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Heng pi - Nokia 6233 Cellular Phone

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Hi,

This problem is not clear to advice on what to do, please give more details on this problem.

Take care.

Posted on Aug 08, 2010

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Posted on Jan 02, 2017

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Jia heng lighter watch parts and configuration of components?


Jia Heng Butane Lighter Watch Battery Replacement

The battery replacement for the Jia Heng Butane Lighter Watch is fairly easy. The clock face actually gets removed from the lighter body. The only tools you will need are jewelers Phillips and slotted screwdrivers; Phillips and slotted.

Remove band by compressing spring pin with slotted screwdriver by pushing in the pin. These are standard watch band pins.Remove back 4 screws to remove backThe clock face is help on by 2 screws removed from the open back, there are at the 11 and 4 o'clock orientation when looking at the back.The front will drop off.Remove the plastic alignment spacer.Replace the 377 button battery.Put it back together by reversing the process.

Attached pictures
Front
Back
Clock face screws
Plastic alignment spacer
Battery placement

6da297ca-f5c4-44e1-ae26-1bea530bf139.jpg

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Find the trig function given its period cos 5 pi


cos(5PI)=cos(4PI+PI)=cos(PI)=-1
sin(19PI/6)=sin(18PI/6+ PI/6)=sin(3PI +Pi/6)=sin(2PI+PI+PI/6)=sin(PI+PI/6)=sin(-PI/6)=-sin(PI/6)=-1/2

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Windows xp not install heng problwm more restart


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To replace door hindge


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regards aniruddh

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Kalu heng tu masalnya pa,,,,,ya... hp nokia52000


Memory terlalu besar bisa,atau masang apikasi yg ga sesuai,maen game terlalu lama atau bisa juga virus.umumnya sih kepenuhaan memory,usahakan sisakan 25% dari kapasitas max mmc.moga membantu.

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Math problem


This sounds like someones homework. I'm risking my reputation here but here goes.

Previous Area was Pi x R x R. = Pi X 10 X 10 = 100 X Pi
Previous Perimeter is 2 X Pi X R = 2 X Pi X 10 = 20 X Pi

New shape is a rectangle with a semicircle at each end and width of 10 cm.
New Perimeter is circular bits + straight edges between them.
We know the circular bits but not how long the straight bits are so ...
Perimeter = 20 X Pi = (2 X Pi X 5) + L X 2 = 10 X Pi + (L X 2)
So L = (20 - 10) X Pi / 2 = 5 X Pi.

So the new Area is ... (Pi X 5 X 5) + (10 X 5 X Pi)
= 75 X Pi.
= 75 X 3.14 = 235.5

Nov 07, 2007 | Adobe Photoshop 7.0 (321115627)

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