Question about Computers & Internet

Ad

Hi,

a 6ya expert can help you resolve that issue over the phone in a minute or two.

best thing about this new service is that you are never placed on hold and get to talk to real repairmen in the US.

the service is completely free and covers almost anything you can think of (from cars to computers, handyman, and even drones).

click here to download the app (for users in the US for now) and get all the help you need.

goodluck!

Posted on Jan 02, 2017

Ad

SOURCE: EUROVOX MAX V - North East /Mbro

ok try this to sory your problem out. Press menu, 1570 , on nagravision screen is EMU set to ON ?

press ok , code screen make sure this is in box . Provider ID NTL 5401,

key 0. 3F B8 36 62 72 E5 E2 76

key 1. 35 5E D6 40 6E AA 99 41

should work fine now .good luck.

Posted on Dec 16, 2008

Ad

SOURCE: trig and distance

Debs,

this is solved by starting with the SECOND leg of the flight considered as a triangle.

Find how far DUE east the plane travels (100 km x Cos10 = 83.9 km) using 10 degrees because that is how much is left of the 90 degree quadrent after subtracting the 80 degrres course direction.

Similarly find out how far DUE north the plane travels (100 km x Cos80 = 11 km).

Now get the total flight NORTH = 300 + 11 = 311

- and total EAST = 83.9

Finally, use Pythagoras theorem.to get the total DISTANCE:

square root of ( 311 squared + 83 squared ) = 321 km

Also the DIRECTION from its Tangent of 83 /311 = 14.9 degrees

Posted on Dec 19, 2008

SOURCE: code for telewest north east starview plz

any one got codes for the box

Posted on May 18, 2009

SOURCE: compass is no longer pointing North

I had the same issue. I found that if you re-calibrate the compass the same way you did the first time, then it will act properly. I've had to do this a couple of times and it works.

Posted on Jun 29, 2009

SOURCE: a person walks 25.degree north

(r, theta) --> (3.10 km, 25 degrees)

[r = 3.10 km; theta = 25 degrees]

x = rcostheta

y = rsintheta

x, in this case, would be the horizontal, or eastward distance, so the appropriate values would be substituted in the x equation to solve for it.

x = 3.10 * (cos25) = 2.81 km

y would be the vertical, or northward distance, so the appropriate values would be substituted in the y equation to solve for it.

y = 3.10 * (sin25) = 1.31 km

To verify the solutions, here is the optional step: (just to be sure!)

r = sqrt (x^2 + y^2)

r = sqrt (2.81^2 + 1.31^2)

r = 3.0999 --> 3.10 km

Therefore, the person must walk 1.31 km due north and 2.81 km due east to arrive at the same location.

Posted on Sep 20, 2012

Just add the three vectors together. The first vector is 0.0i + 4.0j . The second vector is about 1.4i - 1.4j . The third is about -0.7i - 0.7j .

Adding the three vectors together gives about 0.7i + 1.9j .The exact answer is sqrt(0.5)i + (4.0-3sqrt(0.5))j .

Adding the three vectors together gives about 0.7i + 1.9j .The exact answer is sqrt(0.5)i + (4.0-3sqrt(0.5))j .

Mar 15, 2013 | Camping, Backpacking & Hiking

3.10 km times sine of 25 degrees is about 1.31 km.

3.10 km times cosine of 25 degrees is about 2.81 km.

The person would have to walk 1.31 km north and 2.81 km east.

Since you didn't specify the make and model of your calculator, I'm afraid I can't give you the keystroke sequences to calculate these results.

3.10 km times cosine of 25 degrees is about 2.81 km.

The person would have to walk 1.31 km north and 2.81 km east.

Since you didn't specify the make and model of your calculator, I'm afraid I can't give you the keystroke sequences to calculate these results.

Jul 04, 2011 | Office Equipment & Supplies

a person walks 25.degree north of east for 3.10 km.How far would she have to walk due north and due east to arrive at the same location?

Jul 04, 2011 | Vector Power On Board High Intensity...

Since there are by definition 100 cm in a meter, the distance is 50x100 or 5000 cm. At 1cm/s it takes the ant 5000 seconds to cover the distance. There are 60 seconds in a minute, so it takes 83 minutes and 20 seconds.

Sep 14, 2010 | Casio FX-115ES Scientific Calculator

draw a right triangle. The bottom of the triangle is 29.6 cm and the angle is 52 degrees (from the other edge). note: triangle not to scale.

| \

|52 \

| \

| \

| \ |

|_____38\ 52|

29.6

Therefore the inside of the angle is 38 (90-52) and the opp angle is also 52 (90-38)

sine = opp / hyp therefore hyp = opp / sine

length of hypotenuse is: 29.6 * sine 52 deg.

therefore the length of the hypotenuse is 23.32511 cm. the ant travels 1.4 cm / sec so the ant travels to the other edge in 16.66 seconds.

| \

|52 \

| \

| \

| \ |

|_____38\ 52|

29.6

Therefore the inside of the angle is 38 (90-52) and the opp angle is also 52 (90-38)

sine = opp / hyp therefore hyp = opp / sine

length of hypotenuse is: 29.6 * sine 52 deg.

therefore the length of the hypotenuse is 23.32511 cm. the ant travels 1.4 cm / sec so the ant travels to the other edge in 16.66 seconds.

Oct 21, 2009 | Whirlpool LER4634J Electric Dryer

The answer is 0.

Jun 28, 2009 | Welding Tools

I had the same issue. I found that if you re-calibrate the compass the same way you did the first time, then it will act properly. I've had to do this a couple of times and it works.

Jun 12, 2009 | Timex Expedition E Compass Watch Titanium...

Debs,

this is solved by starting with the SECOND leg of the flight considered as a triangle.

Find how far DUE east the plane travels (100 km x Cos10 = 83.9 km) using 10 degrees because that is how much is left of the 90 degree quadrent after subtracting the 80 degrres course direction.

Similarly find out how far DUE north the plane travels (100 km x Cos80 = 11 km).

Now get the total flight NORTH = 300 + 11 = 311

- and total EAST = 83.9

Finally, use Pythagoras theorem.to get the total DISTANCE:

square root of ( 311 squared + 83 squared ) = 321 km

Also the DIRECTION from its Tangent of 83 /311 = 14.9 degrees

this is solved by starting with the SECOND leg of the flight considered as a triangle.

Find how far DUE east the plane travels (100 km x Cos10 = 83.9 km) using 10 degrees because that is how much is left of the 90 degree quadrent after subtracting the 80 degrres course direction.

Similarly find out how far DUE north the plane travels (100 km x Cos80 = 11 km).

Now get the total flight NORTH = 300 + 11 = 311

- and total EAST = 83.9

Finally, use Pythagoras theorem.to get the total DISTANCE:

square root of ( 311 squared + 83 squared ) = 321 km

Also the DIRECTION from its Tangent of 83 /311 = 14.9 degrees

Dec 19, 2008 | Super Tutor Trigonometry (ESDTRIG) for PC

Oct 23, 2017 | Computers & Internet

Oct 23, 2017 | Computers & Internet

31 people viewed this question

Usually answered in minutes!

×