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Henry is one more than three times as old as cheryl. In 5 years, the sum of their ages will 63 . how old is henry now ?

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He is 38

Posted on Jul 22, 2010

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Sam is 5 years old...his older brother Tom is 3 times as old as Sam...when Sam is 20...how old will Tom be?


Well, Tom is 3 x 5 = 15 yrs now. Sam has 15 yrs to go to 20. Then Tom will be 15 + 5 = 30 yrs.

Or, Tom is 10 yrs older than Sam now, so when Sam is 20........

May 15, 2015 | GPS

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Find the smallest two consecutive even integers such that three times the smaller is at least 19 more than the sum of the two integers


Let x be the smallest number.
Let x + 2 be the other number (consecutive even integer)

Now to translate the rest;)
three times the smaller 3(x)
19 more -19
sum of the two integers - (x) +( x+2)

Pulling it together,
3x -19 = x + x +2
collect like terms
3x - 19 = 2x + 2
Put all the constants on one side by adding 19 to both sides.
3x - 19 +19= 2x + 2 + 19
3x = 2x +21
Subtract 2x from both sides to have all the x's on one side.
3x - 2x = 2x +21 - 2x
x = 21
The other number is 21 + 2, or 23
Check:three times the smaller = 3 x 21 = 63
sum of the two integers = 21 + 23 or 44
is 63 at least 19 more than 44






Feb 19, 2015 | Office Equipment & Supplies

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Adjoa is three years older than her brother Kwame.seven years ago,the sum of their ages 13years.calculate the sum of their present ages.


Let Adjoa's age be x and Kwame's y.
  • Adjoa is 3 years older than Kwame: x=y+3
  • Seven years ago sum of their ages was 13: (x-7)+(y-7)=13
  • Now you substitute first equation into second equation: (y+3-7)+(y-7)=13
  • 2y-4-7=13
  • 2y=24
  • y=24/2=12 years
  • x=y+3=12+3=15 years
  • sum of their present ages is x+y=12+15=27 years

Sep 27, 2011 | Office Equipment & Supplies

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The sum of ages of marian, diana and carlos are 17. Two years from now marian will twice as old as diana. if carlos is half as old as marian four years from now. How ald are they now ? Pls show the...


Let m be Marian's age, d Diana's age and c Carlos age.
  • sum of ages is 17: m+d+c=17
  • two years from now Marian will be twice as old as Diana: m+2=2*(d+2) so m+2=2d+4 so 2d=m-2 or d=(m-2)/2=m/2-1
  • Carlos will be half as old as Marian 4 years from now: c+4=1/2(m+4) or c+4=m/2+2 or c=m/2-2
  • now: m+d+c=m+m/2-1+m/2-2=17
  • 2m=17+3=20
  • m=20/2=10 years
  • d=m/2-1=5-1=4 years
  • c=m/2-2=5-2=3 years
Marian is 10 years old, Diana 4 years old and Carlos is 3 years old.

I hope I helped :)

Sep 18, 2011 | Office Equipment & Supplies

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Jan is twice as old as jake. The sum of their ages is 5 times jake's age less 48. How old are Jan and Jake


Jan is 48 years old and Jake is 24 years old.
(Jan - N, Jake - K N=2K N+K=5K-48 N+K+48=5K N+48=4K N+48=2N 48=N K=N/2=48/2=24)
Thanks, that was fun.

Jul 26, 2011 | Washing Machines

1 Answer

Cindy is 5 years older than Alex and 7 years older than peter sum


Three unknowns with three equasions:
cindy is 5 years older than alex. write it as c = a + 5
cindy is 7 years older than peter. write it as c = p + 7
The sum of their ages is 21. write it as c + a + p = 21
first solve for peters age in terms of alex's age.
c = p + 7 or
(a + 5) = p + 7 or
p = (a + 5) - 7 or
p = a - 2
substitute in and solve the equasion:
(a + 5) + a + (a - 2) = 21 or
3a + 3 = 21 or
3a = 24 or
a = 8

c = a + 5 or
c = 8 + 5 = 13

c = p + 7 or
p = c - 7 or
p = 13 - 7 = 6

cindy is 13, alex is 8 and peter is 6
This is called simultaneous equasions and will always work if you have the same number of unknowns as you have equasions (or relationships).

Sep 20, 2009 | Puzzle Toys

2 Answers

Age problem


X+X+28=4(X+X)
2X+28=4X+4X
28=8X-2X
28=6X
X=4

The twins are 4 yrs. old. The mother is 32.

Do I pass?

Apr 21, 2009 | Mathsoft StudyWorks! Mathematics Deluxe...

1 Answer

Maths & statistic


Standard deviation is the average root mean squared deviation from the average of the numbers.

Familiarize yourself with the wikipedia page on standard deviation: http://en.wikipedia.org/wiki/Standard_deviation

In this case, your question is easy. The standard deviation is 0, so this means the boys ages are all the same.

So they're all 24/3 = 8 years old.

Proof:
8 + 8 + 8 = 24 <-- satisfies the constraint that the boys ages must total to 24.

Get the standard deviation of these numbers;

8+8+8 / 3 = 8 <-- the average value is 8

The deviation of each boy's age from the average is:
boy 1
--------
8 years old, which deviates from 8 by 0
boy 2
--------
8 years old, which deviates from 8 by 0
boy 3
--------
8 years old, which deviates from 8 by 0

So the deviations are 0, 0 and 0.

To get the standard deviation, you sum the squares of the deviations of each boy, get the average, and square root. So:

0² + 0² + 0² = 0
Average is 0 / 3 = 0
Square root of 0 = 0

So the standard deviation is 0. Which shouldn't be much of a surprise to you. We just had to actually DO the work to show that it was in fact 0.

Feb 08, 2008 | Audio Players & Recorders

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