Question about Calculators

$15,000 at 3% and $6,000 at 7%.

If this is homework, be sure to show your work.

If this is homework, be sure to show your work.

Sep 06, 2014 | Calculators

With simple interest, there is no compounding. To earn 2200.50 interest in six years, you need to earn 2200.50/6 = 366.75 each year. In order to earn 366.75 at 10.5%, you need a principal of 366.75/10.5% = 3492.86.

If the interest is compounded annually then you only need to invest 2682.13.

If the interest is compounded annually then you only need to invest 2682.13.

May 03, 2014 | Casio FX-115ES Scientific Calculator

2/5 of the total or $600.

If this is homework, be sure to show your work.

If this is homework, be sure to show your work.

Apr 04, 2014 | Calculators

To get $500,00 four years from now, how much must you invest today, assuming an annual interest rate of 4%?

A=P(1+i)^n, where A is the amount, P is the principal or initial investment, i is the interest rate per period, and n is the number of periods.

500,000 = P (1+0.04)^4

500,000/(1.04^4) = P

P = $427,402.10

Good luck,

Paul

A=P(1+i)^n, where A is the amount, P is the principal or initial investment, i is the interest rate per period, and n is the number of periods.

500,000 = P (1+0.04)^4

500,000/(1.04^4) = P

P = $427,402.10

Good luck,

Paul

Feb 17, 2014 | Sharp EL-738 Scientific Calculator

Invest R10000 in a bank investing at 14% compounded twice a year.

A = P(1+i)^n, where A is the amount, P is the principal or initial investment, i is the interest rate per period, and n is the number of periods.

If the annual rate is 14%, the semi-annual rate is 7%. One year is now composed of 2 6-month periods.

So after one year, we have A = 10 000 (1.07)^2 or 11,449.

Good luck,

Paul

A = P(1+i)^n, where A is the amount, P is the principal or initial investment, i is the interest rate per period, and n is the number of periods.

If the annual rate is 14%, the semi-annual rate is 7%. One year is now composed of 2 6-month periods.

So after one year, we have A = 10 000 (1.07)^2 or 11,449.

Good luck,

Paul

Nov 19, 2013 | Sharp EL-738 Scientific Calculator

In case of difficulty TI 30Xiis :

Jun 23, 2013 | Texas Instruments TI 30XIIS Scientific...

Hi,

Jane starts with 1200$ at the beginning of the first year, and at the end of the fourth year she has 1200$+300$=1500$

Use x for her annual interest rate, that means at the end of the first year she will have 1200$*[(100+x)/100]. At the end of the second year her first-year money earns at the same rate, so she will have 1200$*[(100+x)/100]*[(100+x)/100]=1200$*[(100+x)/100]^2 at the end of the second year.

At the end of the third year she will have 1200$*[(100+x)/100]^2 *[(100+x)/100]=1200$*[(100+x)/100]^3

At the end of the fourth year she will have

1200$*[(100+x)/100]^3 *[(100+x)/100]=1200$*[(100+x)/100]^4 which is equals to 1500$

1200$*[(100+x)/100]^4=1500$ divide both sides by 1200$

[(100+x)/100]^4=1,25 take the fourth root of both sides

(100+x)/100=1,05737 both sides*100

100+x = 105,737 both sides -100

x=5,737

So Jane's annaual interest rate was 5,737%.

Hope it helps you.

Jane starts with 1200$ at the beginning of the first year, and at the end of the fourth year she has 1200$+300$=1500$

Use x for her annual interest rate, that means at the end of the first year she will have 1200$*[(100+x)/100]. At the end of the second year her first-year money earns at the same rate, so she will have 1200$*[(100+x)/100]*[(100+x)/100]=1200$*[(100+x)/100]^2 at the end of the second year.

At the end of the third year she will have 1200$*[(100+x)/100]^2 *[(100+x)/100]=1200$*[(100+x)/100]^3

At the end of the fourth year she will have

1200$*[(100+x)/100]^3 *[(100+x)/100]=1200$*[(100+x)/100]^4 which is equals to 1500$

1200$*[(100+x)/100]^4=1500$ divide both sides by 1200$

[(100+x)/100]^4=1,25 take the fourth root of both sides

(100+x)/100=1,05737 both sides*100

100+x = 105,737 both sides -100

x=5,737

So Jane's annaual interest rate was 5,737%.

Hope it helps you.

Mar 10, 2011 | Sharp EL-738 Scientific Calculator

2nd [CLR TVM] (clear TVM registers)

2 4 0 0 +/- PV ($2400 initial investment, negative because you're paying it out)

6 I/Y (6% annual interest)

1 N (one year)

CPT FV (compute future value, see 2544.00, the value after one year)

5 N (five years)

CPT FV (see 3211.74, the value after five years)

1 0 N (ten years)

CPT FV (see 4298.03, the value after ten years)

2 4 0 0 +/- PV ($2400 initial investment, negative because you're paying it out)

6 I/Y (6% annual interest)

1 N (one year)

CPT FV (compute future value, see 2544.00, the value after one year)

5 N (five years)

CPT FV (see 3211.74, the value after five years)

1 0 N (ten years)

CPT FV (see 4298.03, the value after ten years)

Feb 19, 2011 | Texas Instruments BA II PLUS Financial...

4 5 0 0 0 +/- PV (investment amount, negative because you're paying it out)

2 5 0 0 0 0 FV (desired amount, positive because you're receiving it)

2 0 SHIFT xP/YR (20 years)

I/YR (calculate annual interest rate)

2 5 0 0 0 0 FV (desired amount, positive because you're receiving it)

2 0 SHIFT xP/YR (20 years)

I/YR (calculate annual interest rate)

Jan 23, 2011 | HP 10bII Calculator

after 3 years u wil get rs 43692..

Aug 29, 2008 | Calculators

Dec 10, 2016 | Calculators

Dec 07, 2016 | Calculators

80 people viewed this question

Usually answered in minutes!

4590*8%*120

Please describe the specifics of your problem below. We'll add

your post as a comment to aashish jai's simple interst problem, and notify you when a new solution is

×