Question about Vivendi Excel@ Mathematics Study Skills (71101) for PC, Mac

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Posted on Mar 03, 2011

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Let X be the time taken when train is moving in its normal speed.

Y be the normal speed of the train.

Speed = distance/time

that is X = 400 / Y

or Y = 400 / X --------- (1)

When speed is decreased by 5 km/hr time increases by 4 hour

that is X + 4 = 400 / Y -5

= X + 4 = 400 X / 400 - 5X ( substitute Y = 400 /X we get this equation)

on solving we get 5X^2 + 20x - 1600 = 0

we get two solutions X = 16 and -20

-20 is neglected (time cannot be negative)

substitute X in equation (1)

Y = 400 / 16 = 25 km/hr

So normal speed of train is 25 km/hr.

Posted on Jun 02, 2010

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Posted on Jan 02, 2017

Fixed distance is D

D=(5h*80 km/h)=T*50 km/h

T=(400 km)/(50 km/h)=8 hours

D=(5h*80 km/h)=T*50 km/h

T=(400 km)/(50 km/h)=8 hours

Jul 02, 2014 | Casio FX-115ES Scientific Calculator

How long it takes to drive any distance depends on your average speed. Whatever is your average speed, divide that into the distance you have to travel. For instance, if your speed is 100 kilometers per hour and you need to go 400 kilometers, it will take you (400 km/100 kmph=) four hours. Always be sure to use the same units of measurement, English or metric, in your arithmetic.

May 12, 2014 | Google Finance

Journey time 2hrs = 2 x 60 mins = 2 x 60 x 60 seconds

Distance 180 km = 180,000 m

Average speed = 3 x 6 x 10000 / 2 x 6 x 6 x 100 m/s

= 6 x 6 x 100 x 100 / [2 x (2 x 6 x6 x100)] m/s

= 100 / 4 m/s

= 25 m/s

5.May.2014

Distance 180 km = 180,000 m

Average speed = 3 x 6 x 10000 / 2 x 6 x 6 x 100 m/s

= 6 x 6 x 100 x 100 / [2 x (2 x 6 x6 x100)] m/s

= 100 / 4 m/s

= 25 m/s

5.May.2014

May 05, 2014 | Office Equipment & Supplies

The speed of the stream is 5 km/hr.

Aug 24, 2013 | Office Equipment & Supplies

The easiest way to reach
Ranthambore is to take a train to Sawai Madhopur. This town is well connected
with trains to/from Jaipur, Bombay and Delhi.

Nearby Airports - Jaipur and Kota

Distance by rail:

Delhi - 362 km, Agra - 227 km, Bombay 1027 km, Kota - 108 km, Jaipur - 132 km

Distance by road:

Delhi - 480 km (via Dausa), Jaipur - 180 km (via Tonk)

Nearby Airports - Jaipur and Kota

Distance by rail:

Delhi - 362 km, Agra - 227 km, Bombay 1027 km, Kota - 108 km, Jaipur - 132 km

Distance by road:

Delhi - 480 km (via Dausa), Jaipur - 180 km (via Tonk)

Jun 18, 2013 | Wildlife Research Health & Beauty

Somebody went to the APPS menu, scrolled down or up to reach an applications called INEQUALZ. When executed it remains in memory until it is kicked out. Do the same operation as described above and press INEQAULZ. In the subsequent screen select the option that says Uninstall or quit Inequalz.

Aug 08, 2011 | Texas Instruments TI-84 Plus Calculator

2924 Kms / 43 Hrs = 68 Km/hr

Jul 03, 2011 | 2011 Audi A5

Sep 19, 2010 | Vivendi Excel@ Mathematics Study Skills...

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