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# 1 divided by infinite=0 - Brother Computers & Internet

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Yes. but the correct answer is undifined

Posted on Jul 17, 2010

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It's a vertical line so the slope is infinite.

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There are an infinite number of numbers that qualify. The smallest such positive number is 125. The next such number is 251.

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### How do i factor numbers on a ti-30xs calculator

This calculator does not have a key that you can use to find the prime factor of an integer.
You can however use the calculator to find the factors
1. If number is even divide it by 2
Keep dividing by 2, while keeping track of how many times you divided by 2.
If you divided 5 times by 2 before getting an odd number, then your first factor is 2^5
2. Now try dividing by 3, keep track of the number of times you divided by 3 before you could not divide by 3 any more. If you divided 0 times by 3, your second factor is 3^0, or 1 and 3 is not a factor.
If you divided 4 times by 3, your second factor is 3^4
3. Divide by 5, until you can't any more. Keep track of the number of times you divided by 5.
4. Divide by all other prime numbers 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, etc. For each prime number, keep track of how many times you divided by it, until you could not any more.

Example: 23100
Division by 2
23100/2=11550 ---------> 1 division by 2
11550/2=5775 ----------> 2 divisions by 2
Note that 5775 is not divisible by 2. No more divisions by 2.
First factor is 2^2

Division by 3:
5775/3=1925 ----------> 1 division by 3
1925/3=641. 66667 Not an integer. No more divisions by 3.
2nd factor is 3^1

Division by 5 (number ends in 5)
1925/5 =385 -------> 1 division by 5
385/5=77 ----------> 2 divisions by 5 and no more (quotient does not end in 0 or 5)
3rd factor is 5^2

Division by 7
77/7=11 --------> 1 division by 7, and no more
4th factor is 7^1=7

Division by 11
11/11=1
5th factor is 11^1=11

Assembling the factors 2^2, 3^1, 5^2, 7, 11
Prime factorization of 23100 is
23100=(2^2)(3)(5^2)(7)11

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There would be 0 remainders because 17 divided by 0 yields "does not exist"

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### 20 divided by 28

20 divided by 28 equals:

5 / 7

or

0.714285714285714285...

Notice the infinitely repeating sequence (714285).

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### 100.00 divided by 0.04

To do this calculation on a Canon P23-DHV Calculator press [1] [0] [0] [(divide)] [.] [0] [4] [=] this should give you
2,500.

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### How do i solve negative 15x to the power of 4 divided by 3x

-15x^4 / 3x = -5x³ for x 0.

You should be able to figure this out without having to resort to a calculator. Note the "for x 0"... the two functions are identical everywhere, except the -15x^4 / 3x version is undefined for x = 0 (3 times 0 is 0 and you cannot divide by 0). The function has a "hole" at this point. -5x³ does not suffer from this defect, for x=0 it simply evaluates to 0, so you have to mention this fact to make it proper.

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### One divided by zero equal to infinity,why

This is from wikipedia:

When division is explained at the elementary arithmetic level, it is often considered as a description of dividing a set of objects into equal parts. As an example, consider having ten apples, and these apples are to be distributed equally to five people at a table. Each person would receive = 2 apples. Similarly, if there are 10 apples, and only one person at the table, that person would receive = 10 apples.

So for dividing by zero - what is the number of apples that each person receives when 10 apples are evenly distributed amongst 0 people? Certain words can be pinpointed in the question to highlight the problem. The problem with this question is the "when". There is no way to distribute 10 apples amongst 0 people. In mathematical jargon, a set of 10 items cannot be partitioned into 0 subsets. So , at least in elementary arithmetic, is said to be meaningless, or undefined.

Similar problems occur if we have 0 apples and 0 people, but this time the problem is in the phrase "the number". A partition is possible (of a set with 0 elements into 0 parts), but since the partition has 0 parts, vacuously every set in our partition has a given number of elements, be it 0, 2, 5, or 1000. If there are, say, 5 apples and 2 people, the problem is in "evenly distribute". In any integer partition of a 5-set into 2 parts, one of the parts of the partition will have more elements than the other.

In all of the above three cases, , and , one is asked to consider an impossible situation before deciding what the answer will be, and that is why the operations are undefined in these cases.

To understand division by zero, we must check it with multiplication: multiply the quotient by the divisor to get the original number. However, no number multiplied by zero will produce a product other than zero. To satisfy division by zero, the quotient must be bigger than all other numbers, i.e., infinity. This connection of division by zero to infinity takes us beyond elementary arithmetic (see below).

A recurring theme even at this elementary stage is that for every undefined arithmetic operation, there is a corresponding question that is not well-defined. "How many apples will each person receive under a fair distribution of ten apples amongst three people?" is a question that is not well-defined because there can be no fair distribution of ten apples amongst three people.

There is another way, however, to explain the division: if we want to find out how many people, who are satisfied with half an apple, can we satisfy by dividing up one apple, we divide 1 by 0.5. The answer is 2. Similarly, if we want to know how many people, who are satisfied with nothing, can we satisfy with 1 apple, we divide 1 by 0. The answer is infinite; we can satisfy infinite people, that are satisfied with nothing, with 1 apple.

Clearly, we cannot extend the operation of division based on the elementary combinatorial considerations that first define division, but must construct new number systems.

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