Question about Mathsoft Solving and Optimization Extension Pack III (46513) for PC

# Alvin is now 20 years older than his son.In 10 years,he will be twice as old as his son's age.What are their present age's?

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Christine,

D=S+20 (Dad is 20 years older than Son)
D+10 = 2xS (In ten years Dad will be twice Son's current age)
therefore (by substitution):
S+20+10 = 2xS
S+30 = 2S
2S = S+30
2S-S = 30 (subtract S from both sides)
S = 30 (Son's current age) *answer*
D = S+20
D = 30+20

In ten years, Dad will be 60, which is twice Son's current age of 30.

Posted on Aug 27, 2010

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