Question about Prentice Hall College Algebra Enhanced with Graphing Utilities Value Package (includes Ma

1 Answer

The perimeter of a rectangular field is 338 yards. If the length of the field is 95 yards, what is its width?

Posted by on

Ad

1 Answer

  • Level 2:

    An expert who has achieved level 2 by getting 100 points

    MVP:

    An expert that got 5 achievements.

    Sergeant:

    An expert that has over 500 points.

    Governor:

    An expert whose answer got voted for 20 times.

  • Expert
  • 170 Answers

148 yds

Posted on Jul 31, 2010

Ad

1 Suggested Answer

6ya6ya
  • 2 Answers

SOURCE: I have freestanding Series 8 dishwasher. Lately during the filling cycle water hammer is occurring. How can this be resolved

Hi,
a 6ya expert can help you resolve that issue over the phone in a minute or two.
best thing about this new service is that you are never placed on hold and get to talk to real repairmen in the US.
the service is completely free and covers almost anything you can think of (from cars to computers, handyman, and even drones).
click here to download the app (for users in the US for now) and get all the help you need.
goodluck!

Posted on Jan 02, 2017

Ad

Add Your Answer

Uploading: 0%

my-video-file.mp4

Complete. Click "Add" to insert your video. Add

×

Loading...
Loading...

Related Questions:

1 Answer

Find the perimeter and area of a rectangle with a length of 11 yards and a width of 12 yards


the perimeter of any square sided object is 2 times the height added to 2 times the width: (2h)+(2w). The actual answer for your sizes is 46 yards given by 2 times 11 plus 2 times 12. Hope this helps.

Aug 03, 2017 | The Computers & Internet

1 Answer

Would like to calculate the dimensions of a rectangular pool with a perimeter of 55 meters using decimals only


Let's break down the question to its components.

It is a rectangular pool. It has four sides, with a length and width and the angles in corners being 90 degrees.

Let l be the length of the pool.
Let w be the width of the pool.

The perimeter of the pool is l + l + w + w or 2l + 2w

So 2l + 2w = 55 metres

You could make up a table for all the possible values, starting with a width of 1. 2(1) + 2w = 55
2 + 2w = 55
2w = 53
w = 53 /2

Good luck,

Paul

Feb 09, 2017 | The Office Equipment & Supplies

1 Answer

The length, l, of a rectangle is 5/2 its width, w. The length, l, of the rectangle is 10 inches. What is the perimeter of the rectangle? What Iis the area of the rectangle, in sauare inches?


We are given the following data:

length = 5/2 * width
length = 10 inWe know through the transitive

property of equality that the following must be true:

5/2 * width = 10 in

We then solve this equation algebraically for width:

width = (10 in) * 2/5
width = 4 in

The perimeter of the rectangle is given by substituting our known values of length and width into the following general equation:

Perimeter = 2 * length + 2 * width
Perimeter = 2(10 in) + 2(4 in) = 28 in

In a similar fashion, we substitute these known values into the general equation for the area of the rectangle to solve for the same:

Area = length * width
Area = (10 in)(4 in)=40 in^2

Nov 29, 2016 | The Computers & Internet

1 Answer

The perimeter of a rectangle is 600 yards. what are the dimensions of the rectangle if the length is 20 yards more then the width


160 by 140

The perimeter is 600, so 2w+2l=600 where w is the width and l is the length.
Divide both sides by 2: w+l=300
The length is 20 more than the width: l=w+20
Substituting in the previous equation: w+(w+20)=300
Collecting terms: 2w+20=300
Subtract 20 from both sides: 2w=280
Divide by 2: w=140
Thus the width is 140. Substituting into the equation for length: l=140+20
Simplifying: l=160
The width is 140 and the length is 160

Sep 15, 2014 | MathAid Algebra II

2 Answers

How do you solve a rectangle is eight inches longer than its width. find the dimensions of the rectangle if the perimeter is 60 cm


The rectangle is 11cm by 19cm.

The perimeter is 60, so the width and length must add to 30. The length is 8 more than the width, or width+width+8=30. Solve that for width, then you can calculate the length based on the width.

If this is homework, be sure to show your work.

Oct 11, 2013 | Lands Phones

1 Answer

A rectan Dear Madam Please look at the math questions below. Please help me solve the questions Question 1 : A rectangular tablecloth is 2.5 m long. Trim is to be sewn around the perimeter of the cloth...


1. Well this one is pretty simple. Since you are not supposed to trim the length trim the width instead.
to make the perimeter 0.4 m shorter cut the cloth by 0.2 m width the picture will make it clear.
champ_guru.jpg


2. let the length of rectangle be x cm
and breadth = 20 cm
now original perimeter = 2(x+20) cm


new length = x-30 cm
breadth remains same = 20 cm
new perimeter = 2(x-30+20) cm = 2(x-10) cm

According to question

new perimeter = old perimeter /2
2(x-10) = 2(x+20) /2
2x -20 = x + 20
x = 40 cm


hence length of longer side 40 cm.

If you want to directly comm ankitsharma.220@gmail.com

Feb 13, 2011 | Vivendi Excel@ Mathematics Study Skills...

1 Answer

What is rectangular prism?


Hello
Rectangular Prism/Cuboid Definition:
A Rectangular Prism/Cuboid is a solid figure bounded by six rectangular faces, a rectangular box. All angles are right angles, and opposite faces of a cuboid are equal. It is also a right rectangular prism.

Rectangular Prism/Cuboid Formula:
Area of Base(A) = l * w
Perimeter of Base(P) = 2l + 2w
Surface Area of Prism = 2(lw) + (2l + 2w)h = 2A + Ph
Volume of Prism = lwh = Ah
Diagonal of Prism = Sqrt(l² + w² + h²)
where
l = length, w = width, h = height

Hope this helps, if so do rate the solution

Jan 15, 2011 | MathRescue Word Problems Of Algebra Lite

2 Answers

The perimeter of a rectangular field is 628 meters. The length of the field exceeds its width by 6 meters. What is the demensions.


Let x = the short side. Then the long side is the short side plus 6 meters
now we have 2 sides that are x meters long, add those together gives us 2x for the length
of both short sides

The length of the long side is x + 6 for one side and x + 6 for the other side. Added together we have x + 6 + x + 6 = 2x + 12

Adding the 4 sides together we get 2x ( the 2 short sides) + 2x + 12 (the long sides) we get 4x + 12 = the perimeter or 628. 4x + 12 = 628. Subtract 12 from both sides of the equation leaves 4x = 616. divide both sides by 4 leaves x = 154 So the width is 154 meters and the length is 160 meters.

Hope this helps

Good luck Loringh

Oct 06, 2008 | SoftMath Algebrator - Algebra Homework...

Not finding what you are looking for?
Prentice Hall College Algebra Enhanced with Graphing Utilities Value Package (includes Ma Logo

Related Topics:

157 people viewed this question

Ask a Question

Usually answered in minutes!

Top Prentice Hall Computers & Internet Experts

Captain Ashish

Level 3 Expert

118 Answers

k24674

Level 3 Expert

7993 Answers

kakima

Level 3 Expert

102366 Answers

Are you a Prentice Hall Computer and Internet Expert? Answer questions, earn points and help others

Answer questions

Manuals & User Guides

Loading...