# Twenty-five numbers are entered from the keyboard into an array.The number to be searched is entered through the keyboard by user.Write a program to find if the number to be searched is present in the array and if it is present,display the number of times it appears in the array.

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Pseudo is
-> integer type count =0;
->Take input from user 'Number'
->loop from 0th to 24th element
->Compare each element with user entered number and if it matches then do count++.
finally display the count.

Posted on Aug 10, 2010

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## Related Questions:

### Write a program that accept a number and output its equivalent in words.

Below is the program written in Turbo C.

#include<stdio.h>
void pw(long,char[]);
char *one[]={" "," one"," two"," three"," four"," five"," six"," seven","
eight"," Nine"," ten"," eleven"," twelve"," thirteen"," fourteen","
fifteen"," sixteen"," seventeen"," eighteen"," nineteen"};
char *ten[]={" "," "," twenty"," thirty"," forty"," fifty"," sixty","
seventy"," eighty"," ninety"};

void main()
{
long n;
clrscr();
printf("
Enter any 9 digit no: ");
scanf("%9ld",&n);
if(n<=0)
printf("Enter numbers greater than 0");
else
{
pw((n/10000000),"crore");
pw(((n/100000)%100),"lakh");
pw(((n/1000)%100),"thousand");
pw(((n/100)%10),"hundred");
pw((n%100)," ");
}
getch();
}

void pw(long n,char ch[])
{
(n>19)?printf("%s %s ",ten[n/10],one[n%10]):printf("%s ",one[n]);
if(n)printf("%s ",ch);
}

Aug 06, 2010 | Borland Turbo C++ Suite 1.0...

Tip

### HOW TO COUNT THE OCCURRENCES OF A TEXT STRING

In the cell that you want the result to appear in, enter the appropriate formula from the following examples.
How to Count the Occurrences of a Number
Use this formula
=SUM(IF(range=number,1,0))
where range is the range that you want to search, and number is the number that you want to count.
NOTE: This formula must be entered as an array formula. To enter an array formula, press CTRL+SHIFT+ENTER.
How to Count the Occurrences of a Text String
Method 1
Use this formula
=SUM(IF(range="text",1,0))
where range is the range that you want to search, and text is the text that you want to find (the text must be enclosed in quotation marks).
NOTE: The above formula must be entered as an array formula. To enter an array formula, press CTRL+SHIFT+ENTER.
Method 2
Use the COUNTIF() function to count the occurrences of a text string. For example, use the formula
=COUNTIF(range,"text")
where range is the range of cells that you are evaluating, and text is the text string that you want to count instances of (note that text must be enclosed in quotation marks).
NOTE: This formula must be entered as an array formula. To enter an array formula, press CTRL+SHIFT+ENTER.
Wildcard characters can be used within the COUNTIF function.
The asterisk character (*) represents more than one character. For example, to count all the cells in the range a1:a10 that contain an "x," you can use the following formula:
=COUNTIF(a1:a10,"*x*")
The question mark character (?) can also be used to represent one wildcard character -- for example, to count all cells in the range whose second character is the letter, such as "ax" or "bx."
=COUNTIF(a1:a10,"?x*")

on Nov 11, 2013 | Microsoft Excel Computers & Internet

### Hwo can i solved a bineary search problam in c++

first arrange your array in ascending order.and keep the two variables one for starting index and one for last index
then check your number with center(center = (first index + last index))/2 element of array.
if it is lager then center element then set first index = center,
if smaller then last index = center
else you got the number..

Jul 25, 2010 | Borland Turbo C++ Suite 1.0...

### Make a program that will accept tthe size of an array (number must be greater than). Enter and fill the array with numbers then sort in descending order (largest to smallest). Display the unsorted and...

coding in C++

#include<iostream.h>
#include<conio.h>
#define max 50

void main()
{
clrscr();
int arr[max],size=0;
int i=0,j=0,temp;
do
{
cout<<"Enter the size of array(less than or equal to 50)";
cin>>size;
} while(size>50);

for(i=0;i<size;i++){
cout<<"Enter a number";
cin>>arr[i];
}

for( i=1;i<size;i++){
for(j=0;j<size;j++){
if(arr[j+1]>arr[j]){
temp = arr[j];
arr[j] = arr[j+1];
arr[j+1] = temp;

}

}
}
cout<<”Array in descending order”;
for(i=0;i<size;i++){
cout<<arr[i]<<"\n";
}
getch();
return 0;
}

Mar 09, 2010 | Computers & Internet

### C++ poker program

Hi.

I suggest creating an Array of Cards (cardOne,cardTwo,etc. to five)

If you can enter them in one at a time, after declaring the array, assign the values to the array.

cin < cardOne; (Psuedo code by the way, hope you don't mind)

Afterwards, you'll have an array with 5 cards.

Declare what full houses, flushes, etc would require.
Use an if statement (If you don't mind lots of code) to compare the entered Array against possible hands.

I didn't necessarily give you any specific C++ code. However, if you Google C++ user input, you should find plenty of commands that may help you.

Good Luck

(And not sure about Linear search to be honest, you can use a Linear search, but if you did it the way I explained, you just have to compare hand to a series of conditionals.)

Sep 23, 2009 | Computers & Internet

### C++

http://www.cplusplus.com/doc/tutorial/

May 01, 2009 | Computers & Internet

### Please Solve this C++ Program

Write a program to prompt the user to input several lines of input. A line of inputs is terminated by '*'. For each readline of input the program should output:(use pointer notation for the array) . The total # of words . The lenght of the longest word in the line At the end the program should output: . The total number of words read in all lines of input . The lenght of the longest word read in all lines of input

Jan 19, 2009 | Computers & Internet

### Apex Digital GB4308 remote

Jan 05, 2007 | Apex Digital GB4308 43" Rear Projection...

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