HOW DO U LOG OUT!!!!!!!!!!!???????????????????

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In the upper right hand corner, click the Account dropdown, and "logout."

Posted on Aug 02, 2010

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Hi,

To log out of your **Facebook** account, kindly click the **'Account'** tab at the top-right of the Facebook page and then select **'Logout' **from the drop-down menu. (*See attached image*)

Hope this solves your problem. Thanks for using **FixYa.**

Posted on Aug 02, 2010

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Posted on Jan 02, 2017

Is the original problem (log 10,000 - log 1,000) / (4 log 1.0125) ? If so, press

( 1 0 0 0 0 LOG - 1 0 0 0 LOG ) / ( 4 * 1 . 0 1 2 5 LOG =

and you should see the expected result.

( 1 0 0 0 0 LOG - 1 0 0 0 LOG ) / ( 4 * 1 . 0 1 2 5 LOG =

and you should see the expected result.

Jul 25, 2011 | Office Equipment & Supplies

The answer for the problem log(4) - log(2) is actually 0.301, so the good news is that your calculator is working properly! Here's a quick breakdown of the solution for the problem:

1) We know that log(x) = N means that 10^N = x. So in this case, we need to find a number that 10 can be raised to in order to get 4 and 2.

2) To get a better idea of what the answer to the problem will be, we look at the scale of the numbers. 4 and 2 are both smaller than 10. In order to raise any number to a power and get a smaller number, that power must be less than 1. If the power was 1 or greater, the answer would be more than 10. Therefore, we know that log(4) is a decimal less than 1 and log(2) is a decimal less than 1.

3) Now we'll simplify the problem. A logarithm rule states that:

log(x) - log(y) = log(x/y)

We can use this rule to simplify the equation in the problem.

log(4) - log(2) = log(4/2)

Since 4/2 = 2,

log(4) - log(2) = log(4/2) = log(2)

4) Now to solve the equation, the only thing that must be calculated is log(2). This would be done on a calculator. In step 2, we analyzed that log(2) must be less than 1. Therefore, the calculator is correct with the answer 0.301.

Hope this helped!

1) We know that log(x) = N means that 10^N = x. So in this case, we need to find a number that 10 can be raised to in order to get 4 and 2.

2) To get a better idea of what the answer to the problem will be, we look at the scale of the numbers. 4 and 2 are both smaller than 10. In order to raise any number to a power and get a smaller number, that power must be less than 1. If the power was 1 or greater, the answer would be more than 10. Therefore, we know that log(4) is a decimal less than 1 and log(2) is a decimal less than 1.

3) Now we'll simplify the problem. A logarithm rule states that:

log(x) - log(y) = log(x/y)

We can use this rule to simplify the equation in the problem.

log(4) - log(2) = log(4/2)

Since 4/2 = 2,

log(4) - log(2) = log(4/2) = log(2)

4) Now to solve the equation, the only thing that must be calculated is log(2). This would be done on a calculator. In step 2, we analyzed that log(2) must be less than 1. Therefore, the calculator is correct with the answer 0.301.

Hope this helped!

Nov 30, 2010 | Texas Instruments TI-84 Plus Calculator

Calculate it the same way as on most other calculators, using the relation

log_b(x) = log(x)/log(b) = ln(x)/ln(b)

In words, calculate the log base 10 of x divided by the log base 10 of the base. You can also use the natural log function instead of the common (base 10) log--just be consistent.

log_b(x) = log(x)/log(b) = ln(x)/ln(b)

In words, calculate the log base 10 of x divided by the log base 10 of the base. You can also use the natural log function instead of the common (base 10) log--just be consistent.

Oct 19, 2010 | DateXX DS-883 Calculator

The natural log is the LN key, located just to the left of the 7 key.

To calculate the common log, use the relationship log(x) = ln(x)/ln(10).

To calculate the natural log of 3, press 3 LN

To calculate the common log of 3, press 3 LN / 1 0 LN =

To calculate the common log, use the relationship log(x) = ln(x)/ln(10).

To calculate the natural log of 3, press 3 LN

To calculate the common log of 3, press 3 LN / 1 0 LN =

Aug 09, 2010 | Texas Instruments BA-II Plus Calculator

LOG 1 . 9 ) / 4 LOG 1 . 0 1 7 5 ENTER

Jul 05, 2010 | Texas Instruments TI-83 Plus Calculator

It's simple here some logs:

log x base y = log x / log y

log (x*y) = log x + log y

log (x/y) = log x - log y

you just need to know that the default base of log in calculators is 10, so log x mean

log x base 10 = log x / log 10,

so write log x / log y for log x base y example:

log 8 base 2 = log 8 / log 2 that is how you write it on calculator, hope it was helpful

log x base y = log x / log y

log (x*y) = log x + log y

log (x/y) = log x - log y

you just need to know that the default base of log in calculators is 10, so log x mean

log x base 10 = log x / log 10,

so write log x / log y for log x base y example:

log 8 base 2 = log 8 / log 2 that is how you write it on calculator, hope it was helpful

Jul 01, 2009 | Texas Instruments TI-83 Plus Calculator

Look the calculators has a default base 10 and you can't change it but you may learn this:

log x base y = log x / log y

log (x*y) = log x + log y

log (x/y) = log x - log y

so instead input log 8 base 2 you need to input log 8 / log 2

your example answer is about 0.919... if i get right what did you write.

Glad to help :)

log x base y = log x / log y

log (x*y) = log x + log y

log (x/y) = log x - log y

so instead input log 8 base 2 you need to input log 8 / log 2

your example answer is about 0.919... if i get right what did you write.

Glad to help :)

Feb 21, 2009 | HP 33s Calculator

Yes look you can't enter the base in calculators it's default 10 so use:

log x base y = log x / log y

log (x*y) = log x + log y

log (x/y) = log x - log y

so instead of log 8 base 2 input log 8 / log 2 it's easy

hope you understand :)

log x base y = log x / log y

log (x*y) = log x + log y

log (x/y) = log x - log y

so instead of log 8 base 2 input log 8 / log 2 it's easy

hope you understand :)

Feb 21, 2009 | Sharp EL-531VB Calculator

It's 2*3=6 but about the base, you can't change it in the calculators the default base it's 10 so log x it's Logbase 10^x here some logs:

log x base y = log x / log y

log (x*y) = log x + log y

log (x/y) = log x - log y

in your example log 9 base 3 = log 9 / log 3 etc.

hope you get it, and it was helpful

log x base y = log x / log y

log (x*y) = log x + log y

log (x/y) = log x - log y

in your example log 9 base 3 = log 9 / log 3 etc.

hope you get it, and it was helpful

Nov 12, 2008 | Texas Instruments TI-89 Calculator

Here something that would help you:

log x base y = log x / log y

log (x*y) = log x + log y

log (x/y) = log x - log y

so log 24 base 2 it's log 24 / log 2 etc.

and if i get right what you wrote x= 10 ^ ( 3 * (log 5) ) if no inverse it it's easy really Hope it's helped you.

log x base y = log x / log y

log (x*y) = log x + log y

log (x/y) = log x - log y

so log 24 base 2 it's log 24 / log 2 etc.

and if i get right what you wrote x= 10 ^ ( 3 * (log 5) ) if no inverse it it's easy really Hope it's helped you.

Oct 23, 2008 | Casio FX-260 Calculator

Jul 27, 2018 | Facebook Social Network

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