Question about Microsoft Windows XP Professional

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Are you joking.........

this is a pc sopport website.

although i will solve this for you

let, age=x

1/(x-3)+1/(x+5)=1\3

solving you will get non integral soln.

hence no soln.

Posted on Jun 03, 2010

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Posted on Jan 02, 2017

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Dec 02, 2016 | Cars & Trucks

Let Adjoa's age be x and Kwame's y.

- Adjoa is 3 years older than Kwame: x=y+3
- Seven years ago sum of their ages was 13: (x-7)+(y-7)=13
- Now you substitute first equation into second equation: (y+3-7)+(y-7)=13
- 2y-4-7=13
- 2y=24
- y=24/2=12 years
- x=y+3=12+3=15 years
- sum of their present ages is x+y=12+15=27 years

Sep 27, 2011 | Office Equipment & Supplies

Let m be Marian's age, d Diana's age and c Carlos age.

I hope I helped :)

- sum of ages is 17: m+d+c=17
- two years from now Marian will be twice as old as Diana: m+2=2*(d+2) so m+2=2d+4 so 2d=m-2 or d=(m-2)/2=m/2-1
- Carlos will be half as old as Marian 4 years from now: c+4=1/2(m+4) or c+4=m/2+2 or c=m/2-2
- now: m+d+c=m+m/2-1+m/2-2=17
- 2m=17+3=20
- m=20/2=10 years
- d=m/2-1=5-1=4 years
- c=m/2-2=5-2=3 years

I hope I helped :)

Sep 18, 2011 | Office Equipment & Supplies

Jan is 48 years old and Jake is 24 years old.

(Jan - N, Jake - K N=2K N+K=5K-48 N+K+48=5K N+48=4K N+48=2N 48=N K=N/2=48/2=24)

Thanks, that was fun.

(Jan - N, Jake - K N=2K N+K=5K-48 N+K+48=5K N+48=4K N+48=2N 48=N K=N/2=48/2=24)

Thanks, that was fun.

Jul 26, 2011 | Washing Machines

The average is 20, it means the total is 60. The sum of ratio is 15 (3+5+7)

Therefore the age of a girl is calculated by multiplying the respective ration with total and dividing by sum of ratio

Age of Eldest girl = 7 x 60 /15 = 28

Hope it helps! Good Luck!

CreativeTECH

Therefore the age of a girl is calculated by multiplying the respective ration with total and dividing by sum of ratio

Age of Eldest girl = 7 x 60 /15 = 28

Hope it helps! Good Luck!

CreativeTECH

Feb 15, 2011 | Computers & Internet

Hi,

Let the present age of the Rodney = X

present Age of the Jasmin = Y

As per the Situation,

Y-9 = 2 (X - 9)

Y-9 = 2X - 18

Y = 2X - 18 +9

Y = 2X-9

Second,

X + Y = 45

Y = 45 - X

Taking Both the situations,

2X - 9 = 45 - X

3X = 54

X = 54/3 = 18

Y = 45 - 18 = 27

Hence,

Age of Jasmin = 27

Let me know, if needed further assistance.

Hope i helped you.

Thanks for using ' Fixya ' and have a nice day!!

Let the present age of the Rodney = X

present Age of the Jasmin = Y

As per the Situation,

Y-9 = 2 (X - 9)

Y-9 = 2X - 18

Y = 2X - 18 +9

Y = 2X-9

Second,

X + Y = 45

Y = 45 - X

Taking Both the situations,

2X - 9 = 45 - X

3X = 54

X = 54/3 = 18

Y = 45 - 18 = 27

Hence,

Age of Jasmin = 27

Let me know, if needed further assistance.

Hope i helped you.

Thanks for using ' Fixya ' and have a nice day!!

Mar 17, 2010 | Disney Watches

Three unknowns with three equasions:

cindy is 5 years older than alex. write it as c = a + 5

cindy is 7 years older than peter. write it as c = p + 7

The sum of their ages is 21. write it as c + a + p = 21

first solve for peters age in terms of alex's age.

c = p + 7 or

(a + 5) = p + 7 or

p = (a + 5) - 7 or

p = a - 2

substitute in and solve the equasion:

(a + 5) + a + (a - 2) = 21 or

3a + 3 = 21 or

3a = 24 or

a = 8

c = a + 5 or

c = 8 + 5 = 13

c = p + 7 or

p = c - 7 or

p = 13 - 7 = 6

cindy is 13, alex is 8 and peter is 6

This is called simultaneous equasions and will always work if you have the same number of unknowns as you have equasions (or relationships).

cindy is 5 years older than alex. write it as c = a + 5

cindy is 7 years older than peter. write it as c = p + 7

The sum of their ages is 21. write it as c + a + p = 21

first solve for peters age in terms of alex's age.

c = p + 7 or

(a + 5) = p + 7 or

p = (a + 5) - 7 or

p = a - 2

substitute in and solve the equasion:

(a + 5) + a + (a - 2) = 21 or

3a + 3 = 21 or

3a = 24 or

a = 8

c = a + 5 or

c = 8 + 5 = 13

c = p + 7 or

p = c - 7 or

p = 13 - 7 = 6

cindy is 13, alex is 8 and peter is 6

This is called simultaneous equasions and will always work if you have the same number of unknowns as you have equasions (or relationships).

Sep 20, 2009 | Puzzle Toys

X+X+28=4(X+X)

2X+28=4X+4X

28=8X-2X

28=6X

X=4

The twins are 4 yrs. old. The mother is 32.

Do I pass?

2X+28=4X+4X

28=8X-2X

28=6X

X=4

The twins are 4 yrs. old. The mother is 32.

Do I pass?

Apr 21, 2009 | Mathsoft StudyWorks! Mathematics Deluxe...

Paul 3 years younger to his friend peter. In seven years, the product of their ages would be 5 more than the product of their ages 5 years ago. How old are they now?

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