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Given a current of 10amps and a resistance of 500ohms what is the voltage plz could u help me on this

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Ohms law can be applied here . When applying Ohms circuits are taken as perfect with no additional deviations to values introduced by connections or temperature, so although not exactly correct it is a very good guide. Almost all electical calcs can be done with Ohms law and its variations.

V(volts) = I(current) x R (resistance)

I x R =5000
so V =5000

Answer is 5000 Volts

Posted on Apr 30, 2008

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What could cause the fuel pump to have no power?

All cars, made. EFI
1: fuse good.?
2: ECU sees key on, some cars run pump for 3 seconds now, many don't, read FSM under fuel pump it's all there.

3: The ECU energizes the Fuel pump relay as you crank engine.
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1. Find voltage if the current I =0.2a and the resistance R=1000 ohms 2.Find the resistance if V=220V and I =5A

(Voltage) = (Current) x (Resistance)
1. Voltage is 200 Volts
2. Resistance is 44 Ohms

Sep 02, 2013 | Office Equipment & Supplies

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Which current are you referring to ??......

If you think of an electrical device as a piece of plumbing, voltage is the amount of water that you send down into the pipe, resistance is the pipe's relative width or narrowness, and current is the speed with which the water flows.
Power measures the water's relative difficulty or ease making its way through the pipe.
You relate all these values to one another using a common set of physics equations known as Ohm's law.
If you need to calculate electricity's current flow, you'll need to have at least two of the three values -- voltage, resistance or power -- listed above.

Calculate current flow using voltage and resistance.
According to Ohm's law, you can express electricity's current in amps as a ratio of its voltage in volts to the resistance of the device it's flowing through in ohms -- I = E/R, respectively.
For example, if you want to know the current flow of 220 V of electricity as it flows through a laptop computer with 80 ohms of resistance, you would simply plug these values into the equation as follows: I = 220/80 = 2.75 amps.
Calculate current flow using power and resistance.
Ohm's law also states that electrical current, "I," is equal to the square root of the power dissipated as it travels through the device divided by that device's resistance.
If a light bulb dissipates 80 watts of power and has a resistance of 55 ohms, you can calculate the electricity's current as follows: I = sqrt(80/55) = sqrt(1.4545) = 1.20 amps.

Calculate current flow using power and voltage.
If you have a space heater which dissipates 420 watts of power when it takes in 120 V of electricity, Ohm's law states you can calculate this electricity's current using the equation "I = P/E." For this example, compute current like so: I =420/120 = 3.5 amps.

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Higher resistance components and circuits will have significantly lower current flow (and lower wattages), so a higher voltage is supported and provides greater resolution of measured values on the meter.

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How to charge the lanzar 1.6 capacitor

typically you can charge or discharge large capacitors using a resistor. Not just any resistor will do. You will need one with high-enough resistance and wattage ratings or you'll burn up the resistor. I would use a 1/2W, 4.7kohm or a 1W, 1kohm. These are minimum values and you can use a slightly higher resistance but it will take longer to charge/discharge.

To charge, connect the positive terminal, then hold the resistor between the ground wire and the ground terminal for 30-60 seconds. Then connect the ground terminal. To discharge, disconnect both terminals, then hold the resistor across the terminals (do not reconnect terminals without charging). In either case, you can use your fingers to hold the resistor as DC will not shock you, but if the resistor gets hot it will burn you. I use needle-nose pliers to hold the resistor (just in case). Just be careful not to short the resistor leads or terminals with the pliers.

Explanation: For a standard cap 1 - 2 farads, the discharge voltage is up to 20V so we'll figure off of that. I would use at least a 1/2 watt resistor, a 1 watt could be safer, depending on the value. For a 1 watt, the current can be no more than .05A at 20V. For a 1/2 watt, only .025A. Let's say .04A and .02A, respectively. Ohms = Volts / Amps, so 20V / .04A gives us 500ohms. Double that to be safe (avoid overheating) and it's 1kohm. Same process for the 1/2W version will be 2kohm, but it's not as hefty, so I would recommend 4.7kohm.

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Getting Power everywhere is not cord. I have

Try reading the resistance on the coil itself. If your coil is damaged and has a high resistance the voltage will still read 120 volts, becuase there is no current. The voltage drop across the coil is equal to the resistance of the coil times the current. V = I * R. "I" being current. If the resistance of the coil is high because it is broken then the voltage will still read 120V. Another way is to read the current through the coil.

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I have a motorola v262 and just changed the keypad, but i can hear callers and they cannot hear me? can you help?


if you manage to change the keypad most probably the condenser MIC inside the phone been misaligned. try to check if the condeser MIC is properly sitted on it's original place and if you do have a multi tester you might as well check the resistance of the condenser MIC.
the nromal resistance for condeser MIC is 500ohms and some are 60 omhs.


Jan 17, 2009 | Motorola Mobility V262

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