 copper (CU) or #2 aluminum (AL), requires a #8 CU or #6 AL grounding electrode conductor.

150 amp SE conductors that are #1 CU or 2/0 AL require a #6 CU or #4 AL grounding electrode conductor.

200 amp SE conductors that are 2/0 or 3/0 CU or 4/0 or 250 AL require a #4 CU or #2 AL grounding electrode conductor.

You may be required to provide a secondary grounding electrode if you can not provide data supporting minimum soil resistivity to the AHJ.

Lastly, bonding of the residence's cold water pipes is required. A #8 is used for 100 amp services and #6 for up to 200 amp services. If on a public water supply, the bonding conductor must be connected on the street side of the meter and the house side of the meter (should the meter be removed there will be no voltage present to injure the person removing the meter) to the grounding electrode conductor termination bar in the meter socket or ground bar in the service entrance equipment. Installation and connection of an IBT (Intersystem Bonding Terminal) is required for telephone, cable TV, etc. You may need to bond gas piping and metal duct work., and some locations specifically prohibit bonding one or more of these items.

The short of this is you must determine the requirements of your locality. The AHJ can tell what they are - but will probably not tell you how to do it.

I hope this was helpful.

Feb 23, 2012 | Hammering

1 Answer

I use headphones from my nokia phone for my pc and they were worked great, but now i can hear the sound that comes from the right side on both speakers, and the sount that come from left i can hear on


If you look closely at the plug itself (the metal part which actually goes into the hole), you will see that there are either 3 or 4 shiny metal areas separated by some black plastic or some other hard substance. The shiny metal area is a conductor of electricity, and the black part is an insulator of electricity, keeping the conductors separate. Normal stereo earphones have 3 conductor areas, because that is all you need to send a different signal to each ear. Earphones that include a microphone, however, require four separate metal sections, because they need another separate conductor for connecting the microphone. They try to design the 4-conductor plug so that it can still be used in a 3-conductor jack (backwards-compatible), but it is not going to be perfect.So the headphone jack in your PC is designed to accept a plug with 3 separate areas, and will connect each of those 3 separate areas to the correct circuit on the sound card of the computer, but the earphones for your phone likely have 4 separate areas, unless I am barking up the wrong tree. You can typically connect another sort of microphone to a PC, but normally it is a separate plug altogether.So why did it work before, and not now, you ask? headphone jacks have very small, metal, moving parts that physically come in contact with the appropriate separate conductors when you insert the plug. Moving parts like this can change over time enough that(or can have dirt get inside them to the point where) they no longer connect exactly the same way that they used to, especially for plugs that they are not originally designed to connect with in the first place. Headphone jacks probably cost the manufacturer somewhere around a cent apiece (just guessing), so unless the manufacturer is one that will always pick the most expensive, robust components, what we are dealing with is a problem with a part that cost less than a nickel (maybe less than a penny, for all I know) and was not really engineered to handle a 4-conductor headphone jack. If you get a 3-conductor set of headphones, they will probably work correctly, but remember you get what you pay for, so the cheaper you go, the more likely they are to **** out sooner than later.

Feb 02, 2012 | Audio Players & Recorders

1 Answer

Pyoblema con el dispositivo bluetooth


Hola,

Puede descargar al último conductor para usted bluetooth aquí. después de instalar la prensa de conductor de bluetooth FN + F5 para permitir el bluetooth y inidicator en la pantalla le dirán si el bluetooth está en o lejos. Asegúrese de que selecciona a conductor de thr para su sistema operativo

No se olvide de dar las gracias. Gracias por utilizar Fixya.

Feb 10, 2011 | Lenovo G455 Laptop Computer 070834U...

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Vehicle was driven without issue, parked overnight and next morning would not start. Managed to start with aerostart, drove 50kms to town done shopping then drove to toilets came back out and no start, got...


replace the wires. start with coil lead. the metal end may not be making a good connection with the wire.The conductor can burn away inside the insultion and leave no exterior burns to see. I would remove the metal end and trim back enough insulation to expose about an inch of the carbon impregnated conductor. Then with the conductor folded backwards along the outside of the wire, refit the metal clip tightly. Ensure that plenty of the conductor is held tightly under the clip, about half an inch. The tight fit is all you need to ensure a good contact. Good Luck! Duck

Jan 10, 2011 | Ford Festiva Cars & Trucks

1 Answer

Mag-lite does not work i have tried new batteries and new bulb and cleaning the spring in the rear.The switch appears to be operating correctly,but has not been checked


If your flashlight is like mine...

The switch closes the circuit to the bulb, so there is a wire, or metal conductor running from the switch to the bulb holder. If your switch is mechanical, it will push a metal lever forward ... bend lever this so it contacts the bulb holder better. If your switch has a wire, the wire is soldered to the bulb holder, but the switch may be bad

There is a second wire or metal conductor running to the back of the flashlight. This conductor has to make good connection to the metal spring. Stretch out the metal spring, and see if it rotates a bit so it makes better contact with the conductor coming from bulb.

There is a third point. This is where the front of the battery touches. If batteries touch the bulb, then the problem is the metal spring in the back or the mechanical switch lever. If your batteries touch a copper spring, see if you can clean this spring and pull it out a bit.

Oct 17, 2010 | MagLite Mag-Lite& Flashlight

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I have a doubt whether that in presence of tap water or salt water or air the nail gets rusted fastly


The short answer is Yes, it does. The reason is, because "salt" (NaCl) is a strong electrolyte, which facilitates the flow of electrons in a naturally produced mini-circuit on the surface of the nail, which is in contact with both air (oxygen) and moisture (water).


The "mini-circuit" mentioned above is the consequence of the kind of reaction (oxidation and reduction occurring simultaneously, called a redox reaction) that an uncharged metal atom (like iron, Fe) can undergo because of its ability to lose its valence electrons (loosely held) that normally move around the outermost orbital of its nucleus. This kind of electron transfer spontaneously occurs (i.e., by itself without any outside help) only if the iron is able to come in contact with an atom of another element, or the ion of that other element (which can be a metal or not), that has an attraction for electrons (standard reduction potential) that is stronger than the attraction of electrons by the iron. For a more detailed and technical explanation, please see my "Solution 2" for this problem.


What's salt got to do with all this?

An electrolyte (pronounced, electro-lite), is so-named because it is a substance that can conduct electricity (electric current). Strong electrolytes (salts) dissolved in water, melted (molten) electrolytes (in absence of water), and pure metals are good electrical conductors*. What makes a strong electrolyte able to conduct electricity is its ionic nature, that is, its being made up of ions, which have charges. When NaCl ("salt") is dissolved in water, it immediately breaks up (dissociates) into its constituent ions (Na+ and Cl-). It's these ions that make the solution a good conductor. So, the more ions in aqueous solution, the more effective the solution can support the flow (transfer) of electrons (current) that are involved in the type of reaction (redox) occurring in the rusting of a nail.


*Exactly how these substances are able to act as conductors has been described in complex theories, but most chemistry textbooks omit them, except for how metals behave as conductors - see more about this using the key search term, electron-sea model, a very well developed theory of metallic bonding. Probably, one of the most essential characteristics of a good conductor is the mobility of its charged particles. For example, though a solution of ions is a good conductor, the pure solid form of the same electrolyte behaves as a non-electrolyte! So, it is reasonable to deduce that when an electron contributes to an electron current going through a solution of ions, it hops a ride on those charged particles, or that the very rapid collisions between them are very effective in allowing virtually instantaneous net electron movement across them.


You also asked about the effect of tap water. See my Solution 2 for this problem.


###

Aug 26, 2010 | Scientific Explorer My First Chemistry Kit

1 Answer

Which of the on reacting with ferrous sulphate(FeSO4) will give a black residue? a) Zn ; b) Al ; c) Fe ; d) Cu


What an interesting question! You are asking "Which [of the listed metals] on reacting with FeSO4 will give a black residue?

My answer is None of them - but possibly from either a) Zn and b) Al under certain conditions as indicated below.

Both elemental zinc and aluminum will undergo a redox (reduction-oxidation) reaction with the Fe2+ ion (of FeSO4) to give zinc and aluminum ions (Zn2+ and Al3+), which would form the zinc and aluminum salts, ZnSO4 and Al2(SO4)3 - both of which are white solids. The other product in each of these reactions is elemental iron, which is reported to be silvery, if the iron is free of contaminants). Pure elemental iron is not black. If the freshly formed iron is oxidized, it would probably from iron oxide, Fe2O3, which is "rust," which is reddish-brown, and not black.

HOWEVER, if the above elemental iron becomes colloidal in the presence of impurities (e.g., organics), it is possible that the iron might appear to to be a black residue. And this could occur from the reaction of FeSO4 with either a) Zn or b) Al.

Elemental iron (Fe) will not react with FeSO4, because there would not be any other metallic reactant present that could either oxidize or reduce it.

Finally, elemental copper (Cu) and FeSO4 would not undergo a spontaneous redox reaction written as follows: Cu + Fe2+ => Cu2+ + Fe, no reaction. (Only the reverse reaction would occur: Cu2+ + Fe => Cu + Fe2+, but the problem does not indicate the presence of either Cu2+ or Fe in choice d.)

Jun 27, 2010 | Scientific Explorer My First Chemistry Kit

1 Answer

Olympus FE-290 mode settings--only some are correct--"P" no good


FixYa sent me an email asking whether the problem was solved, and if so, how I did it....Here is my response to that query...
The problem is solved....I decided not to wait for an answer (that I didn't expect would come---the issue was a bit "involved") and placed the item up for auction on ebay with a clear description of the camera's deficiencies. Bidding has already commenced as I write this. Someone ELSE may be contacting you soon about this, though!

Jan 05, 2009 | Olympus FE-290 Digital Camera

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