# Form the greatest 5 digit number that rounds to 15000 using only odd numbers from 1 - 9 and without repeating a digit

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Round to how many significant figures? And what does this have to do with Kodak digital cameras?

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Posted on Jul 08, 2010

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Posted on Jan 02, 2017

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## Related Questions:

### -54k^2+3k

-54k^2+3k I assume that you want to factor this completely.
I do it one component at a time.
What is the biggest common factor of -54 and 3. I use a trick of adding the digits of the number. If 3 and/or 9 go into that number evenly, than 3 and/or 9, respectively go into the original number. In this case, 5+4 = 9 and since 3 goes into 9 evenly, 3 goes into 54 evenly. Since the factors of 3 are 3 and 1, this must be the greatest common factor of this component.
Onto the next component, what is the greatest common factor of k^2 and k. The answer is k, because k^2 doesn't go evenly into k.
Combining the two, the greatest common factor is 3k.

Next we have to divide 3k into each term.
3k(-18k+1) or -3k(18k-1)

Good luck,

Paul

Mar 29, 2017 | Homework

### How many 3-digit number combinations can you make with using odd numbers

If the numbers repeat twice, there are five combinations (111, 333, 555, 777, and 999). If the numbers only repeat once, there are sixty combinations (113, 131, 311, 115, 151, 511, etc).

Mar 18, 2014 | Computers & Internet

### What are rational numbers

Use the words: decimal part, not decimal fractin
Any number whose decimal part is periodic (has a recurring pattern that repeats indefinitely) is equivalent to a rational number, IS a rational number
0.345 345 345 ... =345/999=115/333
In the following screen captures, discard the last digit if it does not belong to a period. It is the effect of rounding up of the calculator

Period is 345

Period is 1

Period is 09

Period is 79

In general, if you have a decimal part of the form 0.d_1 d_2 d_3....d_n d_1 d_2 d_3 ...d_n ... where d_1 is the first digit of the period, d_2 is the 2nd digit of the period, ..., d_n is the n-th digit (and the last one) of the period, then the fraction representation of
0.d_1d_2...d_n d_1d_2... d_n ...=(d_1d_2...d_n)/(99...9) where the number of 9's in the denominator is equal to the number of digits in the period.
Once the fraction is found, one should reduce it to its simplest form.

Mar 02, 2014 | Office Equipment & Supplies

### How to find G.C.F. on a TI-30xIIs calculator?

I don't think there's specific key for this but you can do it this way:

1. Divide those 2 numbers for which you want to find gcf
2. If you get result as decimal number press keys [2nd][PRB] to display it as fraction
3. Also if fraction you get is in form a b/c (ex. 1 2/3) you have to convert it to form d/c (for 1 2/3 that would be 5/3)
4. Greatest common factor is then 1st number divided by numerator (or 2nd number divided by denominator)
For example:
• You want to find greatest common factor of 30 and 18.
• You divide them: you should get 5/3 (after converting result to fraction of form d/c, as described in steps 2 and 3).
• This means that 30/18=5/3=5x/3x (x is gcf here).
• Now you know that x=30/5=18/3=6 so greatest common factor is 6.

I hope this helps :)

Sep 10, 2011 | Texas Instruments TI-30 XIIS Calculator

### Using all digits 5, 4 and 8, how many different numbers can you form if no digit is repeated? What if digits may be repeated?

This question refers to combination and permutation. In order to calculate this, you need to think of it logically.

To calculate without repeats, it's fairly simple. In the first digit x, you have three options (5,4,8), however in y there are only two options (the two which were not in x), and z only has one option (the one that was left over). When you calculate them out you do it by multiplication, IE 3*2*1=6. This is also called a factorial, and is expressed as 3!

To express with repeats, the formula is a little different. It depends on what size number you are trying to make, and I'm not sure that you gave that information. If you are only making a 3 digit number, the solution would be as follows. x has 3 options again, but since there can be repeats both y and z have 3 options as well. When calculated, it comes out to 3*3*3-27

Jul 19, 2011 | Computers & Internet

### I am a number rounding me to the nearest thousand makes me a 1000.All my digits are even their sum is 12 they are in order from greatest to least and no digit is repeated what number am I

642.
They are all even numbers and they are all in order from greatest to lease. Their sum must add up to 12 also. so 6 +4 +2 = 12.
If you round it to the nearest 1000 you get 642.
Take each thing they are saying as 1 of your rules to get the number. And use that to eliminate numbers for example. 1 3 5 7 are all eliminated. then use numbers to get to 12 that must be even. Finally make sure they are from greatest to least.

Sep 30, 2010 | Fast Rabbit Software Master Math Word...

### I am a number rounding me to the nearest thousand makes me a 1000.All my digits are even their sum is 12 they are in order from greatest to least and no digit is repeated what number am I ?

642.
They are all even numbers and they are all in order from greatest to lease. Their sum must add up to 12 also. so 6 +4 +2 = 12.
If you round it to the nearest 1000 you get 642.
Take each thing they are saying as 1 of your rules to get the number. And use that to eliminate numbers for example. 1 3 5 7 are all eliminated. then use numbers to get to 12 that must be even. Finally make sure they are from greatest to least.

Sep 29, 2010 | Fast Rabbit Software Master Math Word...

### How to find the sum of odd numbers

for(i=1;i<n;i=i+2)
sum=sum+i;

n=no of terms,sum=0

Aug 29, 2010 | Computers & Internet

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