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Posted on Jan 02, 2017

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Well, Tom is 3 x 5 = 15 yrs now. Sam has 15 yrs to go to 20. Then Tom will be 15 + 5 = 30 yrs.

Or, Tom is 10 yrs older than Sam now, so when Sam is 20........

Or, Tom is 10 yrs older than Sam now, so when Sam is 20........

May 15, 2015 | GPS

Let x be the smallest number.

Let x + 2 be the other number (consecutive even integer)

Now to translate the rest;)

three times the smaller 3(x)

19 more -19

sum of the two integers - (x) +( x+2)

Pulling it together,

3x -19 = x + x +2

collect like terms

3x - 19 = 2x + 2

Put all the constants on one side by adding 19 to both sides.

3x - 19 +19= 2x + 2 + 19

3x = 2x +21

Subtract 2x from both sides to have all the x's on one side.

3x - 2x = 2x +21 - 2x

x = 21

The other number is 21 + 2, or 23

Check:three times the smaller = 3 x 21 = 63

sum of the two integers = 21 + 23 or 44

is 63 at least 19 more than 44

Let x + 2 be the other number (consecutive even integer)

Now to translate the rest;)

three times the smaller 3(x)

19 more -19

sum of the two integers - (x) +( x+2)

Pulling it together,

3x -19 = x + x +2

collect like terms

3x - 19 = 2x + 2

Put all the constants on one side by adding 19 to both sides.

3x - 19 +19= 2x + 2 + 19

3x = 2x +21

Subtract 2x from both sides to have all the x's on one side.

3x - 2x = 2x +21 - 2x

x = 21

The other number is 21 + 2, or 23

Check:three times the smaller = 3 x 21 = 63

sum of the two integers = 21 + 23 or 44

is 63 at least 19 more than 44

Feb 19, 2015 | Office Equipment & Supplies

Let Adjoa's age be x and Kwame's y.

- Adjoa is 3 years older than Kwame: x=y+3
- Seven years ago sum of their ages was 13: (x-7)+(y-7)=13
- Now you substitute first equation into second equation: (y+3-7)+(y-7)=13
- 2y-4-7=13
- 2y=24
- y=24/2=12 years
- x=y+3=12+3=15 years
- sum of their present ages is x+y=12+15=27 years

Sep 27, 2011 | Office Equipment & Supplies

Let m be Marian's age, d Diana's age and c Carlos age.

I hope I helped :)

- sum of ages is 17: m+d+c=17
- two years from now Marian will be twice as old as Diana: m+2=2*(d+2) so m+2=2d+4 so 2d=m-2 or d=(m-2)/2=m/2-1
- Carlos will be half as old as Marian 4 years from now: c+4=1/2(m+4) or c+4=m/2+2 or c=m/2-2
- now: m+d+c=m+m/2-1+m/2-2=17
- 2m=17+3=20
- m=20/2=10 years
- d=m/2-1=5-1=4 years
- c=m/2-2=5-2=3 years

I hope I helped :)

Sep 18, 2011 | Office Equipment & Supplies

Jan is 48 years old and Jake is 24 years old.

(Jan - N, Jake - K N=2K N+K=5K-48 N+K+48=5K N+48=4K N+48=2N 48=N K=N/2=48/2=24)

Thanks, that was fun.

(Jan - N, Jake - K N=2K N+K=5K-48 N+K+48=5K N+48=4K N+48=2N 48=N K=N/2=48/2=24)

Thanks, that was fun.

Jul 26, 2011 | Washing Machines

Three unknowns with three equasions:

cindy is 5 years older than alex. write it as c = a + 5

cindy is 7 years older than peter. write it as c = p + 7

The sum of their ages is 21. write it as c + a + p = 21

first solve for peters age in terms of alex's age.

c = p + 7 or

(a + 5) = p + 7 or

p = (a + 5) - 7 or

p = a - 2

substitute in and solve the equasion:

(a + 5) + a + (a - 2) = 21 or

3a + 3 = 21 or

3a = 24 or

a = 8

c = a + 5 or

c = 8 + 5 = 13

c = p + 7 or

p = c - 7 or

p = 13 - 7 = 6

cindy is 13, alex is 8 and peter is 6

This is called simultaneous equasions and will always work if you have the same number of unknowns as you have equasions (or relationships).

cindy is 5 years older than alex. write it as c = a + 5

cindy is 7 years older than peter. write it as c = p + 7

The sum of their ages is 21. write it as c + a + p = 21

first solve for peters age in terms of alex's age.

c = p + 7 or

(a + 5) = p + 7 or

p = (a + 5) - 7 or

p = a - 2

substitute in and solve the equasion:

(a + 5) + a + (a - 2) = 21 or

3a + 3 = 21 or

3a = 24 or

a = 8

c = a + 5 or

c = 8 + 5 = 13

c = p + 7 or

p = c - 7 or

p = 13 - 7 = 6

cindy is 13, alex is 8 and peter is 6

This is called simultaneous equasions and will always work if you have the same number of unknowns as you have equasions (or relationships).

Sep 20, 2009 | Puzzle Toys

X+X+28=4(X+X)

2X+28=4X+4X

28=8X-2X

28=6X

X=4

The twins are 4 yrs. old. The mother is 32.

Do I pass?

2X+28=4X+4X

28=8X-2X

28=6X

X=4

The twins are 4 yrs. old. The mother is 32.

Do I pass?

Apr 21, 2009 | Mathsoft StudyWorks! Mathematics Deluxe...

Standard deviation is the average root mean squared deviation from the average of the numbers.

Familiarize yourself with the wikipedia page on standard deviation: http://en.wikipedia.org/wiki/Standard_deviation

In this case, your question is easy. The standard deviation is 0, so this means the boys ages are all the same.

So they're all 24/3 = 8 years old.

Proof:

8 + 8 + 8 = 24 <-- satisfies the constraint that the boys ages must total to 24.

Get the standard deviation of these numbers;

8+8+8 / 3 = 8 <-- the average value is 8

The deviation of each boy's age from the average is:

boy 1

--------

8 years old, which deviates from 8 by 0

boy 2

--------

8 years old, which deviates from 8 by 0

boy 3

--------

8 years old, which deviates from 8 by 0

So the deviations are 0, 0 and 0.

To get the standard deviation, you sum the squares of the deviations of each boy, get the average, and square root. So:

0² + 0² + 0² = 0

Average is 0 / 3 = 0

Square root of 0 = 0

So the standard deviation is 0. Which shouldn't be much of a surprise to you. We just had to actually DO the work to show that it was in fact 0.

Familiarize yourself with the wikipedia page on standard deviation: http://en.wikipedia.org/wiki/Standard_deviation

In this case, your question is easy. The standard deviation is 0, so this means the boys ages are all the same.

So they're all 24/3 = 8 years old.

Proof:

8 + 8 + 8 = 24 <-- satisfies the constraint that the boys ages must total to 24.

Get the standard deviation of these numbers;

8+8+8 / 3 = 8 <-- the average value is 8

The deviation of each boy's age from the average is:

boy 1

--------

8 years old, which deviates from 8 by 0

boy 2

--------

8 years old, which deviates from 8 by 0

boy 3

--------

8 years old, which deviates from 8 by 0

So the deviations are 0, 0 and 0.

To get the standard deviation, you sum the squares of the deviations of each boy, get the average, and square root. So:

0² + 0² + 0² = 0

Average is 0 / 3 = 0

Square root of 0 = 0

So the standard deviation is 0. Which shouldn't be much of a surprise to you. We just had to actually DO the work to show that it was in fact 0.

Feb 08, 2008 | Audio Players & Recorders

Aug 11, 2018 | Apple Computers & Internet

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