HOW DO U LOG OUT!!!!!!!!!!!???????????????????

Ad

In the upper right hand corner, click the Account dropdown, and "logout."

Posted on Aug 02, 2010

Ad

Hi,

To log out of your **Facebook** account, kindly click the **'Account'** tab at the top-right of the Facebook page and then select **'Logout' **from the drop-down menu. (*See attached image*)

Hope this solves your problem. Thanks for using **FixYa.**

Posted on Aug 02, 2010

Ad

Hi,

a 6ya expert can help you resolve that issue over the phone in a minute or two.

Best thing about this new service is that you are never placed on hold and get to talk to real repairmen in the US.

the service is completely free and covers almost anything you can think of.(from cars to computers, handyman, and even drones)

click here to download the app (for users in the US for now) and get all the help you need.

Goodluck!

Posted on Jan 02, 2017

Is the original problem (log 10,000 - log 1,000) / (4 log 1.0125) ? If so, press

( 1 0 0 0 0 LOG - 1 0 0 0 LOG ) / ( 4 * 1 . 0 1 2 5 LOG =

and you should see the expected result.

( 1 0 0 0 0 LOG - 1 0 0 0 LOG ) / ( 4 * 1 . 0 1 2 5 LOG =

and you should see the expected result.

Jul 25, 2011 | Office Equipment & Supplies

The answer for the problem log(4) - log(2) is actually 0.301, so the good news is that your calculator is working properly! Here's a quick breakdown of the solution for the problem:

1) We know that log(x) = N means that 10^N = x. So in this case, we need to find a number that 10 can be raised to in order to get 4 and 2.

2) To get a better idea of what the answer to the problem will be, we look at the scale of the numbers. 4 and 2 are both smaller than 10. In order to raise any number to a power and get a smaller number, that power must be less than 1. If the power was 1 or greater, the answer would be more than 10. Therefore, we know that log(4) is a decimal less than 1 and log(2) is a decimal less than 1.

3) Now we'll simplify the problem. A logarithm rule states that:

log(x) - log(y) = log(x/y)

We can use this rule to simplify the equation in the problem.

log(4) - log(2) = log(4/2)

Since 4/2 = 2,

log(4) - log(2) = log(4/2) = log(2)

4) Now to solve the equation, the only thing that must be calculated is log(2). This would be done on a calculator. In step 2, we analyzed that log(2) must be less than 1. Therefore, the calculator is correct with the answer 0.301.

Hope this helped!

1) We know that log(x) = N means that 10^N = x. So in this case, we need to find a number that 10 can be raised to in order to get 4 and 2.

2) To get a better idea of what the answer to the problem will be, we look at the scale of the numbers. 4 and 2 are both smaller than 10. In order to raise any number to a power and get a smaller number, that power must be less than 1. If the power was 1 or greater, the answer would be more than 10. Therefore, we know that log(4) is a decimal less than 1 and log(2) is a decimal less than 1.

3) Now we'll simplify the problem. A logarithm rule states that:

log(x) - log(y) = log(x/y)

We can use this rule to simplify the equation in the problem.

log(4) - log(2) = log(4/2)

Since 4/2 = 2,

log(4) - log(2) = log(4/2) = log(2)

4) Now to solve the equation, the only thing that must be calculated is log(2). This would be done on a calculator. In step 2, we analyzed that log(2) must be less than 1. Therefore, the calculator is correct with the answer 0.301.

Hope this helped!

Nov 30, 2010 | Texas Instruments TI-84 Plus Calculator

Calculate it the same way as on most other calculators, using the relation

log_b(x) = log(x)/log(b) = ln(x)/ln(b)

In words, calculate the log base 10 of x divided by the log base 10 of the base. You can also use the natural log function instead of the common (base 10) log--just be consistent.

log_b(x) = log(x)/log(b) = ln(x)/ln(b)

In words, calculate the log base 10 of x divided by the log base 10 of the base. You can also use the natural log function instead of the common (base 10) log--just be consistent.

Oct 19, 2010 | DateXX DS-883 Calculator

The natural log is the LN key, located just to the left of the 7 key.

To calculate the common log, use the relationship log(x) = ln(x)/ln(10).

To calculate the natural log of 3, press 3 LN

To calculate the common log of 3, press 3 LN / 1 0 LN =

To calculate the common log, use the relationship log(x) = ln(x)/ln(10).

To calculate the natural log of 3, press 3 LN

To calculate the common log of 3, press 3 LN / 1 0 LN =

Aug 09, 2010 | Texas Instruments BA-II Plus Calculator

LOG 1 . 9 ) / 4 LOG 1 . 0 1 7 5 ENTER

Jul 05, 2010 | Texas Instruments TI-83 Plus Calculator

It's simple here some logs:

log x base y = log x / log y

log (x*y) = log x + log y

log (x/y) = log x - log y

you just need to know that the default base of log in calculators is 10, so log x mean

log x base 10 = log x / log 10,

so write log x / log y for log x base y example:

log 8 base 2 = log 8 / log 2 that is how you write it on calculator, hope it was helpful

log x base y = log x / log y

log (x*y) = log x + log y

log (x/y) = log x - log y

you just need to know that the default base of log in calculators is 10, so log x mean

log x base 10 = log x / log 10,

so write log x / log y for log x base y example:

log 8 base 2 = log 8 / log 2 that is how you write it on calculator, hope it was helpful

Jul 01, 2009 | Texas Instruments TI-83 Plus Calculator

Look the calculators has a default base 10 and you can't change it but you may learn this:

log x base y = log x / log y

log (x*y) = log x + log y

log (x/y) = log x - log y

so instead input log 8 base 2 you need to input log 8 / log 2

your example answer is about 0.919... if i get right what did you write.

Glad to help :)

log x base y = log x / log y

log (x*y) = log x + log y

log (x/y) = log x - log y

so instead input log 8 base 2 you need to input log 8 / log 2

your example answer is about 0.919... if i get right what did you write.

Glad to help :)

Feb 21, 2009 | HP 33s Calculator

Yes look you can't enter the base in calculators it's default 10 so use:

log x base y = log x / log y

log (x*y) = log x + log y

log (x/y) = log x - log y

so instead of log 8 base 2 input log 8 / log 2 it's easy

hope you understand :)

log x base y = log x / log y

log (x*y) = log x + log y

log (x/y) = log x - log y

so instead of log 8 base 2 input log 8 / log 2 it's easy

hope you understand :)

Feb 21, 2009 | Sharp EL-531VB Calculator

It's 2*3=6 but about the base, you can't change it in the calculators the default base it's 10 so log x it's Logbase 10^x here some logs:

log x base y = log x / log y

log (x*y) = log x + log y

log (x/y) = log x - log y

in your example log 9 base 3 = log 9 / log 3 etc.

hope you get it, and it was helpful

log x base y = log x / log y

log (x*y) = log x + log y

log (x/y) = log x - log y

in your example log 9 base 3 = log 9 / log 3 etc.

hope you get it, and it was helpful

Nov 12, 2008 | Texas Instruments TI-89 Calculator

Here something that would help you:

log x base y = log x / log y

log (x*y) = log x + log y

log (x/y) = log x - log y

so log 24 base 2 it's log 24 / log 2 etc.

and if i get right what you wrote x= 10 ^ ( 3 * (log 5) ) if no inverse it it's easy really Hope it's helped you.

log x base y = log x / log y

log (x*y) = log x + log y

log (x/y) = log x - log y

so log 24 base 2 it's log 24 / log 2 etc.

and if i get right what you wrote x= 10 ^ ( 3 * (log 5) ) if no inverse it it's easy really Hope it's helped you.

Oct 23, 2008 | Casio FX-260 Calculator

80 people viewed this question

Usually answered in minutes!

×