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F(x)=2x+3;g(X)=x+1 - Computers & Internet

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Hi,

g(1) = 2(1) - 3 = -1

So f(g(1)) = f(-1) = (-1)² + 2 = 1 + 2 = 3

f(g(1)) = 3 <==ANSWER

A second way:

f(g(x)) = (2x - 3)² + 2 =

4x² - 12x + 9 + 2 =

4x² - 12x + 11

f(g(1)) = 4(1)² - 12(1) + 11 = 4 - 12 + 11 = 3

f(g(1)) = 3

There you go...

Posted on Aug 08, 2010

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2logx+log3\4-log(2x+3\4)=0


easy:
2log(x) + log(3/4) - log(2x + 3/4) = 0
log(x^2) + log(3/4) = log(2x + 3/4)
log(3/4*x^2) = log(2x + 3/4)
3/4*x^2 = 2x + 3/4
multiply equation by 4:
3x^2 = 8x + 3
3x^2 - 8x - 3 = 0
solve this quadratic eq. and you get
x1 = 3
x2 = -1/3

does it make sense?

Mar 05, 2017 | Computers & Internet

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All three sides of a triangle are equal in length of one side is 2x+5 and one side is 4x-3 find the perimeter of the triangle


If all sides are equal then 2x + 5 = 4x - 3
2x = 8
x = 4

so the perimeter is 3 times either expression above
3 * (8 + 5) = 39
.

Jan 12, 2017 | The Computers & Internet

1 Answer

2x plus 5y equals 7 3x plus 6y equals 3


1) 2x + 5y = 7
2) 3x + 6y = 3

I'm going to use the method of elimination to solve for x and y.
Multiply 1) by 3 and 2) by 2 to allow the x's to be eliminated.

1) 6x + 15y = 21
2) 6x + 12y = 6

Now subtract line 2 from line 1.

0x + 3y = 15
---- ----
3 3 divide both sides by 3 to get y by itself.
y =5.
Substitute into 1) to calculate x.
2x + 5(5) = 7
2x + 25 = 7
2x + 25 -25 = 7 - 25
2x = -18
---- ----- divide both sides by 2 to get x by itself
2 2

x = -9

Check by plugging in answer into the other equation, in this case 2)

3 (-9) + 6(5) = 3
-27 + 30 = 3
3 = 3
We did it correctly and checked to prove that we did it right.

Good luck.

Paul

Mar 12, 2015 | Office Equipment & Supplies

2 Answers

4x-(2x-3)=0


4x-(2x-3)=0
=>4x-2x+3=0 ; (after the bracket's oepned and multiplied by - [minus])
=>2x+3=0 ; taken x as common and 4-2=2 i.e. x(4-2) = 2x
=>2x=-3 ; +3's moved on the right-hand side, so it becomes -3
=>x=-3/2 ; 2 has been moved to the right-hand side and divided with -3 i.e 1/2 multiplied by -3 = -3/2

Hence, x = -3/2


Good luck.

Thanks for using FixYa.

Aug 13, 2010 | SoftMath Algebrator - Algebra Homework...

1 Answer

Differentiate each of the following w.r.t.x; 29.sin2xsinx


Use the rule for differentiating products of functions: ()' signifies derivative
(29*sin(2X)*sin(X))'= (29)'*sin(2X)*sin(X) +29* (sin(2X))'*sin(X) +29*sin(2X)*(sin(X))'
But
  1. (29)'=0 derivative of a constant is zero
  2. (sin(2X))'=cos(2X)*(2X)'=2*cos(2X)
  3. (sin(X))'=cos(X)
Result is
(29*sin(2X)*sin(X))'= 29*2*cos(2X)*sin(X)+29*sin(2X)*cos(X)

You could also have cast your formula in the form
sin(2X)*sin(X)= 1/2[ cos(2X-X)-cos(2X+X)]=1/2[cos(X)-cos(3X)]
then calculated the derivative of
29/2*[cos(X)-cos(3X)]
which is
29/2*[-si(X) +3*sin(3X)]

The challenge for you is to prove that the two forms are equivalent
29*2*cos(2X)*sin(X)+29*sin(2X)*cos(X)=29/2*[-si(X) +3*sin(3X)]

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1 Answer

Find three consecutive odd integers such that twice the product of the first two is 7 more than the product of last two


Hi,

Let's say your 3 numbers are a, b and c. Because they are consecutive and odd, you can write them like this:

a = 2x-1, b = 2x+1, c = 2x+3

Now, your problem looks like this:

2(2x-1)(2x+1) = (2x+1)(2x+3) + 7
2(4x^2-1) = 4x^2+6x+2x+3 + 7
8x^2-2 = 4x^2+8x+10
4x^2-8x-12 = 0
4(x^2-2x-3) = 0
x^2-2x-3 = 0

The solutions for this quadratic equation ( see more about this kind of equations here: http://en.wikipedia.org/wiki/Quadratic_equation ) are x=3 or x=-1. So, you've got two sets of solutions:

[1] a = 5, b = 7, c = 9
[2] a = -3, b = -1, c = 1


Take care,
Alex

Oct 15, 2009 | Google Computers & Internet

1 Answer

Find thier ages


Edwin is 14. Ruel is 7.

In 3 years Edwin will be 17. Edwin will be 10. (3*10 - 13 = 17)

Let x=Ruel's age now, and 2x=Edwin's age now.

2x+3=3(x+3)-13
2x+3=3x+9-13
2x+3=3x-4
2x+7=3x
7=x

If you are going to post these, the least you could do is rate them as Fixya. :-) Thanks!

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3 Answers

Algebra


Paul 3 years younger to his friend peter. In seven years, the product of their ages would be 5 more than the product of their ages 5 years ago. How old are they now?

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5 Answers

Algebra 1


B. 2((2-Y)/3)-Y=3
2(2-Y)-Y=9
4-2Y-Y=9
-3Y=9-4
-3Y=5
-Y=5/3
Y=-1.67

A. 3X+(-1.67)=2
3X-1.67=2
3X=2+1.67
3X=3.67
X=3.67/3
X=1.22

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