Question about Mathsoft StudyWorks! Mathematics Deluxe 5.0 (11513) for PC

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Posted on Jan 02, 2017

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You should feel happy that your calculator can perform some exact calculations. If you do not want the exact values you can press the SD key. You can also press SHIFT EXE rather than EXE alone.

Dec 07, 2016 | Office Equipment & Supplies

x^2 squares the value (multiplies by itself), x^-1 inverts it (divides it into one), x! calculates the factorial, and square root calculates the square root.

Feb 20, 2014 | Casio FX-9750GPlus Calculator

(Square root(7))*(Square root (15))=(Square root (7*15)=Square root(105)

Mar 29, 2012 | MathRescue Word Problems Of Algebra Lite

Hi rayalak857,

Have a nice day.

Calculator does not have a solve program, but you can use it to solve the quadratic equation with a little effort. If you know the theory skip toward the end.

Here is the example:

Let aX^2+bX+C=0

1. First calculate the discriminant usually called Delta and given by

Delta =b^2 -4*a*c store the value in the variable D

If Delta is positive you have two roots X1 and X2 given by

X1=(-b+square root of Delta)/(2*a)

X2=(-b- square root of Delta)/(2*a)

If Delta is equal to 0, X1=X2=-b/(2*a)

If Delta i negative, no real solutions exist

You only solve if Delta is positive or equal to 0.

Putting in the values of a, b, and c

value of a (put you number) [SHIFT][STO] A

value of b (put your value) [SHIFT][STO] B

value of c (put you value) [SHIF][STO] C

[ALPHA] B [X^2] -4[x][ALPHA] A [x][ALPHA] C [=]

Value of delta is displayed. If it is positive, you store its square root in D

[Square root] [ANS] [SHIFT][STO] D ;

Calculate 1/(2*a) and store in variable F

1./(2[x] ALPHA A) [SHIFT][STO] F

To obtain X1

[ALPHA] F [x] ( (-) ALPHA B + ALPHA D ) [=]

To obtain X2

[ALPHA] F [x] ( (-) ALPHA B - ALPHA D ) [=]

Be careful: the (-) is the change sign not the regular minus sign.

Hope it helps. Goodluck

Thank you for using fixya.

Have a nice day.

Calculator does not have a solve program, but you can use it to solve the quadratic equation with a little effort. If you know the theory skip toward the end.

Here is the example:

Let aX^2+bX+C=0

1. First calculate the discriminant usually called Delta and given by

Delta =b^2 -4*a*c store the value in the variable D

If Delta is positive you have two roots X1 and X2 given by

X1=(-b+square root of Delta)/(2*a)

X2=(-b- square root of Delta)/(2*a)

If Delta is equal to 0, X1=X2=-b/(2*a)

If Delta i negative, no real solutions exist

You only solve if Delta is positive or equal to 0.

Putting in the values of a, b, and c

value of a (put you number) [SHIFT][STO] A

value of b (put your value) [SHIFT][STO] B

value of c (put you value) [SHIF][STO] C

[ALPHA] B [X^2] -4[x][ALPHA] A [x][ALPHA] C [=]

Value of delta is displayed. If it is positive, you store its square root in D

[Square root] [ANS] [SHIFT][STO] D ;

Calculate 1/(2*a) and store in variable F

1./(2[x] ALPHA A) [SHIFT][STO] F

To obtain X1

[ALPHA] F [x] ( (-) ALPHA B + ALPHA D ) [=]

To obtain X2

[ALPHA] F [x] ( (-) ALPHA B - ALPHA D ) [=]

Be careful: the (-) is the change sign not the regular minus sign.

Hope it helps. Goodluck

Thank you for using fixya.

Sep 13, 2011 | Casio FX-300MS Calculator

Easy. Give me something harder next time :)

Sep 15, 2010 | The Learning Company Learn to Speak...

To convert a single value to decimal, press Diamond then ENTER. To get them all that way, press MODE then F2. Scroll down to Exact/Approx and change it from Auto or Exact to Approximate.

May 12, 2010 | Texas Instruments TI-89 Calculator

Hello,

The calculator does not have a solve program, but you can still use it to solve the quadratic equation with a little effort. If you know the therory skip toward the end.

Let aX^2+bX+C=0

1. First calculate the discriminant usually called Delta and given by

Delta =b^2 -4*a*c store the value in the variable D

If Delta is positive you have two roots X1 and X2 given by

X1=(-b+square root of Delta)/(2*a)

X2=(-b- square root of Delta)/(2*a)

If Delta is equal to 0, X1=X2=-b/(2*a)

If Delta i negative, no real solutions exist

You only solve if Delta is positive or equal to 0.

Putting in the values of a, b, and c

value of a (put you number) [SHIFT][STO] A

value of b (put your value) [SHIFT][STO] B

value of c (put you value) [SHIF][STO] C

[ALPHA] B [X^2] -4[x][ALPHA] A [x][ALPHA] C [=]

Value of delta is displayed. If it is positive, you store its square root in D

[Square root] [ANS] [SHIFT][STO] D ;

Calculate 1/(2*a) and store in variable F

1./(2[x] ALPHA A) [SHIFT][STO] F

To obtain X1

[ALPHA] F [x] ( (-) ALPHA B + ALPHA D ) [=]

To obtain X2

[ALPHA] F [x] ( (-) ALPHA B - ALPHA D ) [=]

Be careful: the (-) is the change sign not the regular minus sign.

Hope it helps.

The calculator does not have a solve program, but you can still use it to solve the quadratic equation with a little effort. If you know the therory skip toward the end.

Let aX^2+bX+C=0

1. First calculate the discriminant usually called Delta and given by

Delta =b^2 -4*a*c store the value in the variable D

If Delta is positive you have two roots X1 and X2 given by

X1=(-b+square root of Delta)/(2*a)

X2=(-b- square root of Delta)/(2*a)

If Delta is equal to 0, X1=X2=-b/(2*a)

If Delta i negative, no real solutions exist

You only solve if Delta is positive or equal to 0.

Putting in the values of a, b, and c

value of a (put you number) [SHIFT][STO] A

value of b (put your value) [SHIFT][STO] B

value of c (put you value) [SHIF][STO] C

[ALPHA] B [X^2] -4[x][ALPHA] A [x][ALPHA] C [=]

Value of delta is displayed. If it is positive, you store its square root in D

[Square root] [ANS] [SHIFT][STO] D ;

Calculate 1/(2*a) and store in variable F

1./(2[x] ALPHA A) [SHIFT][STO] F

To obtain X1

[ALPHA] F [x] ( (-) ALPHA B + ALPHA D ) [=]

To obtain X2

[ALPHA] F [x] ( (-) ALPHA B - ALPHA D ) [=]

Be careful: the (-) is the change sign not the regular minus sign.

Hope it helps.

Sep 24, 2009 | Casio FX-300MS Calculator

Hello,

The question is not clear. What is the value of y?. The calculator cannot help if y is not known.**I will give you a few hints for this algebra problem:**

1. Taking the square root is equivalent to raising to the 1/2 power.

2. Power of a product is equal to the product of the powers. (X*Y)^a=(X^a) times (Y^a)

3. (X^a)^b =X^ (a*b)

Hope it helps.

The question is not clear. What is the value of y?. The calculator cannot help if y is not known.

1. Taking the square root is equivalent to raising to the 1/2 power.

2. Power of a product is equal to the product of the powers. (X*Y)^a=(X^a) times (Y^a)

3. (X^a)^b =X^ (a*b)

Hope it helps.

Mar 31, 2009 | Texas Instruments TI-86 Calculator

The exact square root is 14.1419

The 200= 100 * 2

50 * 2 * 2

25 * 2 * 2 * 2

5 * 5 * 2 * 2 * 2

5 * 2 suare root of 2 so the final answer is

10 Square root of 2

The 200= 100 * 2

50 * 2 * 2

25 * 2 * 2 * 2

5 * 5 * 2 * 2 * 2

5 * 2 suare root of 2 so the final answer is

10 Square root of 2

Nov 13, 2008 | Texas Instruments TI-30XA Calculator

The answer is Square root of 2. ( )

They way it works is :

sec theta at 45 degre is 1 over cosine of theta or

cosine of theta is square root of 2 over 2.

Therefore you have 1 over square root of 2 over 2.

After rationalization and simplification you should have .

They way it works is :

sec theta at 45 degre is 1 over cosine of theta or

cosine of theta is square root of 2 over 2.

Therefore you have 1 over square root of 2 over 2.

After rationalization and simplification you should have .

Feb 20, 2008 | Ingenico I6550 (6550US0041)

Nov 08, 2011 | Mathsoft StudyWorks! Mathematics Deluxe...

Jul 26, 2010 | Mathsoft StudyWorks! Mathematics Deluxe...

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